It would be

logbook_noc.objects.filter(StatusProgress__in = ['1 Pending', '2 On 
Progress'])

You can read more about this at Making queries 
<https://docs.djangoproject.com/en/2.1/topics/db/queries/> and please take 
a look at Coding styles 
<https://docs.djangoproject.com/en/dev/internals/contributing/writing-code/coding-style/>
 
and PEP8 <https://www.python.org/dev/peps/pep-0008/>, because reading this 
code is a pain. 

On Friday, November 30, 2018 at 8:28:22 AM UTC+2, pujiarahman wrote:
>
> helo, 
> iam new for python.  
>
> my : models.py
>
> lass logbook_noc(models.Model):
> idLogbookN = models.IntegerField(primary_key=True)
> kodetiket = models.CharField(max_length=30)
> CustName = models.CharField(max_length=30)
> TanggalLo = models.DateTimeField()
> DeskripsiLo = models.TextField()
> StatusProgress = models.CharField(max_length=30)
> PenangananLo = models.TextField() 
> TglUpdate = models.DateTimeField()
>
>
> class Meta:
> managed = False
> db_table = 'logbook_noc'
> def __str__(self):
> return self.Id
>
>   
>  my: views.py
>
> def home(request):
> logbooks = logbook_noc.objects.filter(StatusProgress = '1 Pending' )
> paginator = Paginator(logbooks, 8)
> page = request.GET.get('page')
> pb = paginator.get_page(page)
> return render(request, 'blog/home.html', {'pb':pb})
>
>
> how to add  one word again to filter like '2 On Progress'
> i tray to logbooks = logbook_noc.objects.filter(StatusProgress = '1 
> Pending' or '2 On Progress' )
> the output for status is only 1 Pending the 2 On Progress not display..
>
> Thanks
>
>

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