Frank Klemm wrote:
>
> :: > This is a little bit problematic, because the number of distorted
> :: > bands does not tell you the weight of distortions you will get.
> :: > What do you think sounds uglier:
> :: > 20 distorted bands, each 0.1 dB
> :: > or
> :: > 1 distorted band by 2 dB
> :: > ???
> ::
> :: I would say that 20 distorted bands at 0.1dB is preferable, and assume
> :: that this is the choice of lame's algorithms. Is this assumption wrong ?
> ::
> Yes and no.
>
> That depends on the distortion of the undistorted bands. Also undistorted
> bands have an distortion, it is negative.
You are saying : "has a distortion" != "is distorted" ?
> First you need a table of the probability to hear distortions:
>
> distortion probability error noise
> [d=dB] [p=%] [i]
> -10 50.0 0.0000
> -3 50.8 0.0004
> -2.5 52.0 0.0025
> -2 53.2 0.0064
> -1.5 55.6 0.020
> -1 57.9 0.040
> -0.5 63.3 0.116
> -0.25 66.3 0.176
> 0 70.2 0.281
isn't 0 dB distortion == no distortion ?
How can it be heared ?
> +0.1 72.2 0.336
> +0.2 74.2 0.422
> +0.3 76.1 0.504
> +0.4 78.0 0.593
> +0.5 80.0 0.706
> +1 87.1 1.28
> +1.5 93.7 2.34
> +2 97.2 3.65
> +2.5 99.0 5.43
> +3 99.8 8.4
> +3.5 99.9 9.5
[ snip ]
Sorry if this is an "reader IQ too low" error :-)
David Balazic
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