> Would it be good to say exactly what type of rounding this is? What > is 19 / 5? How about 19 / -5? FWIW, here's what Perl > currently thinks: > > 19 / 5 = 3 > (-19)/ 5 = -3 > 19 /-5 = -3 > (-19)/-5 = 3
On way to solve this is to provide two sets of division operators, ie div/mod vs quo/rem, one of them is mapped to '/'/'%', and the other maps to regular method names. Hong
