Unfortunately this doesn't work because ICompositeUserType doesn't
derive from IUserType and therefore the generic constraint on
UserTypeConvention is not satisfied:
The type 'TestProject.Data.NHibernateMaps.MoneyUserType' cannot be
used as type parameter 'TUserType' in the generic type or method
'FluentNHibernate.Conventions.UserTypeConvention<TUserType>'. There is
no implicit reference conversion from
'TestProject.Data.NHibernateMaps.MoneyUserType' to
'NHibernate.UserTypes.IUserType'.
On Mar 23, 11:28 pm, James Gregory <jagregory....@gmail.com> wrote:
> Instead of IUserTypeConvention, try deriving from the base-class
> UserTypeConvention, see if that makes any difference.
>
> You should be able to do what you've written as:
>
> public class MoneyTypeConvention
> : UserTypeConvention<MoneyUserType>
> {}
>
> On Mon, Mar 23, 2009 at 11:16 PM, James <james.freiwi...@gmail.com> wrote:
>
> > I'm having trouble mapping composite user types with the new style
> > conventions.
>
> > I've done the following:
>
> > public class MoneyTypeConvention : IUserTypeConvention
> > {
> > public bool Accept(IProperty target)
> > {
> > return Accept(target.PropertyType);
> > }
>
> > public void Apply(IProperty target)
> > {
> > target.CustomTypeIs(typeof (MoneyUserType));
> > }
>
> > public bool Accept(Type type)
> > {
> > return type == typeof (Money);
> > }
> > }
>
> > However I'm still getting:
> > NHibernate.MappingException: Could not determine type for:
> > TestProject.Core.Model.ValueTypes.Money, TestProject.Core,
> > Version=1.0.0.0, Culture=neutral, PublicKeyToken=null, for columns:
> > NHibernate.Mapping.Column(Price)
>
> > Not really sure where I'm going wrong. I'm setting up my mappings as
> > follows:
>
> > AutoPersistenceModel mappings = AutoPersistenceModel
> > .MapEntitiesFromAssemblyOf<TestModelClass>
> > ()
> > .Where(GetAutoMappingFilter)
>
> > .ConventionDiscovery.AddFromAssemblyOf<AutoPersistenceModelGenerator>
> > ()
> > .WithSetup(GetAutoMappingSetup)
> > .UseOverridesFromAssemblyOf<AutoPersistenceModelGenerator>
> > ();
>
> > Any help would be much appreciated.
> > Thanks,
> > James.
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