On 12-07-22 5:33 PM, arun wrote:
Hi Duncan,
That was my original suggestioin. His reply suggests that it is not that he
wanted.
I didn't see your reply. Maybe you sent it privately? In any case, I
think it is up to Sverre to give an example of what he wants, since your
suggestion, Weidong's and mine all appear to do what he asked for.
Duncan Murdoch
"
Not quite. It still orders the values in an increasing order, you've
just changed the values here. I'm using reorder() to prepare for
plotting the values, so I can't change the values."
bymean2<-with(InsectSprays,reorder(spray,count,function(x) -mean(x)))
bymean2
[1] A A A A A A A A A A A A B B B B B B B B B B B B C C C C C C C C C C C C
D D
[39] D D D D D D D D D D E E E E E E E E E E E E F F F F F F F F F F F F
attr(,"scores")
A B C D E F
-14.500000 -15.333333 -2.083333 -4.916667 -3.500000 -16.666667
####################
Levels: F B A D E C
#######################
A.K.
----- Original Message -----
From: Duncan Murdoch <murdoch.dun...@gmail.com>
To: Sverre Stausland <john...@fas.harvard.edu>
Cc: r-help@r-project.org
Sent: Sunday, July 22, 2012 4:56 PM
Subject: Re: [R] Reorder in decreasing order
On 12-07-22 12:27 PM, Sverre Stausland wrote:
reorder() is probably the best way to order the levels in a vector
without manually specifying the order. But reorder() orders by default
in an increasing order: "The levels are ordered such that the values
returned by ‘FUN’ are in increasing order."
Is there a way to do what reorder() does, but order the levels
according to a _decreasing_ order of the values?
Yes, as Weidong suggested:
x <- rnorm(20)
y <- factor(sample(letters[1:3], 20, replace=TRUE))
reorder(y, x, mean)
[1] a a c c c b b a b a c c b b a a a a c a
attr(,"scores")
a b c
-0.2012975 0.6117830 0.2180352
Levels: a c b
reorder(y, x, function(x) -mean(x))
[1] a a c c c b b a b a c c b b a a a a c a
attr(,"scores")
a b c
0.2012975 -0.6117830 -0.2180352
Levels: b c a
Duncan Murdoch
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