I have x,y data and would like to compute the average of y at each level of x.
> x [1] 0.006110 0.007027 0.007027 0.007027 0.008081 0.008081 0.008081 0.008081 [9] 0.008081 0.008081 0.008081 0.009293 0.009293 0.009293 0.009293 0.009293 [17] 0.009293 0.009293 0.009293 0.010686 0.010686 0.010686 0.010686 0.010686 [25] 0.010686 0.010686 0.010686 0.010686 0.010686 0.012289 0.012289 0.012289 [33] 0.012289 0.012289 0.012289 0.012289 0.012289 0.012289 0.012289 0.012289 [41] 0.012289 0.012289 0.014133 0.014133 0.014133 0.014133 0.016253 0.018691 [49] 0.021494 0.024718 0.028426 0.032690 0.037594 0.043233 0.049718 0.057175 [57] 0.065752 0.075614 0.086957 0.100000 > y [1] 0 0 1 0 0 1 0 1 1 0 1 1 1 0 1 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 0 1 1 1 1 1 1 [39] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 > table(x,y) y x 0 1 0.00611 1 0 0.007027 2 1 0.008081 3 4 0.009293 3 5 0.010686 4 6 0.012289 1 12 0.014133 0 4 0.016253 0 1 0.018691 0 1 0.021494 0 1 0.024718 0 1 0.028426 0 1 0.03269 0 1 0.037594 0 1 0.043233 0 1 0.049718 0 1 0.057175 0 1 0.065752 0 1 0.075614 0 1 0.086957 0 1 0.1 0 1 I would like to compute p = count1/(count0 +count1). For example, for x=0.012289, p= 12/(1+12)= 0.923077. Please tell me how to do it. Maybe there is a better way to do this without going through table(). Thanks very much for any help. Bill Simpson ______________________________________________ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help