Re: Concatenate 2 ranges

[Vladimir Panteleev via Digitalmars-d-learn]

On Friday, 11 November 2016 at 13:30:17 UTC, RazvanN wrote:
I know that I can use the .array property, but I think that 
this iterates through all of my elements. Using 
assumeSorted(chain(r1, r2).array) will return a SortedRange, 
but I am not sure what the complexity for this operation is.

.array allocates, so it's going to be O(n), but the allocation 
will probably be more expensive.

Is there a way to concatenate 2 ranges (SortedRange in my case) 
in O(1) time?

assumeSorted(chain(a, b)) ?

This works for me:

auto r = assumeSorted(chain([1, 2, 3].sort(), [1, 2, 3].sort()));