On 2/9/2011 11:39 AM, Bruce Southey wrote: > np.argmax(x>5) # doesn't appear to be correct
It was an answer to the particular question of how to do find_first, which it does (at the cost of a boolean array): it finds the first element greater than 5. >>> x array([5, 4, 3, 6, 7, 3, 2, 1]) >>> np.argmax(x>5) 3 >>> x[3] 6 You can also find the first element less than 4, etc. >>> np.argmax(x<4) 2 The condition should be chosen for the problem. As Josef pointed out, the usefulness of this and other approaches can depend on the monotonicity of the series. fwiw, Alan _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion