Thanks! Jose
On Thu, Aug 11, 2011 at 8:15 PM, Fernando Perez <fperez....@gmail.com>wrote: > On Thu, Aug 11, 2011 at 4:43 PM, Jose Borreguero <borregu...@gmail.com> > wrote: > > a = random.randn(3,3) > > b = a.reshape(1,3,3).repeat(50,axis=0) > > scipy.linalg.block_diag( *b ) > > > > slightly simpler, but equivalent, code: > > b = [a]*50 > scipy.linalg.block_diag( *b) > > Cheers, > > f > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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