Re: Junctions, Sets, and Threading.

[Aldo Calpini]

Damian Conway wrote:
 >    @s = 'item' _ [EMAIL PROTECTED];
That's:
     @s = 'item »_« @x;
(just checking that my unerstanding is correct, don't want to be 
nitpicking :-)

assuming that you meant to prepend the string "item" to each element of 
@x, isn't that:

       @s = 'item' »~« @x;
?
furthermore, given that the operator "hyperates" on one side only, 
shouldn't this be:

        @s = 'item' ~« @x;
?
cheers,
Aldo