In IRC I had a question and I don't know how to do it ...
If you have a solution of an equation, how to apply the result to a
function?
sage: var('x y')
(x, y)
sage: solve([x+y==6, x-y==4], x, y)
[[x == 5, y == 1]]
sage: f = 2*x+y
The best I came up is
sage: f.subs(dict([ (s.lhs() , s.rhs()) for s in sol[0]]))
11
My proposal is, that Sage does this automatically, e.g. just
sage: f(sol[0])
11
Other ideas? Is this already possible?
Harald
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