In message <a9927dee74f64e0186f0b...@clph-d133.clinpharm.ox.ac.uk>, Paul
Hodges <p...@cassland.org> writes
--On 22 May 2009 18:02 +0200 "James E. Bailey"
<derhindem...@googlemail.com> wrote:
I've never seen this, in fact the opposite! How is lilypond
insisting? Can you make a two or three measure example that shows
what you mean?
Sorry, I missed out what turned out to be the key bit of information -
that the last bar was also the second part of an \alternative at the
end of a repeat which started with a \partial. I have been shown a
solution off list. What I had written was:
\alternative {
{ c2. }
{ c1 \bar "|." }
}
I think it's the short first alternative that's throwing it off. Another
trick to try is to pad it out - { c2. s4 }. That might be a lot simpler
than various tweaks to get it to behave (although it might introduce
other problems instead ...).
Cheers,
Wol
--
Anthony W. Youngman - anth...@thewolery.demon.co.uk
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