Hi,
I have been using Haskell for a few weeks now and I can say that I
am totally impressed by how easy it is to program with it. I am now
doing some small exercises to get used to the language syntax and I have
a little (newbie) question:
Suppose I declare a function foo like:
foo :: [Double] -> Int -> Int
foo a b
Suppose now that I want to apply this function to a list that
contains lists of doubles (something like [[Double]]) using map, but I
want to keep the 'b' parameter fixed (with a value of 5 for instance).
Is it possible to use map passing the function foo with the 2nd argument
only ? In other words, if I wrote this function like:
foo :: Int -> [Double] -> Int
I could clearly call it with:
map (foo 5) my_list_of_lists_of_doubles
But how to do that (if possible) when I invert the parameters list ?!
Thanks in advance,
Andre Abs da Cruz
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