>> Think of it like the compiler generates the ivars from the property
>> definitions. So the ivar would be indeed explicit ivars - just not
>> defined as such in the classic way.
>
> Doesn't matter. The subclass still needs to know the size of its superclass 
> so that it generate the proper ivar offsets. If the ivar declarations are not 
> visible to the compiler, it cannot know this information.

But there is the property declaration where it can derive that information from.

FWIW I check on the llvm IRC channel and the response was "I wouldn't
be surprised if there are annoying edge cases, but offhand I don't see
any reason it couldn't be done."
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