As I understand it, in the case of partial overlap you just divide the overlapping portion of B by A, so the direct division here would have the same effect. I don't understand why is that division assuming A = 2B.
In any case, your function is heavier on the ifs, but mine has to do more with each option, so I'm not sure which would perform better. And I think yours is more readable, although less concise. - Paulo 2010/8/6 Alexandre González <agonzale...@gmail.com> > Mmmmm the third case coul be this, for example: > > |-------A-------------| |--------------A------------| > ----------------------------- -------------------------------------- > > |B| |-----B----| > > If I directly apply (his_diff/my_diff) I think that I'm assuming that A = > 2B and it isn't the case... I need to get my range and her range and deleter > the union between them with a substraction. > > range(A) - range(B) 17000s - 13000s > ---------------------------- for example: --------------------------- = > 0.2352 = 23% > range(A) 17000s > > What do you think about? Perhaps I'm mading mistakes and can't understand > your reply. Anyway, thanks for reply :) > > Bye! > Álex González > > > On Fri, Aug 6, 2010 at 02:09, Paulo Almeida > <igcbioinformat...@gmail.com>wrote: > >> In the third case, I didn't understand why you didn't divide (his_to - >> his_from) / (my_to - my_from). Bearing that in mind, this made sense in my >> head, but analyze it carefully: >> >> def match(mf,mt,hf,ht): >> mydiff = diff_in_seconds(mf,mt) >> if (mf >= hf and mt <= ht) or (mf < hf and mt > ht): >> mydiff = diff_in_seconds(mf,mt) >> hisdiff = diff_in_seconds(hf,ht) >> return min(1, hisdiff / mydiff) >> else: >> case1 = max(0, diff_in_seconds(hf, mt)) >> case2 = max(0, diff_in_seconds(mf, ht)) >> diff = min(case1, case2) >> return (diff / mydiff) >> >> def diff_in_seconds(d1,d2): >> timedelta = d2 - d1 >> return float(timedelta) >> >> print match(0,100,40,90) >> >> >> 2010/8/5 Alexandre González <agonzale...@gmail.com> >> >>> I've develope a "simple" function to calculate the difference between 2 >>> dates, and the time that they are interpolated. >>> >>> I need it to: I arrive to a site at a hour (my_from), I go out from the >>> site at a hour (my_to). Some friend arrive at the site at a hour (his_from) >>> and let it at a hour (his_to) >>> >>> If I stay in the site after he arrives and before he goes out, the >>> "probability" of match is 1, if I let the site after he arrives, the >>> probability of match is 0... You can see the samples in the documentation. >>> >>> I need to know if this is a good way to do, and if compare all the kinds >>> of matching (I've found 6). This is the code: >>> >>> def time_match(self, my_from, my_to, his_from, his_to): >>> """ >>> I've found 6 general kinds of time matching. It's better to >>> explain it with graphics: >>> >>> (my_from)--A--(my_to) >>> ------------------------- >>> (his_from)--B--(his_to) >>> """ >>> >>> # |-A-| |-A-| >>> # -------------------- or -------------------- >>> # |--B--| |--B--| >>> if my_to < his_from or his_to < my_from: >>> return 0 >>> >>> # |--A--| >>> # -------------------- >>> # |------B-------| >>> elif my_from >= his_from and my_to <= his_to: >>> return 1 >>> >>> # |-----A-------| >>> # -------------------- >>> # |-B-| >>> elif my_from < his_from and my_to > his_to: >>> my_diff_to_reuse = diff_in_seconds(my_from, my_to) >>> diff = my_diff_to_reuse - self.diff_in_seconds(his_from, >>> his_to) >>> >>> return (diff / my_diff_to_reuse) >>> >>> # |---A---| >>> # -------------------- >>> # |---B---| >>> elif my_from <= his_from and my_to <= his_to: >>> diff = self.diff_in_seconds(his_from, my_to) >>> >>> return (diff / self.diff_in_seconds(my_from, my_to)) >>> >>> # |---A---| >>> # -------------------- >>> # |---B---| >>> elif my_from >= his_from and my_to >= his_to: >>> diff = self.diff_in_seconds(my_from, his_to) >>> >>> return (diff / self.diff_in_seconds(my_from, my_to)) >>> >>> # If I'm here I have a problem >>> return 0 >>> >>> >>> def diff_in_seconds(date1, date2): >>> # Initial from: http://www.bytemycode.com/snippets/snippet/304/ >>> timedelta = date2 - date1 >>> diff = timedelta.days*24*3600 + timedelta.seconds >>> >>> return abs(float(diff)) >>> >>> Thanks! >>> -- >>> Please, don't send me files with extensions: .doc, .docx, .xls, .xlsx, >>> .ppt and/or .pptx >>> http://mirblu.com >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Django users" group. >>> To post to this group, send email to django-us...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> django-users+unsubscr...@googlegroups.com<django-users%2bunsubscr...@googlegroups.com> >>> . >>> For more options, visit this group at >>> http://groups.google.com/group/django-users?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Django users" group. >> To post to this group, send email to django-us...@googlegroups.com. >> To unsubscribe from this group, send email to >> django-users+unsubscr...@googlegroups.com<django-users%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/django-users?hl=en. >> > > > > -- > Please, don't send me files with extensions: .doc, .docx, .xls, .xlsx, .ppt > and/or .pptx > http://mirblu.com > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com<django-users%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > -- You received this message because you are subscribed to the Google Groups "Django users" group. 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