Hi, Try this,
files <- paste("RA94010",1:3,sep="") # or files <- list.files(pattern = "RA94010") list.of.data <- lapply(files, read.table, header=F) # if required, collapse into a single data.frame do.call(rbind, list.of.data) HTH, baptiste 2009/10/28 Sybille Wendel <wendel.sybi...@googlemail.com>: > Dear all, > > I have a lot of data files (.txt) that I want to read in all at once, if > possible. > the files have names in time system. for example: RA940101, RA940102, > RA940103, RA940104 an so on. > (meaning: RA, year:91, month: here january, day of the month.) > > I tried something like > > vektor <- c("RA940101","RA940102","RA940103") > > for (x in 1:3) > { data <- read.table(paste(vektor[x],sep=""),header=F) } > > But how can I put the vektor on the left side, so that data would be instead > of data the three first days of the year 1994? > > best wishes and thanks a lot for your answers, > > Sybille > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.