On Jun 8, 2015, at 3:51 PM, Douglas E. Miles <d...@veritablesoftware.com> wrote:
> Hi all! > > From http://perldoc.perl.org/functions/substr.html: > > substr has a 4th argument (or you can use substr as an lvalue) for > replacement. > substr EXPR,OFFSET,LENGTH,REPLACEMENT > > From http://doc.perl6.org/routine/substr I don't see any way to do a > replacement. What is the idiomatic way of doing a positional string > replacement in Perl 6? Thanks! Method form: $ perl6 -e 'my $s = "abc"; $s.substr-rw(1,1) = "z"; say $s;' azc Function form: $ perl6 -e 'my $s = "abc"; substr-rw($s, 1,1) = "z"; say $s;' azc I also do not see substr-rw in doc.perl6.org. It needs to be added. In the meantime, you can find it here: http://design.perl6.org/S32/Str.html — Hope this helps, Bruce Gray (Util of PerlMonks)
