Farouk Nathoo <[EMAIL PROTECTED]> writes:
> parameter <- 0 # initial value
> for (i in 1:1000)
> {
> parameter <- one.step(parameter, data)
> mem <- memory.size()
> cat(parameter," ", mem,"\n")
> }
>
>
> I output the memory.size() at each iteration and this grows and grows
> until I run out of memory and get an allocation error. When this happens,
> I record the last parameter value, quit R, start R again and rerun the
> procedure starting with this most recent value. I'd rather not do it this
> way! I have increased the memory limit using the memory.limit() function
> and this helps a bit.
>
> My Questions:
>
> 1. Is there any way to free the memory after each iteration since
> I really don't need anything other than the most recent parameter value?
That generally shouldn't be necessary, unless you're doing something
in one.step() that causes R objects to hang around after each
iteration. A typical mistake is to have an attach() inside the loop
and end up with 1000 copies of the entire data set on the search
path...
> 2. If I run this code on the same machine but using the Linux OS will i
> have the same problem?
Most likely, yes.
> 3. Would I be able to avoid this problem if I ran the loop in some other
> language like Perl or C and called the R function to do one iteration at
Probably not.
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907
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