X <- numeric(length(data.frame))
before the loop maybe work, because
my computer works and works !?
christian
---------- Weitergeleitete Nachricht ----------
Subject: filter out many data.frames Date: Sonntag, 16. Mai 2004 00:02 From: Christian Schulz <[EMAIL PROTECTED]> To: [EMAIL PROTECTED]
Hi ,
i would like filter out all combinations of a data-mining result? How i have to declare X because in every loop step it have another lengths ?
X <- numeric(length(i1,...,i64)) ?
Many thanks Christian
tres <- function(data.frame) { + data <- expand.grid(class02 = c("A","B","C","D"), class04 = c("A","B","C","D"),PREDICT = c("A","B","C","D")) + for (i in 1:nrow(data)){ + X[i]<- dtree[dtree$class02 == paste(data$class02[i]) & dtree$class04 == paste(data$class04[i]) & dtree$PREDICT==paste(data$PREDICT[i]),] + } + return(X[i]) + }
Eh. You really want to rewrite that code. It depends on objects available in its parent (or grand-parent) envrionment.
I don't see why you need all those calls to paste().
You do *not* want to call an argument data.frame nor any other object data, but you *do* want to use the arguments specified.
Now, if X is initialized with numeric(), X is a numeric (n x 1) vector. I think you need at least a matrix or better a list, if the subsetting stuff returns more or even less than one row.
For a list X use, e.g., X <- vector(nrow(data), mode = "list") just before the for loop.
Uwe Ligges
tres(dtree)
Error: Object "X" not found
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