And to add on to Rich Ulrich's note, if the mean isn't zero, then z^2 is non-central chi-square. -Dick Startz
On Thu, 29 Nov 2001 12:29:47 -0500, Rich Ulrich <[EMAIL PROTECTED]> wrote: >On Thu, 29 Nov 2001 15:48:48 +0300, Ludovic Duponchel ><[EMAIL PROTECTED]> wrote: > >> If x values have a normal distribution, is there a normal distribution >> for x^2 ? > >If z is standard normal [ that is, mean 0, variance 1.0 ] >then z^2 is chi squared with 1 degree of freedom. > >And the sum of S independent z variates >is chi squared with S degrees of freedom. ---------------------- Richard Startz [EMAIL PROTECTED] Lundberg Startz Associates ================================================================= Instructions for joining and leaving this list and remarks about the problem of INAPPROPRIATE MESSAGES are available at http://jse.stat.ncsu.edu/ =================================================================