On 08/20/2013 09:43 PM, Paolo Bonzini wrote: > Il 20/08/2013 03:07, Wanlong Gao ha scritto: >> -numa node,nodeid=0,cpus=0, \ >> -numa mem,size=1024M,policy=membind,host-nodes=0-1 \ >> -numa node,nodeid=1,cpus=1 \ >> -numa mem,size=1024M,policy=interleave,host-nodes=1 > > What nodes would the memory be in, for this command line? Does it just
The original concept here is that if the nodeid is omitted, it will be set node by node from node0. Here I also keep the original concept, so the memory will be in node0 and node1. > compute the total and split it evenly across the nodes (so that the > "-numa node" options could omit nodeid and cpus too)? If no memory size is given for any nodes, the memory will split across all nodes like (ram_size / nb_numa_nodes). And yes nodeid and cpus options can also be omitted from the original concept. > > Also, do you still need a "-m" option if you use "-numa mem"? The "-m" options will be used to compute the memory size of each node if the memory size of each node is not set by "-numa mem" option. This is also be consistent with the original concept. Thanks, Wanlong Gao > > Paolo >
