Igor Lopez wrote: > Jason wrote: >> Assuming I need to draw 100mA for 1 sec, that's 0.100 Coulombs. The pic >> has a minimum operating voltage of 2V. Worst case, the battery is down >> to 2.7V, so I want no more than 0.5V drop when the motor runs. From >> [2], my capacitor should be 200mF. Yikes. > > I am assuming we are talking about a DC motor here. > If the resistance of the windings are in the range of 25 ohm then you are > pretty > well on your calculations since you will operate the motor with a > constant DC voltage.
Yep, 29 ohm internal resistance. It pulls 100 mA at 3V DC even when hooked up to a power supply. I thank my lucky stars for that one. :-) thx, Jason. _______________________________________________ geda-user mailing list geda-user@moria.seul.org http://www.seul.org/cgi-bin/mailman/listinfo/geda-user