Hi R users

I was wondering on how to use lapply & co when the applied function has a 
conditional statement and the output is a 'growing' object.
See example below:

list1 <- list('A','B','C')
list2 <- c()

myfun <- function(x,list2)
{
  one_elem <- x
  cat('one_elem= ', one_elem, '\n')
  random <- sample(1:2,1)
  show(random)
  if(random==2)
  {
    list2 <- c(list2,one_elem)
  }else{
    list2
  }
}

lapply(list1,myfun,list2)

Is there a way to get rid of the 'NULL' elements in the output (when there is 
any?), without using a for loop?

Thanks for your help
Lorenzo

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to