I mean, something like this, but with Windows thread calls.
(I can't run any cegcc code at the moment).
Just wondering where would the stack addresses be for new
threads.
Thanks!
Pawel.
[pv230...@druid]~/cprog$ cat stt.c
#include <stdio.h>
#include <pthread.h>
static void prt_stk() {
int i;
fprintf(stdout, "my stack is near %p\n", &i);
}
static void* t_start(void * n) {
prt_stk();
return 0;
}
int main(int argc, char ** argv) {
pthread_t t1;
pthread_t t2;
void * n;
prt_stk();
pthread_create(&t1, 0, t_start, 0);
pthread_create(&t2, 0, t_start, 0);
pthread_join(t1, &n);
pthread_join(t2, &n);
return 0;
}
On Tue, Jun 9, 2009 at 3:06 AM, Danny Backx<[email protected]> wrote:
> You probably mean something like the attached test. What do you want to
> know about it ? I can run it on x86 and on ARM.
>
> Danny
>
> On Mon, 2009-06-08 at 18:16 +0900, Pawel Veselov wrote:
>> Should the prologue code be rewritten to have
>> a thread created before main() is called?
>>
>> Also, it'd be interesting to see where are the
>> new thread stacks are created, I've looked
>> at how other OSes do that, and they just
>> simply create a new segment. Since m$ seem
>> to not give you stack segment for the stack
>> completely, it should allocate thread stacks
>> somewhere in that stack segment.
>>
>>
>> On Mon, Jun 8, 2009 at 6:06 PM, Johnny Willemsen <[email protected]>
>> wrote:
>> > Hi,
>> >
>> >> gcc code may user more of the stack than whatever code that msvc
>> >> produces, thus
>> >> dipping into the red zone more often. So far, I don't see how the 64k
>> >> limit of the
>> >> stack on the main thread can be avoided at all..
>> >
>> > The only option I see (which also Danny proposed) is to create a worker
>> > thread, use that as main thread, then we can control the stack size.
>> >
>> > I will rewrite a few tests at our side to get some objects from the heap
>> > instead of from the stack.
>> >
>> > Johnny
>> >
>> >
>>
> --
> Danny Backx ; danny.backx - at - scarlet.be ; http://danny.backx.info
>
--
With best of best regards
Pawel S. Veselov
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