>Repeat with x = 1 to mylist.count
> repeat with y = 1 to mylist[x].count
> put mylist[x][y]
That would do it with the list I suggested. I probably should have posted
the actual list--I'm reading it from an XML file, and I can't count on all
the child nodes at the same level having the same property. A better
example would be something like[[#puzzle: [#title: "One"], [#level:
"Moderate"], [#word: "Lingo"], [#word: "Director"]], [#puzzle: [#title:
"Two"], [level: "Beginner"], [#word: "Action"], [#word: "Flash"]]]
I think I counted my brackets right.
Tab's method would work. It seems like I should be able to do it with
repeat with #word in something.
Cordially,
Kerry Thompson
Learning Network
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