Re: [algogeeks] C Problem

[kartik sachan]

+1  to yogesh

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Re: [algogeeks] C Problem

[sukran dhawan]

4 and 5. size of will check its first operand. so no evaluation takes
place...

On Sat, Sep 17, 2011 at 2:32 PM, abhinav gupta wrote:

> Ans will be:4,5
>
>
> On Sat, Sep 17, 2011 at 2:23 PM, Sanjay Rajpal  wrote:
>
>> #include
>>
>> int main()
>> {
>> int a=5;
>> printf("Size : %d\n",sizeof( a =15/2));
>> printf("A is %d.",a);
>> }
>>
>> What will be the value of a now ? Plz explain.
>> Sanju
>> :)
>>
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Re: [algogeeks] C Problem

[Yogesh Yadav]

4,5

statements inside sizeof() does not get executed...it will tell just size...


int a=3;
printf("%d",sizeof(a++));

here a++ will not be executed ...it will just tell size ...

Also, lets suppose it execute statements ...then sizeof(int),sizeof(node *)
...will always produce error because int and node* are not executable
statements



On Sat, Sep 17, 2011 at 2:48 PM, prasanth n  wrote:

> 4,7..if we assume the sizeof(int) as 4 bytes..
>
>
> On Sat, Sep 17, 2011 at 2:32 PM, abhinav gupta wrote:
>
>> Ans will be:4,5
>>
>>
>> On Sat, Sep 17, 2011 at 2:23 PM, Sanjay Rajpal  wrote:
>>
>>> #include
>>> int main()
>>> {
>>> int a=5;
>>> printf("Size : %d\n",sizeof( a =15/2));
>>> printf("A is %d.",a);
>>> }
>>>
>>> What will be the value of a now ? Plz explain.
>>> Sanju
>>> :)
>>>
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Re: [algogeeks] C Problem

[prasanth n]

4,7..if we assume the sizeof(int) as 4 bytes..

On Sat, Sep 17, 2011 at 2:32 PM, abhinav gupta wrote:

> Ans will be:4,5
>
>
> On Sat, Sep 17, 2011 at 2:23 PM, Sanjay Rajpal  wrote:
>
>> #include
>> int main()
>> {
>> int a=5;
>> printf("Size : %d\n",sizeof( a =15/2));
>> printf("A is %d.",a);
>> }
>>
>> What will be the value of a now ? Plz explain.
>> Sanju
>> :)
>>
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Re: [algogeeks] C Problem

[abhinav gupta]

Ans will be:4,5

On Sat, Sep 17, 2011 at 2:23 PM, Sanjay Rajpal  wrote:

> #include
>
> int main()
> {
> int a=5;
> printf("Size : %d\n",sizeof( a =15/2));
> printf("A is %d.",a);
> }
>
> What will be the value of a now ? Plz explain.
> Sanju
> :)
>
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[algogeeks] C Problem

[Sanjay Rajpal]

#include

int main()
{
int a=5;
printf("Size : %d\n",sizeof( a =15/2));
printf("A is %d.",a);
}

What will be the value of a now ? Plz explain.
Sanju
:)

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Re: [algogeeks] c problem

[bharatkumar bagana]

@priya:
compiler thinks that " a++; " statement is correct... But for that to do...'
a' should be of type modifiable ... so it gives error saying that "If u want
to modify , that should be lvalue, so lvalue required" 

On Sun, Sep 4, 2011 at 2:27 AM, Yogesh Yadav  wrote:

> @Priya:
> Because a is *unmodifiable* LValue. When we are using a=a+1(a++) , this
> means that we are changing the *base address* of array a[], and that can
> not be possible due to Library files.
>
>
>
>
> On Sun, Sep 4, 2011 at 11:49 AM, priya ramesh <
> love.for.programm...@gmail.com> wrote:
>
>> @yogesh: Thanks a lot for the explaination. Good one indeed. Can you plz
>> tell me y the compiler says lvalue required for the statement
>> a++ when a is an lvalue??
>>
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Re: [algogeeks] c problem

[Yogesh Yadav]

@Priya:
Because a is *unmodifiable* LValue. When we are using a=a+1(a++) , this
means that we are changing the *base address* of array a[], and that can not
be possible due to Library files.



On Sun, Sep 4, 2011 at 11:49 AM, priya ramesh <
love.for.programm...@gmail.com> wrote:

> @yogesh: Thanks a lot for the explaination. Good one indeed. Can you plz
> tell me y the compiler says lvalue required for the statement
> a++ when a is an lvalue??
>
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Re: [algogeeks] c problem

[priya ramesh]

@yogesh: Thanks a lot for the explaination. Good one indeed. Can you plz
tell me y the compiler says lvalue required for the statement
a++ when a is an lvalue??

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Re: [algogeeks] c problem

[Yogesh Yadav]

@Priya:

Lvalue is not a contant value. It can be modifiable or unmodifiable. Lvalue
stands for location value that means that we can store some value here in
this location and rvalue stands for read value that means that it can be
stored at some location that is in memory having lvalue.

Here in case of array a[]. a is unmodifiable Lvalue(Location). That means it
can be used in left hand side of assignment operator because its memory
location.

i.e a[1]=5;
it is a location of array having index 1 contaioning value as 5.

Here 5 was a RValue(Read Value) because it can be assigned to the LValue
Variable.

According to you it is a RValue(Read Value).If it is so then this program
should work

a[]={1,2,3};
b[];
b=a;

But it does not . Because a is not a value that can be read .It was a memory
location.So we cannot assign array a to array b. For this we have to use

memset(b,a,sizeof(b))





On Sat, Sep 3, 2011 at 11:10 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

> if it is an l value, the compiler should say
> "cannot modify const value"
> instead it says
> "l value required"
> This statement proves that a is an r value in main. right??
>
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Re: [algogeeks] c problem

[priya ramesh]

if it is an l value, the compiler should say
"cannot modify const value"
instead it says
"l value required"
This statement proves that a is an r value in main. right??

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Re: [algogeeks] c problem

[sukran dhawan]

@priya :array is a constant pointer to a non constant data remember

On Sat, Sep 3, 2011 at 6:48 PM, priya ramesh  wrote:

> ok but y does the compiler say lvalue required if you perform a++??
>
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Re: [algogeeks] c problem

[sukran dhawan]

lvalue

On Sat, Sep 3, 2011 at 6:44 PM, himanshu kansal  wrote:

> an array is always an *unmodifiable* l-value.
>
>
> On Sat, Sep 3, 2011 at 6:23 PM, priya ramesh <
> love.for.programm...@gmail.com> wrote:
>
>> In main, any array say char a[200],
>> a refers to an r value or an lvalue??
>>
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>
>
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>Regards
>  Himanshu Kansal
>Msc Comp. sc.
> (University of Delhi)
>
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Re: [algogeeks] c problem

[priya ramesh]

ok but y does the compiler say lvalue required if you perform a++??

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Re: [algogeeks] c problem

[himanshu kansal]

an array is always an *unmodifiable* l-value.

On Sat, Sep 3, 2011 at 6:23 PM, priya ramesh  wrote:

> In main, any array say char a[200],
> a refers to an r value or an lvalue??
>
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 Himanshu Kansal
   Msc Comp. sc.
(University of Delhi)

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[algogeeks] c problem

[priya ramesh]

In main, any array say char a[200],
a refers to an r value or an lvalue??

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Re: [algogeeks] c problem

[coder dumca]

@harshalthanks  , can u tell me how to find what features are compiler
dependent

On Wed, Jun 8, 2011 at 4:28 PM, Harshal  wrote:

> This depends upon the implementation. Hence, your program is not
> portable. It's allowed to return NULL, and it's allowed to return a non-NULL
> pointer. Both ways are sanctioned by the Standard.
>
> On Wed, Jun 8, 2011 at 4:20 PM, coder dumca  wrote:
>
>> can any one tell me why this code perfectly running and giving ouput 56
>>
>> int main()
>> {
>> int *p=malloc(0);
>> *p=56;
>> printf("%d",*p);
>> return 0;
>> }
>>
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Re: [algogeeks] c problem

[Harshal]

This depends upon the implementation. Hence, your program is not
portable. It's allowed to return NULL, and it's allowed to return a non-NULL
pointer. Both ways are sanctioned by the Standard.

On Wed, Jun 8, 2011 at 4:20 PM, coder dumca  wrote:

> can any one tell me why this code perfectly running and giving ouput 56
>
> int main()
> {
> int *p=malloc(0);
> *p=56;
> printf("%d",*p);
> return 0;
> }
>
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III Year B.Tech CSE,
NIT Surathkal, Karnataka, India.

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[algogeeks] c problem

[coder dumca]

can any one tell me why this code perfectly running and giving ouput 56

int main()
{
int *p=malloc(0);
*p=56;
printf("%d",*p);
return 0;
}

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Re: [algogeeks] C++ problem..

[Aakash Johari]

@balaji: that's the default value for the parameter. Basically, the
advantage of the default parameter is that you need not to explicitly define
the non-parameterized constructor.

See the difference yourself with following 2 examples.

1)   *class A {
   int m;

   A (int a) {
m = a;
   }
 };*

when you declare an obj of the class A as :
  * A obj;*
in main(), then it reports an error. because the class lacks the constructor
of the form:
*  A() {
  }
*
2) *class A {
   int m;

   A (int a = 0) {
m = a;
   }
 };*

when you declare an obj of the class A as :
  * A obj;*
in main(), then it doesn't report error. because the default parameter lets
the user to skip the explicit(rather strictly) passing the argument value.
When user doesn't pass the argument value, it takes it as the default value
0.

On Wed, May 25, 2011 at 1:42 AM, Gaurav Saxena wrote:

> Actually
>
>
> A(int *m=0*)
>> {
>> a=m;
>> }
>> not
>>   A*(int m*) {
>>a = m;
>> }
>>
>
> means m has a default value of 0 ie this value will be used if no parameter
> is given . So when you pass it a parameter default value is simply ignored.
>
> On Wed, May 25, 2011 at 12:15 PM, Balaji S wrote:
>
>> ya.. thanks :) it works. but.. we are initializing m to 0 in everycall
>> ryt.. ? then how does 1,2,3,is initialized??
>>
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-- 
-Aakash Johari
(IIIT Allahabad)

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Re: [algogeeks] C++ problem..

[Gaurav Saxena]

Actually


A(int *m=0*)
> {
> a=m;
> }
> not
>   A*(int m*) {
>a = m;
> }
>

means m has a default value of 0 ie this value will be used if no parameter
is given . So when you pass it a parameter default value is simply ignored.

On Wed, May 25, 2011 at 12:15 PM, Balaji S  wrote:

> ya.. thanks :) it works. but.. we are initializing m to 0 in everycall
> ryt.. ? then how does 1,2,3,is initialized??
>
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Thanks and Regards ,
Gaurav Saxena

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Re: [algogeeks] C++ problem..

[Balaji S]

ya.. thanks :) it works. but.. we are initializing m to 0 in everycall ryt..
? then how does 1,2,3,is initialized??

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Re: [algogeeks] C++ problem..

[Aakash Johari]

Change it to that.. It will still work.. Don't worry :)

On Tue, May 24, 2011 at 10:56 PM, Balaji S  wrote:

> but
> constructor is
>
>
> A(int *m=0*)
> {
> a=m;
> }
> not
>
>   A*(int m*) {
>a = m;
> }
>
>  ???
>
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-- 
-Aakash Johari
(IIIT Allahabad)

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Re: [algogeeks] C++ problem..

[Balaji S]

but
constructor is

A(int *m=0*)
{
a=m;
}
not
  A*(int m*) {
   a = m;
}

 ???

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Re: [algogeeks] C++ problem..

[Aakash Johari]

This way you can do:

#include 
>
> using namespace std;
>
> class A {
> public:
> int a;
>
> A(int m) {
> a = m;
> }
>
> A() {
> }
> };
>
> int main()
> {
> int i;
>
> A *obj[32];
>
> for ( i = 0; i <= 31; i++ ) {
> obj[i] = new A(i);
> }
>
> for ( i = 0; i <= 31; i++ ) {
> cout << obj[i]->a << endl;
> }
>
> return 0;
> }
>



On Tue, May 24, 2011 at 9:42 PM, Balaji S  wrote:

> Answer pls.. ;-)
>
> Class A
> {
> int a;
>
> public:
>
> A(int m = 0)
> {
> a = m;
> }
>
> int main()
> {
> int i = 0;
>
> /*
> Create the 32 Objects { nObjects[32] } of Class A
> &&
> Initialize the nObjects[i].a = i during the constructor call ( 0 <= i <= 31
> )
> */
> }
> --
> With Regards,
> Balaji.S
>
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-- 
-Aakash Johari
(IIIT Allahabad)

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[algogeeks] C++ problem..

[Balaji S]

Answer pls.. ;-)

Class A
{
int a;

public:

A(int m = 0)
{
a = m;
}

int main()
{
int i = 0;

/*
Create the 32 Objects { nObjects[32] } of Class A
&&
Initialize the nObjects[i].a = i during the constructor call ( 0 <= i <= 31
)
*/
}
-- 
With Regards,
Balaji.S

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