Re: [algogeeks] output

[Tamanna Afroze]

i think because of &operator the program is working differently... also
there is four data value print operation..


On Mon, Dec 9, 2013 at 2:34 AM, Tamanna Afroze  wrote:

> I got some other outputs.. when line 6 isn't commented i got 3 1 2 3, i m
> using turbo c++ compiler..
>
>
> On Fri, Dec 6, 2013 at 8:17 AM, pawan yadav wrote:
>
>> Hi All,
>>
>> I'm not able to get output of following c program :
>>
>> #include
>>  main()
>>  {
>>  int a[] ={ 1,2,3,4,5,6,7};
>>  char c[] = {'a','x','h','o','k'};
>>  //printf("%u   %u\n", &a[3], &a[0]);  line 6
>>  printf("%d %d %d %d \n", (&a[3]-&a[0]));
>>  }
>>
>> If line 6 is commented, output :
>>
>> 3 1562814827 1869117537 0
>>
>> Confusion : why is there 4 output?   "(&a[3]-&a[0])" should give only one.
>>
>> if line 6 is not commented, output :
>>
>> 1554221244   1554221232
>> 3 1554221232 1309214001 64
>>
>>
>>
>> Can anybody please explain why/how these outputs are coming?
>>
>> Thanks,
>> Pawan.
>>
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Re: [algogeeks] output

[Tamanna Afroze]

I got some other outputs.. when line 6 isn't commented i got 3 1 2 3, i m
using turbo c++ compiler..


On Fri, Dec 6, 2013 at 8:17 AM, pawan yadav wrote:

> Hi All,
>
> I'm not able to get output of following c program :
>
> #include
>  main()
>  {
>  int a[] ={ 1,2,3,4,5,6,7};
>  char c[] = {'a','x','h','o','k'};
>  //printf("%u   %u\n", &a[3], &a[0]);  line 6
>  printf("%d %d %d %d \n", (&a[3]-&a[0]));
>  }
>
> If line 6 is commented, output :
>
> 3 1562814827 1869117537 0
>
> Confusion : why is there 4 output?   "(&a[3]-&a[0])" should give only one.
>
> if line 6 is not commented, output :
>
> 1554221244   1554221232
> 3 1554221232 1309214001 64
>
>
>
> Can anybody please explain why/how these outputs are coming?
>
> Thanks,
> Pawan.
>
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[algogeeks] output

[pawan yadav]

Hi All,

I'm not able to get output of following c program :

#include
 main()
 {
 int a[] ={ 1,2,3,4,5,6,7};
 char c[] = {'a','x','h','o','k'};
 //printf("%u   %u\n", &a[3], &a[0]);  line 6
 printf("%d %d %d %d \n", (&a[3]-&a[0]));
 }

If line 6 is commented, output :

3 1562814827 1869117537 0

Confusion : why is there 4 output?   "(&a[3]-&a[0])" should give only one.

if line 6 is not commented, output :

1554221244   1554221232
3 1554221232 1309214001 64



Can anybody please explain why/how these outputs are coming?

Thanks,
Pawan.

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Re: [algogeeks] Output

[Rushiraj Patel]

As arithmetic operator has higher precedence than shifting operator , mask
will have 5th bit zero from left.

So it will deduct 16 from the input if 5th bit is set in the binary
representation of number.
so it will deduct 16 from 56 and 127..but not from 64

But its  just the procedural thing meaning i don't know..


On Sat, Nov 24, 2012 at 2:15 PM, rajesh pandey  wrote:

> void dosomething(int num)
> {
> int mask=~(1<<5-1);
>  int res=num&mask;
> printf("%d",res);
> }
> int main()
> {
> dosomething(56);
> dosomething(64);
> dosomething(127);
>  return 0;
> }
>
> please explain  the logic behind the output.
>
> Thanks,
> Rajesh
>
> --
>
>
>

-- 

[algogeeks] Output

[rajesh pandey]

void dosomething(int num)
{
int mask=~(1<<5-1);
int res=num&mask;
printf("%d",res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}

please explain  the logic behind the output.

Thanks,
Rajesh  

-- 

Re: [algogeeks] output of the program with explanation

[vishwa]

let me keep it simple

 y is integer pointer pointing to address 20 .. x=20

y+7 will point to the addressy + ( size(int) * 7) i.e  50 here
/*y is integer pointer*/

On Tue, Nov 6, 2012 at 11:45 AM, Rahul Kumar Patle <
patlerahulku...@gmail.com> wrote:

> because difference is of 30 bytes..
> and integer takes 4 byte...
> it is representing that there are 7 int blocks between the address x and y
> output will be same as 7 for 31, 30, 29, 28.
>
> 2012/11/6 rajesh pandey 
>
>> *int *x ,int *y;
>> x=(int *) 50;
>> y=(int *)20;
>> cout<>
>> why the output is 7.*
>>
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> Indian Institute of Technology, Kharagpur-721302, 
> India
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Re: Re: [algogeeks] output of the program with explanation

[rajesh . pandey . iiit]

@rahul thnx !!!

On , rahul patil  wrote:
its because it is integer pointer subtraction, So subtraction result will  
be divided by integer size.



so 30/4 = 7.



2012/11/6 rajesh pandey rajesh.pandey.i...@gmail.com>



int *x ,int *y;
x=(int *) 50;
y=(int *)20;
cout
why the output is 7.








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Re: [algogeeks] output of the program with explanation

[rahul patil]

its because it is integer pointer subtraction, So  subtraction  result will
be divided by integer size.

so 30/4 = 7.

2012/11/6 rajesh pandey 

> *int *x ,int *y;
> x=(int *) 50;
> y=(int *)20;
> cout<
> why the output is 7.*
>
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[algogeeks] output of the program with explanation

[rajesh pandey]

*int *x ,int *y;
x=(int *) 50;
y=(int *)20;
cout

[algogeeks] output

[jatin]

 anybdy has basic trie implementation (insertion and printing) ?
o/p
1)
main()
{
char *p1="Name";
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf("%s\n",p2);
} ...it's giving me empty string 
 
2)
i=5;
printf("%d",i++ * i++);
o/p and also tell the reason?

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Re: [algogeeks] output C

[atul anand]

 0001,
 0010,
 0100,
these number are represented in octal ..so u r getting decimal of the same.
1000 -> this is a decimal value;

preceding number by "0" means you are representing it in octal format

similarly preceding "0x" means representing in hexa format.

On Sun, Feb 26, 2012 at 3:38 AM, Ravi Ranjan wrote:

> #include 
> #include 
>
> #define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0]))
>
>   #define PrintInt(expr) printf("%s:%d\n",#expr,(expr))
>
> int main(int argc, char *argv[])
> {
>
>   /* The powers of 10 */
>   int pot[] = {
>   0001,
>   0010,
>   0100,
>   1000
>   };
>   int i;
>
>   for(i=0;iPrintInt(pot[i]);
>
>   system("PAUSE");
>   return 0;
> }
>
>
> howz dat output come plz explain??
>
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[algogeeks] output C

[Ravi Ranjan]

#include 
#include 

#define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0]))

  #define PrintInt(expr) printf("%s:%d\n",#expr,(expr))

int main(int argc, char *argv[])
{

  /* The powers of 10 */
  int pot[] = {
  0001,
  0010,
  0100,
  1000
  };
  int i;

  for(i=0;ihttp://groups.google.com/group/algogeeks?hl=en.

Re: [algogeeks] output expalnation?

[Ratan]

On ideone.com its showing compiler error and on ubuntu garbage value
of b gets as the result...

On Tue, Sep 27, 2011 at 10:21 AM, gaurav yadav
 wrote:
> b=6 will not execute..
>
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-- 
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B. Tech
MNNIT,
Allahabad

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Re: [algogeeks] output expalnation?

[gaurav yadav]

b=6 will not execute..

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Re: [algogeeks] output expalnation?

[sukran dhawan]

compile time error... except case labels nothing else will be executed in
case of switch statements... so definition of b will not be executed.so
compilation error

On Tue, Sep 27, 2011 at 6:28 AM, Ratan  wrote:

> #include
> int main()
> {
>int a=1;
>switch(a)
>{
> int b=6;
>case 1:
> printf("b is %d",b);
>break;
>default:
>printf("b is %d:",b);
>break;
>}
> return 0;
> }
>
> can any1 explain the o/p of this program...
>
>
>
>
>
> Thanxs n Regards
> --
> Ratan Modi
>
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[algogeeks] output expalnation?

[Ratan]

#include
int main()
{
int a=1;
switch(a)
{
 int b=6;
case 1:
printf("b is %d",b);
break;
default:
printf("b is %d:",b);
break;
}
return 0;
}

can any1 explain the o/p of this program...





Thanxs n Regards
-- 
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Re: [algogeeks] output

[Kunal Patil]

@Kumar: +1

@Kumar & Rajeshwar: ExitFailure is outputted because main is expected to
return something which is not done in your case. Just add return 0; at the
end of main to get expected output.

On Tue, Sep 13, 2011 at 11:33 PM, Ishan Aggarwal <
ishan.aggarwal.1...@gmail.com> wrote:

> int main()
> {printf("%s",printf("samsung")+fun());
> return 0;}fun(){return "electronic";}
>
>
>
>
> On Tue, Sep 13, 2011 at 11:28 PM, kumar raja wrote:
>
>> main(){printf("%s",printf("samsung")+fun());}fun(){return "electronic";}
>>
>> The printf is a function which returns the number of printed characters , 
>> and scanf is a function
>> which returns the number of inputs scanned .
>>
>> So after printing "samsung" it returns 7. fun() is returning a pointer to 
>> the constant string
>>
>>
>> "electronic" , so it is like 7["electronic"]
>>
>> so the %s prints that string from the 7th index onwards till end .
>>
>> So output is "nic"
>>
>> so the total output is "samsungnic"
>>
>>
>> but i dont know why it is exiting with some error code..
>>
>>
>>
>> On 13 September 2011 10:51, Rajeshwar Patra wrote:
>>
>>> http://codepad.org/erdnF74M
>>>
>>> can anyone explain the output ???
>>>
>>> --
>>> *Rajeshwar Patra,*
>>> *MCA final year,*
>>> *Nit Durgapur*
>>>
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>>
>>
>>
>> --
>> Regards
>> Kumar Raja
>> M.Tech(SIT)
>> IIT Kharagpur,
>> 10it60...@iitkgp.ac.in
>> 7797137043.
>> 09491690115.
>>
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>
>
>
> --
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> Ishan Aggarwal
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> Presidency Tower-A, M.G.Road,Sector-14
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Re: [algogeeks] output

[Ishan Aggarwal]

int main(){printf("%s",printf("samsung")+fun());return 0;}fun(){return
"electronic";}




On Tue, Sep 13, 2011 at 11:28 PM, kumar raja wrote:

> main(){printf("%s",printf("samsung")+fun());}fun(){return "electronic";}
>
> The printf is a function which returns the number of printed characters , and 
> scanf is a function
> which returns the number of inputs scanned .
>
> So after printing "samsung" it returns 7. fun() is returning a pointer to the 
> constant string
>
> "electronic" , so it is like 7["electronic"]
>
> so the %s prints that string from the 7th index onwards till end .
>
> So output is "nic"
>
> so the total output is "samsungnic"
>
> but i dont know why it is exiting with some error code..
>
>
>
> On 13 September 2011 10:51, Rajeshwar Patra wrote:
>
>> http://codepad.org/erdnF74M
>>
>> can anyone explain the output ???
>>
>> --
>> *Rajeshwar Patra,*
>> *MCA final year,*
>> *Nit Durgapur*
>>
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>
>
>
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> Kumar Raja
> M.Tech(SIT)
> IIT Kharagpur,
> 10it60...@iitkgp.ac.in
> 7797137043.
> 09491690115.
>
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Gurgaon,Haryana.122015 INDIA
Phone : +91-9654602663
ishan2.aggar...@aricent.com 

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Re: [algogeeks] output

[kumar raja]

main(){printf("%s",printf("samsung")+fun());}fun(){return "electronic";}

The printf is a function which returns the number of printed
characters , and scanf is a function
which returns the number of inputs scanned .

So after printing "samsung" it returns 7. fun() is returning a pointer
to the constant string
"electronic" , so it is like 7["electronic"]

so the %s prints that string from the 7th index onwards till end .

So output is "nic"

so the total output is "samsungnic"
but i dont know why it is exiting with some error code..



On 13 September 2011 10:51, Rajeshwar Patra wrote:

> http://codepad.org/erdnF74M
>
> can anyone explain the output ???
>
> --
> *Rajeshwar Patra,*
> *MCA final year,*
> *Nit Durgapur*
>
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10it60...@iitkgp.ac.in
7797137043.
09491690115.

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[algogeeks] output

[Rajeshwar Patra]

http://codepad.org/erdnF74M

can anyone explain the output ???

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*Rajeshwar Patra,*
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*Nit Durgapur*

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Re: [algogeeks] Output question

[Abhishek]

+1 to sagar.
@vartika: if you don't know the concept of Union then understanding this 
program will be quite lenghty, because it will involve lot of calculation. 
try to check some simple examples, like:

union a
{
int a;
char c;
};
int main()
{
 union a xy;
 xy.a=65;
 printf("%c",xy.c);
 xy.c=65;
 printf(" %d",xy.a);
return 0;
}

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Re: [algogeeks] Output question

[sagar pareek]

U should know that union's elements share memory alloted through the largest
data type like in this case 10 bytes is alloted and is shared by all the
union elements.

So in union x :- last element modified is c, so that's why it is printing
garbage values for int and char[] elements...
actually if u convert float value in binary then u will see that what's its
actual integer value is? same case for char[]

in union y : last modified element is integer thats y it is printing 100 for
integer... ascii value of 'd' is 100 thats y printing 'd' for char[] and
0.000 for float

On Mon, Aug 22, 2011 at 4:53 PM, vartika wrote:

> #include
> #include
> int main()
> {
>  typedef union
>  {
>  int a;
>  char b[10];
>  float c;
>  }
>  Union;
>
>  Union x,y = {100};
>  x.a = 50;
>  strcpy(x.b,"hello");
>  x.c = 21.50;
>
>  printf("Union x : %d %s %f \n",x.a,x.b,x.c );
>  printf("Union y :%d %s%f \n",y.a,y.b,y.c);
>  return 0;
> }
>
> Someone pls explain the output
>
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**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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[algogeeks] Output question

[vartika]

#include
#include
int main()
{
 typedef union
 {
  int a;
  char b[10];
  float c;
 }
 Union;

 Union x,y = {100};
 x.a = 50;
 strcpy(x.b,"hello");
 x.c = 21.50;

 printf("Union x : %d %s %f \n",x.a,x.b,x.c );
 printf("Union y :%d %s%f \n",y.a,y.b,y.c);
 return 0;
}

Someone pls explain the output

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[algogeeks] Output?? Why??

[noobcoder]

#include
int main()
{
  char arr[5] = "geeks";
  printf("%s", arr);
  getchar();
  return 0;
}

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Re: [algogeeks] output

[Anil Arya]

Answer=:>  32

On Fri, Aug 12, 2011 at 8:05 PM, Avenged  wrote:

> this is the question :
>
> #include
> #define prn(a) printf("%d",a)
> #define print(a,b,c) prn(a), prn(b), prn(c)
> #define max(a,b) (a>b?a:b)
>
> int main()
> {
> int x=1, y=2;
> print(max(x++,y),x,y);
> print(max(x++,y),x,y);
> return 0;
> }
>
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-- 
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computer science & engineering

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Re: [algogeeks] output

[Avenged]

this is the question :

#include
#define prn(a) printf("%d",a)
#define print(a,b,c) prn(a), prn(b), prn(c)
#define max(a,b) (a>b?a:b)

int main()
{
int x=1, y=2;
print(max(x++,y),x,y);
print(max(x++,y),x,y);
return 0;
}

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Re: [algogeeks] output

[sukran dhawan]

macro has not been terminated and it has so many errors

On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo  wrote:

>  output of the program?
>
> #define prn(a) printf("%d",a)
> #define print(a,b,c) prn(a), prn(b), prn(c)
> #define max(a,b) (a
>
> main()
> {
> int x=1, y=2;
> print(max(x++,y),x,y);
> print(max(x++,y),x,y);
> }
>
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Re: [algogeeks] output

[mani walia]

this is the question in de shaw written test

On Thu, Aug 11, 2011 at 11:48 PM, Anika Jain  wrote:

> this code has so many errors
>
> On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo  wrote:
>
>>  output of the program?
>>
>> #define prn(a) printf("%d",a)
>> #define print(a,b,c) prn(a), prn(b), prn(c)
>> #define max(a,b) (a
>>
>> main()
>> {
>> int x=1, y=2;
>> print(max(x++,y),x,y);
>> print(max(x++,y),x,y);
>> }
>>
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Re: [algogeeks] output

[Anika Jain]

this code has so many errors

On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo  wrote:

>  output of the program?
>
> #define prn(a) printf("%d",a)
> #define print(a,b,c) prn(a), prn(b), prn(c)
> #define max(a,b) (a
>
> main()
> {
> int x=1, y=2;
> print(max(x++,y),x,y);
> print(max(x++,y),x,y);
> }
>
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[algogeeks] output

[manvir siyo]

 output of the program?

#define prn(a) printf("%d",a)
#define print(a,b,c) prn(a), prn(b), prn(c)
#define max(a,b) (a

main()
{
int x=1, y=2;
print(max(x++,y),x,y);
print(max(x++,y),x,y);
}

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Re: [algogeeks] output?

[Arun Vishwanathan]

@sandeep: so the statement becomes if(ch=0) since printf returns integer
0...whats does this mean now actually?0 is ascii for NULL and so ch is
assinged to null? I am slightly confused..

On Tue, Aug 9, 2011 at 7:04 PM, SANDEEP CHUGH wrote:

> @all sorry i give wrong explanation by mistake..:P :P
>
> printf("")  returns no if characters.. in this case returns 0 . which is
> assigned to ch
>
> so in ch 0 is stored and 0 is the ascii value of null character
> when we using ch in --- if (ch) --> it will reduce to if(0) -- as 0 is the
> ascii value of null character
>
> so the output "it doesn't matter"
>
>
> On Tue, Aug 9, 2011 at 10:28 PM, Dipankar Patro wrote:
>
>> o/p:
>> It doesn't matter
>>
>> Reason:
>> printf() returns the number of characters printed to screen.
>> since printf("") will return 0, hence the *else* is selected.
>>
>>
>> On 9 August 2011 22:25, siddharth srivastava  wrote:
>>
>>>
>>>
>>>  On 9 August 2011 22:20, tech rascal  wrote:
>>>
 #include
 int main()
 {
 char ch;
 if((ch=printf("")))
 printf("it matters");
 else
 printf("it doesn't matter");
 return 0;
 }


>>> It doesn't matter
>>>
>>>
>>>

 what will b the output??

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>>>
>>>
>>>
>>> --
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>>> Siddharth Srivastava
>>>
>>>
>>>
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Re: [algogeeks] output?

[SANDEEP CHUGH]

@all sorry i give wrong explanation by mistake..:P :P

printf("")  returns no if characters.. in this case returns 0 . which is
assigned to ch

so in ch 0 is stored and 0 is the ascii value of null character
when we using ch in --- if (ch) --> it will reduce to if(0) -- as 0 is the
ascii value of null character

so the output "it doesn't matter"

On Tue, Aug 9, 2011 at 10:28 PM, Dipankar Patro  wrote:

> o/p:
> It doesn't matter
>
> Reason:
> printf() returns the number of characters printed to screen.
> since printf("") will return 0, hence the *else* is selected.
>
>
> On 9 August 2011 22:25, siddharth srivastava  wrote:
>
>>
>>
>> On 9 August 2011 22:20, tech rascal  wrote:
>>
>>> #include
>>> int main()
>>> {
>>> char ch;
>>> if((ch=printf("")))
>>> printf("it matters");
>>> else
>>> printf("it doesn't matter");
>>> return 0;
>>> }
>>>
>>>
>> It doesn't matter
>>
>>
>>
>>>
>>> what will b the output??
>>>
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>>
>>
>>
>> --
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>> Siddharth Srivastava
>>
>>
>>
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>
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Re: [algogeeks] output?

[siddharth srivastava]

my bad..that I didn't notice = (assumed it to be ==)

On 9 August 2011 22:28, SANDEEP CHUGH  wrote:

> it doesn't matter
>
> On Tue, Aug 9, 2011 at 10:25 PM, siddharth srivastava  > wrote:
>
>>
>>
>> On 9 August 2011 22:20, tech rascal  wrote:
>>
>>> #include
>>> int main()
>>> {
>>> char ch;
>>> if((ch=printf("")))
>>> printf("it matters");
>>> else
>>> printf("it doesn't matter");
>>> return 0;
>>> }
>>>
>>>
>> output wud be : It doesn't matter
>>
>
> reason:  in the printf("") ---> this will return null character and assign
> it to ch and null character has ascii value 0
>
> so statement reduces to
>
> if(0)
>
> rest u knw..
>
>
>
>>
>>
>>
>>>
>>> what will b the output??
>>>
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>>
>>
>>
>> --
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>> Siddharth Srivastava
>>
>>
>>
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Re: [algogeeks] output?

[SANDEEP CHUGH]

it doesn't matter

On Tue, Aug 9, 2011 at 10:25 PM, siddharth srivastava
wrote:

>
>
> On 9 August 2011 22:20, tech rascal  wrote:
>
>> #include
>> int main()
>> {
>> char ch;
>> if((ch=printf("")))
>> printf("it matters");
>> else
>> printf("it doesn't matter");
>> return 0;
>> }
>>
>>
> output wud be : It doesn't matter
>

reason:  in the printf("") ---> this will return null character and assign
it to ch and null character has ascii value 0

so statement reduces to

if(0)

rest u knw..



>
>
>
>>
>> what will b the output??
>>
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>
>
>
> --
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> Siddharth Srivastava
>
>
>
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Re: [algogeeks] output?

[Dipankar Patro]

o/p:
It doesn't matter

Reason:
printf() returns the number of characters printed to screen.
since printf("") will return 0, hence the *else* is selected.

On 9 August 2011 22:25, siddharth srivastava  wrote:

>
>
> On 9 August 2011 22:20, tech rascal  wrote:
>
>> #include
>> int main()
>> {
>> char ch;
>> if((ch=printf("")))
>> printf("it matters");
>> else
>> printf("it doesn't matter");
>> return 0;
>> }
>>
>>
> It doesn't matter
>
>
>
>>
>> what will b the output??
>>
>> --
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>
>
>
> --
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> Siddharth Srivastava
>
>
>
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Re: [algogeeks] output?

[Amol Sharma]

printf returns the numbers of character printed and here it prints nothing
i.e. 0 characters hence returns 0

and hence "it doesnt matter" gets printed
--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Tue, Aug 9, 2011 at 10:25 PM, tech rascal wrote:

> explanation??
>
>
> On Tue, Aug 9, 2011 at 10:24 PM, aditi garg wrote:
>
>> it doesnt matter
>>
>> On Tue, Aug 9, 2011 at 10:20 PM, tech rascal wrote:
>>
>>> #include
>>> int main()
>>> {
>>> char ch;
>>> if((ch=printf("")))
>>> printf("it matters");
>>> else
>>> printf("it doesn't matter");
>>> return 0;
>>> }
>>>
>>>
>>> what will b the output??
>>>
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>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
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Re: [algogeeks] output?

[siddharth srivastava]

On 9 August 2011 22:25, tech rascal  wrote:

> explanation??
>
>
printf returns the no of characters printed
moreover you have an uninitialized char (with garbage value) so comparison
will always be false



>
> On Tue, Aug 9, 2011 at 10:24 PM, aditi garg wrote:
>
>> it doesnt matter
>>
>> On Tue, Aug 9, 2011 at 10:20 PM, tech rascal wrote:
>>
>>> #include
>>> int main()
>>> {
>>> char ch;
>>> if((ch=printf("")))
>>> printf("it matters");
>>> else
>>> printf("it doesn't matter");
>>> return 0;
>>> }
>>>
>>>
>>> what will b the output??
>>>
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>>
>>
>>
>> --
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>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
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Re: [algogeeks] output?

[Varun Jakhoria]

it doesn't matter

On Tue, Aug 9, 2011 at 10:24 PM, Jayanthi shravan
 wrote:
>
>   it matters..
> On Tue, Aug 9, 2011 at 10:20 PM, tech rascal 
> wrote:
>>
>>
>>
>> what will b the output??
>>
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>
>
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...it's only about 0's & 1's

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Re: [algogeeks] output?

[siddharth srivastava]

On 9 August 2011 22:20, tech rascal  wrote:

> #include
> int main()
> {
> char ch;
> if((ch=printf("")))
> printf("it matters");
> else
> printf("it doesn't matter");
> return 0;
> }
>
>
It doesn't matter



>
> what will b the output??
>
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Re: [algogeeks] output?

[tech rascal]

explanation??

On Tue, Aug 9, 2011 at 10:24 PM, aditi garg wrote:

> it doesnt matter
>
> On Tue, Aug 9, 2011 at 10:20 PM, tech rascal wrote:
>
>> #include
>> int main()
>> {
>> char ch;
>> if((ch=printf("")))
>> printf("it matters");
>> else
>> printf("it doesn't matter");
>> return 0;
>> }
>>
>>
>> what will b the output??
>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
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Re: [algogeeks] output?

[Jayanthi shravan]

  it matters..
On Tue, Aug 9, 2011 at 10:20 PM, tech rascal wrote:

>
>
>
> what will b the output??
>
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Re: [algogeeks] output?

[aditi garg]

it doesnt matter

On Tue, Aug 9, 2011 at 10:20 PM, tech rascal wrote:

> #include
> int main()
> {
> char ch;
> if((ch=printf("")))
> printf("it matters");
> else
> printf("it doesn't matter");
> return 0;
> }
>
>
> what will b the output??
>
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Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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[algogeeks] output?

[tech rascal]

#include
int main()
{
char ch;
if((ch=printf("")))
printf("it matters");
else
printf("it doesn't matter");
return 0;
}


what will b the output??

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Re: [algogeeks] output help

[SANDEEP CHUGH]

i dnt get it.. any better explanation..

On Tue, Aug 9, 2011 at 1:13 PM, dinesh bansal  wrote:

> On a little-endian machine, bit structure will be represented as:
>
>  0x00 00 00 45
>
> which is bit.bit4 = 0010 (2 in decimal) bit.bit3 = 0010 (2 in decimal)
> bit.bit1 = 1 (1 in decimal)
>
> since bit.bit1 exists at the rightmost position, while displaying data as
> integer, compiler just repeats the same bit to all the remaining positions
> making it 0x (-1). You can confirm it while setting bit.bit1 to 0
>
> -Dinesh Bansal
>
>
> On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava 
> wrote:
>
>> #include
>> #include
>>
>> int main()
>> {
>> struct value
>> {
>> int bit1:1;
>> int bit3:4;
>> int bit4:4;
>> }bit={1,2,2};
>> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
>> getche();
>> return 0;
>> }
>>  the above code gives output : -1 2 2
>> any idea why???
>>
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>
>
> --
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> best way."
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Re: [algogeeks] output help

[dinesh bansal]

On a little-endian machine, bit structure will be represented as:

 0x00 00 00 45

which is bit.bit4 = 0010 (2 in decimal) bit.bit3 = 0010 (2 in decimal)
bit.bit1 = 1 (1 in decimal)

since bit.bit1 exists at the rightmost position, while displaying data as
integer, compiler just repeats the same bit to all the remaining positions
making it 0x (-1). You can confirm it while setting bit.bit1 to 0

-Dinesh Bansal

On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava wrote:

> #include
> #include
>
> int main()
> {
> struct value
> {
> int bit1:1;
> int bit3:4;
> int bit4:4;
> }bit={1,2,2};
> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> getche();
> return 0;
> }
>  the above code gives output : -1 2 2
> any idea why???
>
> --
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best way."

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Re: [algogeeks] output help

[Rohit Srivastava]

hey guys thanks got it!!


On Tue, Aug 9, 2011 at 12:49 PM, sanjay ahuja wrote:

> Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
> treated as int (signed). Thus lower order bit of bit3 which is 2, are
> 0010 which is 2
> try with
> 1) int bit3:2, output will be -2
> 2) unsigned int bit3:2, output will be 2.
>
> I hope it is cleared now
>
> On 8/9/11, Rohit Srivastava  wrote:
> > #include
> > #include
> >
> > int main()
> > {
> > struct value
> > {
> > int bit1:1;
> > int bit3:4;
> > int bit4:4;
> > }bit={1,2,2};
> > printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> > getche();
> > return 0;
> > }
> >  the above code gives output : -1 2 2
> > any idea why???
> >
> > --
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> >
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>
> Sanjay Ahuja,
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Re: [algogeeks] output help

[sanjay ahuja]

Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
treated as int (signed). Thus lower order bit of bit3 which is 2, are
0010 which is 2
try with
1) int bit3:2, output will be -2
2) unsigned int bit3:2, output will be 2.

I hope it is cleared now

On 8/9/11, Rohit Srivastava  wrote:
> #include
> #include
>
> int main()
> {
> struct value
> {
> int bit1:1;
> int bit3:4;
> int bit4:4;
> }bit={1,2,2};
> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> getche();
> return 0;
> }
>  the above code gives output : -1 2 2
> any idea why???
>
> --
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>

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Re: [algogeeks] output help

[aditi garg]

I think it is because bit1 is only 1 bit fwide and whn u initialize it to
1,since MSB is 1 it treats it as a negative integer...Plz correct me if i am
wrong...

On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava wrote:

> #include
> #include
>
> int main()
> {
> struct value
> {
> int bit1:1;
> int bit3:4;
> int bit4:4;
> }bit={1,2,2};
> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> getche();
> return 0;
> }
>  the above code gives output : -1 2 2
> any idea why???
>
> --
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-- 
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Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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[algogeeks] output help

[Rohit Srivastava]

#include
#include

int main()
{
struct value
{
int bit1:1;
int bit3:4;
int bit4:4;
}bit={1,2,2};
printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
getche();
return 0;
}
 the above code gives output : -1 2 2
any idea why???

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Re: [algogeeks] output help

[Kamakshii Aggarwal]

got it...thanks

On Mon, Aug 8, 2011 at 12:39 AM, aseem garg  wrote:

> typedef doesn't declare an instance of a variable, it declares a type (type
> alias actually),
>
> static is a qualifier you apply to an instance, not a type, so you can use
> static when you use the type, but not when you define the type.
> Aseem
>
>
>
> On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal  > wrote:
>
>> #include
>> int main()
>> {
>>typedef static int *i;
>>   static int j;
>>   i a = &j;
>>   printf("%d", *a);
>>   getchar();
>>   return 0;
>> }
>>
>> what is the error in the code?
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] output help

[aseem garg]

typedef doesn't declare an instance of a variable, it declares a type (type
alias actually),

static is a qualifier you apply to an instance, not a type, so you can use
static when you use the type, but not when you define the type.
Aseem



On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal
wrote:

> #include
> int main()
> {
>typedef static int *i;
>   static int j;
>   i a = &j;
>   printf("%d", *a);
>   getchar();
>   return 0;
> }
>
> what is the error in the code?
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>
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Re: [algogeeks] output help

[Amol Sharma]

using typedef u define the static keyword as int
and the statement static int j thus becomes
int int j

hence the compiler gives the error "multiple storage class in declaration
specifiers"

--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal
wrote:

> #include
> int main()
> {
>typedef static int *i;
>   static int j;
>   i a = &j;
>   printf("%d", *a);
>   getchar();
>   return 0;
> }
>
> what is the error in the code?
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>
> --
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[algogeeks] output help

[Kamakshii Aggarwal]

#include
int main()
{
   typedef static int *i;
  static int j;
  i a = &j;
  printf("%d", *a);
  getchar();
  return 0;
}

what is the error in the code?
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Kamakshi
kamakshi...@gmail.com

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Re: [algogeeks] OUTPUT????

[Aditya Virmani]

output wud be:
0.00
float value= 00.0
integer value=1
1 1 1 0.00

On Sat, Aug 6, 2011 at 2:49 PM, SHIVAM AGRAWAL  wrote:

> any1 plz tell me y output of float type of dis prgrm  is zero?
>
> #include
> #define INT 1
> main()
> {
> struct a
> {
> int type;
> };
> struct c
> {
> int type;
> int e;
> };
> struct b
> {
> int type;
> float f;
> };
> union
> {
> struct a n;
> struct b nf;
> struct c ni;
> }all;
> all.ni.type=INT;
> all.nf.f=10.43;
> all.ni.e=1;
> printf("%f\n",all.nf.f);
> if(all.nf.type==INT)
> printf("float value =%2.1f",all.nf.f);
> if(all.ni.type==INT)
> printf("\ninteger value=%d",all.ni.e);
> printf("\n%d %d %d %f",all.ni.type,all.nf.type,all.ni.e,all.nf.f);
>
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Re: [algogeeks] OUTPUT????

[Ankit Minglani]

out put is :
10.375001
float value =10.4
integer value=1
1 1 1 10.37500

what us the problem ?

On Sat, Aug 6, 2011 at 2:19 AM, SHIVAM AGRAWAL  wrote:

> any1 plz tell me y output of float type of dis prgrm  is zero?
>
> #include
> #define INT 1
> main()
> {
> struct a
> {
> int type;
> };
> struct c
> {
> int type;
> int e;
> };
> struct b
> {
> int type;
> float f;
> };
> union
> {
> struct a n;
> struct b nf;
> struct c ni;
> }all;
> all.ni.type=INT;
> all.nf.f=10.43;
> all.ni.e=1;
> printf("%f\n",all.nf.f);
> if(all.nf.type==INT)
> printf("float value =%2.1f",all.nf.f);
> if(all.ni.type==INT)
> printf("\ninteger value=%d",all.ni.e);
> printf("\n%d %d %d %f",all.ni.type,all.nf.type,all.ni.e,all.nf.f);
>
>  --
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-- 
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Ankit Minglani
NITK Surathkal

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[algogeeks] OUTPUT????

[SHIVAM AGRAWAL]

any1 plz tell me y output of float type of dis prgrm  is zero?

#include
#define INT 1
main()
{
struct a
{
int type;
};
struct c
{
int type;
int e;
};
struct b
{
int type;
float f;
};
union
{
struct a n;
struct b nf;
struct c ni;
}all;
all.ni.type=INT;
all.nf.f=10.43;
all.ni.e=1;
printf("%f\n",all.nf.f);
if(all.nf.type==INT)
printf("float value =%2.1f",all.nf.f);
if(all.ni.type==INT)
printf("\ninteger value=%d",all.ni.e);
printf("\n%d %d %d %f",all.ni.type,all.nf.type,all.ni.e,all.nf.f);

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Re: [algogeeks] output

[Pramod Jayswal]

when swap is called ,as it is a macro ,before compilation its code is
replaced and the code before compilation bcomes:

> # define swap(a,b) temp=a; a=b; b=temp;
> main( )
> {
> int i, j, temp;
> i=5;
> j=10;
> temp=0;
> if( i > j)
>
   //code replaced here

> temp=a;   //not executed (false)
>
   a=b; //a=10(from b=10)
   b=temp;   //b=0 (from temp=0)

> printf( “%d %d %d”, i, j, temp);
> }
>
> and that is why u get output  10,0,0...
>
>

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Re: [algogeeks] output

[loka ranjane]

@saurabh:ya got it..thanks

On Sat, Aug 6, 2011 at 10:26 AM, saurabh singh  wrote:
> Try compiling with gcc -E .That will clear everything
>
> On Sat, Aug 6, 2011 at 10:25 AM, saurabh singh  wrote:
>>
>> hint:MACRo is just substituted as it is
>>
>> On Sat, Aug 6, 2011 at 10:23 AM, ranjane  wrote:
>>>
>>> # define swap(a,b) temp=a; a=b; b=temp;
>>> main( )
>>> {
>>> int i, j, temp;
>>> i=5;
>>> j=10;
>>> temp=0;
>>> if( i > j)
>>> swap( i, j );
>>> printf( “%d %d %d”, i, j, temp);
>>> }
>>>
>>>
>>> On compiling i got ans 10, 0, 0.explain..
>>>
>>> --
>>> You received this message because you are subscribed to the Google Groups
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>>>
>>
>>
>>
>> --
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT ALLAHABAD
>>
>>
>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
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Re: [algogeeks] output

[sagar pareek]

Lets see what happen with ur code...

original
# define swap(a,b) temp=a; a=b; b=temp;
main( )
{
int i, j, temp;
i=5;
j=10;
temp=0;
if( i > j)
swap( i, j );
printf( “%d %d %d”, i, j, temp);
}


after expansion of macro

# define swap(a,b) temp=a; a=b; b=temp;
main( )
{
int i, j, temp;
i=5;
j=10;
temp=0;
if( i > j)
*temp=a;  //only this line comes under if condition*
a=b;
 b=temp;
printf( “%d %d %d”, i, j, temp);
}

On Sat, Aug 6, 2011 at 10:26 AM, saurabh singh  wrote:

> Try compiling with gcc -E .That will clear everything
>
>
> On Sat, Aug 6, 2011 at 10:25 AM, saurabh singh wrote:
>
>> hint:MACRo is just substituted as it is
>>
>>
>> On Sat, Aug 6, 2011 at 10:23 AM, ranjane  wrote:
>>
>>> # define swap(a,b) temp=a; a=b; b=temp;
>>> main( )
>>> {
>>> int i, j, temp;
>>> i=5;
>>> j=10;
>>> temp=0;
>>> if( i > j)
>>> swap( i, j );
>>> printf( “%d %d %d”, i, j, temp);
>>> }
>>>
>>>
>>> On compiling i got ans 10, 0, 0.explain..
>>>
>>> --
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>>>
>>>
>>
>>
>> --
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT ALLAHABAD
>>
>>
>>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
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SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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Re: [algogeeks] output

[saurabh singh]

Try compiling with gcc -E .That will clear everything

On Sat, Aug 6, 2011 at 10:25 AM, saurabh singh  wrote:

> hint:MACRo is just substituted as it is
>
>
> On Sat, Aug 6, 2011 at 10:23 AM, ranjane  wrote:
>
>> # define swap(a,b) temp=a; a=b; b=temp;
>> main( )
>> {
>> int i, j, temp;
>> i=5;
>> j=10;
>> temp=0;
>> if( i > j)
>> swap( i, j );
>> printf( “%d %d %d”, i, j, temp);
>> }
>>
>>
>> On compiling i got ans 10, 0, 0.explain..
>>
>> --
>> You received this message because you are subscribed to the Google Groups
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>>
>>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
>


-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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Re: [algogeeks] output

[saurabh singh]

hint:MACRo is just substituted as it is

On Sat, Aug 6, 2011 at 10:23 AM, ranjane  wrote:

> # define swap(a,b) temp=a; a=b; b=temp;
> main( )
> {
> int i, j, temp;
> i=5;
> j=10;
> temp=0;
> if( i > j)
> swap( i, j );
> printf( “%d %d %d”, i, j, temp);
> }
>
>
> On compiling i got ans 10, 0, 0.explain..
>
> --
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>


-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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[algogeeks] output

[ranjane]

# define swap(a,b) temp=a; a=b; b=temp;
main( )
{
int i, j, temp;
i=5;
j=10;
temp=0;
if( i > j)
swap( i, j );
printf( “%d %d %d”, i, j, temp);
}


On compiling i got ans 10, 0, 0.explain..

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Re: [algogeeks] output???

[sagar pareek]

ha ha
its not like it stores slightly less than actual  :P :P

try this

float a=0.5,b=1.0,c=0.7;

if(0.5==a)
printf("yes a=0.5\n");

if(1.0==b)
printf("yes b=1.0\n");

if(0.7!=c)
printf("Yes c!=0.7\n");

o/p will be
yes a=0.5
yes b=1.0
yes c!=0.7

check it out i will explain it later...
On Fri, Aug 5, 2011 at 9:26 PM, Rajesh Kumar wrote:

> Thanks to all
>
>
> On Fri, Aug 5, 2011 at 8:53 PM, sukran dhawan wrote:
>
>> coz by default all real values are converted to double and it is larger
>> than float.ie real nos are not stored accurately inside computer
>> memory.so
>> since double occupies more memory it prints hi
>>
>>
>> On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal > > wrote:
>>
>>> the reason is dat 0.7 is treated as double..therefore double(0.7)
>>> >float(0.7)
>>>
>>> On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan 
>>> wrote:
>>>
 the output will be hi

 even if u have putted equal to sign there this is becoz 0.7 do not
 exactly stored like 0.7 in a but some thing lesser as describe in ASCII
 format
 that's why it is awlays lesser than 0.7

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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>
>
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COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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Re: [algogeeks] output???

[Rajesh Kumar]

Thanks to all

On Fri, Aug 5, 2011 at 8:53 PM, sukran dhawan wrote:

> coz by default all real values are converted to double and it is larger
> than float.ie real nos are not stored accurately inside computer memory.so
> since double occupies more memory it prints hi
>
>
> On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal 
> wrote:
>
>> the reason is dat 0.7 is treated as double..therefore double(0.7)
>> >float(0.7)
>>
>> On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan wrote:
>>
>>> the output will be hi
>>>
>>> even if u have putted equal to sign there this is becoz 0.7 do not
>>> exactly stored like 0.7 in a but some thing lesser as describe in ASCII
>>> format
>>> that's why it is awlays lesser than 0.7
>>>
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>>
>>
>>
>> --
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] output???

[sukran dhawan]

coz by default all real values are converted to double and it is larger than
float.ie real nos are not stored accurately inside computer memory.so
since double occupies more memory it prints hi

On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal wrote:

> the reason is dat 0.7 is treated as double..therefore double(0.7)
> >float(0.7)
>
> On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan wrote:
>
>> the output will be hi
>>
>> even if u have putted equal to sign there this is becoz 0.7 do not exactly
>> stored like 0.7 in a but some thing lesser as describe in ASCII format
>> that's why it is awlays lesser than 0.7
>>
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Re: [algogeeks] output???

[Kamakshii Aggarwal]

the reason is dat 0.7 is treated as double..therefore double(0.7)
>float(0.7)

On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan wrote:

> the output will be hi
>
> even if u have putted equal to sign there this is becoz 0.7 do not exactly
> stored like 0.7 in a but some thing lesser as describe in ASCII format
> that's why it is awlays lesser than 0.7
>
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Re: [algogeeks] output???

[bagaria.ka...@gmail.com]

.7 in float is taken like .699 i blv ?

On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan wrote:

> the output will be hi
>
> even if u have putted equal to sign there this is becoz 0.7 do not exactly
> stored like 0.7 in a but some thing lesser as describe in ASCII format
> that's why it is awlays lesser than 0.7
>
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*Karan Bagaria*
*MCA Final Year*
Training and Placement Representative
*NIT Durgapur*

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Re: [algogeeks] output???

[kartik sachan]

the output will be hi

even if u have putted equal to sign there this is becoz 0.7 do not exactly
stored like 0.7 in a but some thing lesser as describe in ASCII format
that's why it is awlays lesser than 0.7

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[algogeeks] output???

[Rajesh Kumar]

program output comes - hi
why??

#include
main()
{
float a=0.7;
if(.7> a)
printf("hi\n");
else
printf("hello\n");
}

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Re: [algogeeks] Output Help.

[gaurav gupta]

thanx kamakshi

On Sun, Jul 31, 2011 at 1:56 AM, Kamakshii Aggarwal
wrote:

> @gaurav:refer the link below
> http://c-faq.com/expr/seqpoints.html
>
>
> On Sun, Jul 31, 2011 at 1:53 AM, gaurav gupta wrote:
>
>> bt y it sud b undefind?
>>
>>
>> On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda 
>> wrote:
>>
>>> I dint get any error, not even warning. it might depend from compiler to
>>> compiler. but yeah it should be undefined.
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal <
>>> kamakshi...@gmail.com> wrote:
>>>
 @sanchit:it is undefined..


 On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda <
 sanchit...@gmail.com> wrote:

> I am getting b=2.
> Maybe coz we are assigning 2 to b then incrementing b. But still acc to
> me it should be 3.
> :-\
> No warnings in dev cpp.
>
>
>
> On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma 
> wrote:
>
>> yup it is undefined and the warning is justified
>> b=b++ will assign 2 to b then increment b hence 3 is printed
>>
>> --
>>
>>
>> Amol Sharma
>> Third Year Student
>> Computer Science and Engineering
>> MNNIT Allahabad
>>
>>
>>
>>
>> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta <
>> neeraj.gupta...@gmail.com> wrote:
>>
>>> Yes, it's UB.
>>> For such ques, try to run it on ideone.
>>> It will give a warning if any operation is not standard.
>>> http://ideone.com/bJBGl
>>>
>>>  
>>>
>>> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg <
>>> aditi.garg.6...@gmail.com> wrote:
>>>
 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
 kamakshi...@gmail.com> wrote:

> 3.it is same as b=b+1;
>
>
> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg 
> wrote:
>
>> int b=2;b=b++;
>> b=???
>>
>> Plz explain..
>> Aseem
>>
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> Kamakshi
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 --
 Aditi Garg
 Undergraduate Student
 Electronics & Communication Divison
 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
 New Delhi


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Re: [algogeeks] Output Help.

[Kamakshii Aggarwal]

@gaurav:refer the link below
http://c-faq.com/expr/seqpoints.html

On Sun, Jul 31, 2011 at 1:53 AM, gaurav gupta  wrote:

> bt y it sud b undefind?
>
>
> On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda 
> wrote:
>
>> I dint get any error, not even warning. it might depend from compiler to
>> compiler. but yeah it should be undefined.
>>
>>
>> On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>> @sanchit:it is undefined..
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda >> > wrote:
>>>
 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to
 me it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma wrote:

> yup it is undefined and the warning is justified
> b=b++ will assign 2 to b then increment b hence 3 is printed
>
> --
>
>
> Amol Sharma
> Third Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>
>
>
>
> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta <
> neeraj.gupta...@gmail.com> wrote:
>
>> Yes, it's UB.
>> For such ques, try to run it on ideone.
>> It will give a warning if any operation is not standard.
>> http://ideone.com/bJBGl
>>
>>  
>>
>> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg <
>> aditi.garg.6...@gmail.com> wrote:
>>
>>> it would be undefined...
>>>
>>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>>> kamakshi...@gmail.com> wrote:
>>>
 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:

> int b=2;b=b++;
> b=???
>
> Plz explain..
> Aseem
>
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 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>>
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 --
 Sanchit Manchanda
 COE(3rd year) , NSIT
 http://iblogmythots.wordpress.com/

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>>>
>>>
>>>
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>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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Re: [algogeeks] Output Help.

[gaurav gupta]

bt y it sud b undefind?

On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda wrote:

> I dint get any error, not even warning. it might depend from compiler to
> compiler. but yeah it should be undefined.
>
>
> On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal  > wrote:
>
>> @sanchit:it is undefined..
>>
>>
>> On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda 
>> wrote:
>>
>>> I am getting b=2.
>>> Maybe coz we are assigning 2 to b then incrementing b. But still acc to
>>> me it should be 3.
>>> :-\
>>> No warnings in dev cpp.
>>>
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma wrote:
>>>
 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta <
 neeraj.gupta...@gmail.com> wrote:

> Yes, it's UB.
> For such ques, try to run it on ideone.
> It will give a warning if any operation is not standard.
> http://ideone.com/bJBGl
>
>  
>
> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg  > wrote:
>
>> it would be undefined...
>>
>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>> 3.it is same as b=b+1;
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:
>>>
 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
>>
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>>>
>>>
>>>
>>> --
>>> Sanchit Manchanda
>>> COE(3rd year) , NSIT
>>> http://iblogmythots.wordpress.com/
>>>
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>>
>>
>>
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] Output Help.

[Sanchit Manchanda]

I dint get any error, not even warning. it might depend from compiler to
compiler. but yeah it should be undefined.

On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal
wrote:

> @sanchit:it is undefined..
>
>
> On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda 
> wrote:
>
>> I am getting b=2.
>> Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
>> it should be 3.
>> :-\
>> No warnings in dev cpp.
>>
>>
>>
>> On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma wrote:
>>
>>> yup it is undefined and the warning is justified
>>> b=b++ will assign 2 to b then increment b hence 3 is printed
>>>
>>> --
>>>
>>>
>>> Amol Sharma
>>> Third Year Student
>>> Computer Science and Engineering
>>> MNNIT Allahabad
>>>
>>>
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta >> > wrote:
>>>
 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
 wrote:

> it would be undefined...
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
> kamakshi...@gmail.com> wrote:
>
>> 3.it is same as b=b+1;
>>
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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>>
>>
>>
>> --
>> Sanchit Manchanda
>> COE(3rd year) , NSIT
>> http://iblogmythots.wordpress.com/
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> kamakshi...@gmail.com
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Re: [algogeeks] Output Help.

[Kamakshii Aggarwal]

@sanchit:it is undefined..

On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda wrote:

> I am getting b=2.
> Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
> it should be 3.
> :-\
> No warnings in dev cpp.
>
>
>
> On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma wrote:
>
>> yup it is undefined and the warning is justified
>> b=b++ will assign 2 to b then increment b hence 3 is printed
>>
>> --
>>
>>
>> Amol Sharma
>> Third Year Student
>> Computer Science and Engineering
>> MNNIT Allahabad
>>
>>
>>
>>
>> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
>> wrote:
>>
>>> Yes, it's UB.
>>> For such ques, try to run it on ideone.
>>> It will give a warning if any operation is not standard.
>>> http://ideone.com/bJBGl
>>>
>>>  
>>>
>>> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
>>> wrote:
>>>
 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
 kamakshi...@gmail.com> wrote:

> 3.it is same as b=b+1;
>
>
> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:
>
>> int b=2;b=b++;
>> b=???
>>
>> Plz explain..
>> Aseem
>>
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>
>
>
> --
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> Kamakshi
> kamakshi...@gmail.com
>
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 --
 Aditi Garg
 Undergraduate Student
 Electronics & Communication Divison
 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
 New Delhi


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Re: [algogeeks] Output Help.

[Sanchit Manchanda]

I am getting b=2.
Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
it should be 3.
:-\
No warnings in dev cpp.


On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma  wrote:

> yup it is undefined and the warning is justified
> b=b++ will assign 2 to b then increment b hence 3 is printed
>
> --
>
>
> Amol Sharma
> Third Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>
>
>
>
> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
> wrote:
>
>> Yes, it's UB.
>> For such ques, try to run it on ideone.
>> It will give a warning if any operation is not standard.
>> http://ideone.com/bJBGl
>>
>>  
>>
>> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:
>>
>>> it would be undefined...
>>>
>>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>>> kamakshi...@gmail.com> wrote:
>>>
 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:

> int b=2;b=b++;
> b=???
>
> Plz explain..
> Aseem
>
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 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>>
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Re: [algogeeks] Output Help.

[Amol Sharma]

yup it is undefined and the warning is justified
b=b++ will assign 2 to b then increment b hence 3 is printed
--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta wrote:

> Yes, it's UB.
> For such ques, try to run it on ideone.
> It will give a warning if any operation is not standard.
> http://ideone.com/bJBGl
>
>  
>
> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:
>
>> it would be undefined...
>>
>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>> 3.it is same as b=b+1;
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>>
 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
>>
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Re: [algogeeks] Output Help.

[aseem garg]

On Dev CPP.
Aseem



On Sun, Jul 31, 2011 at 1:42 AM, aseem garg  wrote:

> I am getting 2. >.<
> Aseem
>
>
>
> On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
> wrote:
>
>> Yes, it's UB.
>> For such ques, try to run it on ideone.
>> It will give a warning if any operation is not standard.
>> http://ideone.com/bJBGl
>>
>>  
>>
>> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:
>>
>>> it would be undefined...
>>>
>>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>>> kamakshi...@gmail.com> wrote:
>>>
 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg wrote:

> int b=2;b=b++;
> b=???
>
> Plz explain..
> Aseem
>
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 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>>
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Re: [algogeeks] Output Help.

[aseem garg]

I am getting 2. >.<
Aseem



On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta wrote:

> Yes, it's UB.
> For such ques, try to run it on ideone.
> It will give a warning if any operation is not standard.
> http://ideone.com/bJBGl
>
>  
>
> On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:
>
>> it would be undefined...
>>
>> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>> 3.it is same as b=b+1;
>>>
>>>
>>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>>
 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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>>>
>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
>>
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Re: [algogeeks] Output Help.

[Neeraj Gupta]

Yes, it's UB.
For such ques, try to run it on ideone.
It will give a warning if any operation is not standard.
http://ideone.com/bJBGl

 

On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:

> it would be undefined...
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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Re: [algogeeks] Output Help.

[vidushi]

@aseem its 3
different on yours ?

On Sun, Jul 31, 2011 at 1:37 AM, aseem garg  wrote:

> @Kamakshi: Run karke dekh leti pehle.  :-/
> Aseem
>
>
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] Output Help.

[Amol Sharma]

@aseem output is 3 only...check it once again

http://ideone.com/mWGc5

--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Sun, Jul 31, 2011 at 1:37 AM, aseem garg  wrote:

> @Kamakshi: Run karke dekh leti pehle.  :-/
> Aseem
>
>
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] Output Help.

[vaibhav shukla]

concept of sequence points.search wiki

On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:

> it would be undefined...
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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>
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  best wishes!!
Vaibhav
  MCA

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Re: [algogeeks] Output Help.

[aseem garg]

@Aditi: Run karke dekh leti pehle.  :-/
Aseem



On Sun, Jul 31, 2011 at 1:38 AM, aditi garg wrote:

> it would be undefined...
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
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>
>
>
> --
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> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
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> New Delhi
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Re: [algogeeks] Output Help.

[Kamakshii Aggarwal]

oh sorry,mane galat pad lia..mane sirf b++ dekha...
it is compiler dependent.value of b is changing twice b/w two serial points

On Sun, Jul 31, 2011 at 1:37 AM, aseem garg  wrote:

> @Kamakshi: Run karke dekh leti pehle.  :-/
> Aseem
>
>
>
> On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal  > wrote:
>
>> 3.it is same as b=b+1;
>>
>> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>>
>>> int b=2;b=b++;
>>> b=???
>>>
>>> Plz explain..
>>> Aseem
>>>
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>>
>>
>>
>> --
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>> Kamakshi
>> kamakshi...@gmail.com
>>
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Re: [algogeeks] Output Help.

[aditi garg]

it would be undefined...

On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal
wrote:

> 3.it is same as b=b+1;
>
>
> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>
>> int b=2;b=b++;
>> b=???
>>
>> Plz explain..
>> Aseem
>>
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>
>
>
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> Kamakshi
> kamakshi...@gmail.com
>
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-- 
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] Output Help.

[aseem garg]

@Kamakshi: Run karke dekh leti pehle.  :-/
Aseem



On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal
wrote:

> 3.it is same as b=b+1;
>
> On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:
>
>> int b=2;b=b++;
>> b=???
>>
>> Plz explain..
>> Aseem
>>
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>
>
>
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> Kamakshi
> kamakshi...@gmail.com
>
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Re: [algogeeks] Output Help.

[Kamakshii Aggarwal]

3.it is same as b=b+1;

On Sun, Jul 31, 2011 at 1:32 AM, aseem garg  wrote:

> int b=2;b=b++;
> b=???
>
> Plz explain..
> Aseem
>
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Kamakshi
kamakshi...@gmail.com

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[algogeeks] Output Help.

[aseem garg]

int b=2;b=b++;
b=???

Plz explain..
Aseem

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Re: [algogeeks] OUTPUT PROBLEM

[kartik sachan]

*@AMOL *sending a normal pointer to a const pointer doesn't give any warning



why this is giving??

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Re: [algogeeks] OUTPUT PROBLEM

[Amol Sharma]

the warning comes is as

warning: passing argument 1 of ‘foo’ from incompatible pointer type


foo expects a constant char** but it is not the case...hence warning is
displayed...

remove the const keyword.you'll see no warning !!

--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Sat, Jul 30, 2011 at 5:30 PM, kartik sachan wrote:

>
> #include 
>   void foo(const char **p) { }
>   int main(int argc, char **argv)
>   {
>   foo(argv);
>   return 0;
>   }
>
> why the above code giving me warning can body explain me??
>
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[algogeeks] OUTPUT PROBLEM

[kartik sachan]

#include 
  void foo(const char **p) { }
  int main(int argc, char **argv)
  {
  foo(argv);
  return 0;
  }

why the above code giving me warning can body explain me??

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Re: [algogeeks] output

[Kamakshii Aggarwal]

@piyush:thanks...i got my mistake

On Wed, Jul 27, 2011 at 7:30 PM, Piyush Sinha wrote:

> char const *s and const char *s are both same...try using char *const s..it
> will give error then
>
>
> On Wed, Jul 27, 2011 at 7:21 PM, Kamakshii Aggarwal  > wrote:
>
>> @magesh:so acc to you the code below should give error?
>> #include
>>
>> int main(int argc,char *argv[])
>> {
>>   char const *s="";
>>  char str[]="hello";
>>  s=str;
>>  while(*s){
>>printf("%c",*s++);
>>}
>>
>>  system("pause");
>>
>>   return 0;
>> }
>>
>>
>> On Wed, Jul 27, 2011 at 7:12 PM,  wrote:
>>
>>> ** Its not a const pointer. It is pointer to constant. So only modifying
>>> the value of s will cause error. For constant to pointer the const has to be
>>> between * and the keyword
>>>
>>> Sent from BlackBerry® on Airtel
>>> --
>>> *From: * Kamakshii Aggarwal 
>>> *Sender: * algogeeks@googlegroups.com
>>> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
>>> *To: *
>>> *ReplyTo: * algogeeks@googlegroups.com
>>> *Subject: *[algogeeks] output
>>>
>>> #include
>>>
>>> int main(int argc,char *argv[])
>>> {
>>>  const char *s="";
>>>  char str[]="hello";
>>>  s=str;
>>>  while(*s){
>>>printf("%c",*s++);
>>>}
>>>
>>>  system("pause");
>>>
>>>   return 0;
>>> }
>>> o/p is hello.
>>> why the above code is running normally even when constant char pointer is
>>> being incremented...??plss help...
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
>>> --
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>>
>>
>>
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
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>
>
>
> --
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> *IIIT, Allahabad*
> *+91-7483122727*
> * <https://www.facebook.com/profile.php?id=10655377926> "NEVER SAY
> NEVER"
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kamakshi...@gmail.com

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Re: [algogeeks] output

[mageshthegreat]

Sorry between * and the variable name.
Sent from BlackBerry® on Airtel

-Original Message-
From: Kamakshii Aggarwal 
Sender: algogeeks@googlegroups.com
Date: Wed, 27 Jul 2011 19:21:13 
To: 
Reply-To: algogeeks@googlegroups.com
Subject: Re: [algogeeks] output

@magesh:so acc to you the code below should give error?
#include

int main(int argc,char *argv[])
{
  char const *s="";
 char str[]="hello";
 s=str;
 while(*s){
   printf("%c",*s++);
   }

 system("pause");

  return 0;
}


On Wed, Jul 27, 2011 at 7:12 PM,  wrote:

> ** Its not a const pointer. It is pointer to constant. So only modifying
> the value of s will cause error. For constant to pointer the const has to be
> between * and the keyword
>
> Sent from BlackBerry® on Airtel
> --
> *From: * Kamakshii Aggarwal 
> *Sender: * algogeeks@googlegroups.com
> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
> *To: *
> *ReplyTo: * algogeeks@googlegroups.com
> *Subject: *[algogeeks] output
>
> #include
>
> int main(int argc,char *argv[])
> {
>  const char *s="";
>  char str[]="hello";
>  s=str;
>  while(*s){
>printf("%c",*s++);
>}
>
>  system("pause");
>
>   return 0;
> }
> o/p is hello.
> why the above code is running normally even when constant char pointer is
> being incremented...??plss help...
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>
> --
> You received this message because you are subscribed to the Google Groups
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Re: [algogeeks] output

[Piyush Sinha]

char const *s and const char *s are both same...try using char *const s..it
will give error then

On Wed, Jul 27, 2011 at 7:21 PM, Kamakshii Aggarwal
wrote:

> @magesh:so acc to you the code below should give error?
> #include
>
> int main(int argc,char *argv[])
> {
>   char const *s="";
>  char str[]="hello";
>  s=str;
>  while(*s){
>printf("%c",*s++);
>}
>
>  system("pause");
>
>   return 0;
> }
>
>
> On Wed, Jul 27, 2011 at 7:12 PM,  wrote:
>
>> ** Its not a const pointer. It is pointer to constant. So only modifying
>> the value of s will cause error. For constant to pointer the const has to be
>> between * and the keyword
>>
>> Sent from BlackBerry® on Airtel
>> --
>> *From: * Kamakshii Aggarwal 
>> *Sender: * algogeeks@googlegroups.com
>> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
>> *To: *
>> *ReplyTo: * algogeeks@googlegroups.com
>> *Subject: *[algogeeks] output
>>
>> #include
>>
>> int main(int argc,char *argv[])
>> {
>>  const char *s="";
>>  char str[]="hello";
>>  s=str;
>>  while(*s){
>>printf("%c",*s++);
>>}
>>
>>  system("pause");
>>
>>   return 0;
>> }
>> o/p is hello.
>> why the above code is running normally even when constant char pointer is
>> being incremented...??plss help...
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
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>
>
>
> --
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> Kamakshi
> kamakshi...@gmail.com
>
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Re: [algogeeks] output

[Kamakshii Aggarwal]

@magesh:so acc to you the code below should give error?
#include

int main(int argc,char *argv[])
{
  char const *s="";
 char str[]="hello";
 s=str;
 while(*s){
   printf("%c",*s++);
   }

 system("pause");

  return 0;
}


On Wed, Jul 27, 2011 at 7:12 PM,  wrote:

> ** Its not a const pointer. It is pointer to constant. So only modifying
> the value of s will cause error. For constant to pointer the const has to be
> between * and the keyword
>
> Sent from BlackBerry® on Airtel
> --
> *From: * Kamakshii Aggarwal 
> *Sender: * algogeeks@googlegroups.com
> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
> *To: *
> *ReplyTo: * algogeeks@googlegroups.com
> *Subject: *[algogeeks] output
>
> #include
>
> int main(int argc,char *argv[])
> {
>  const char *s="";
>  char str[]="hello";
>  s=str;
>  while(*s){
>printf("%c",*s++);
>}
>
>  system("pause");
>
>   return 0;
> }
> o/p is hello.
> why the above code is running normally even when constant char pointer is
> being incremented...??plss help...
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>
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Regards,
Kamakshi
kamakshi...@gmail.com

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Re: [algogeeks] output

[mageshthegreat]

Its not a const pointer. It is pointer to constant. So only modifying the value 
of s will cause error. For constant to pointer the const has to be between * 
and the keyword
Sent from BlackBerry® on Airtel

-Original Message-
From: Kamakshii Aggarwal 
Sender: algogeeks@googlegroups.com
Date: Wed, 27 Jul 2011 19:09:20 
To: 
Reply-To: algogeeks@googlegroups.com
Subject: [algogeeks] output

#include

int main(int argc,char *argv[])
{
 const char *s="";
 char str[]="hello";
 s=str;
 while(*s){
   printf("%c",*s++);
   }

 system("pause");

  return 0;
}
o/p is hello.
why the above code is running normally even when constant char pointer is
being incremented...??plss help...
-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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[algogeeks] output

[Kamakshii Aggarwal]

#include

int main(int argc,char *argv[])
{
 const char *s="";
 char str[]="hello";
 s=str;
 while(*s){
   printf("%c",*s++);
   }

 system("pause");

  return 0;
}
o/p is hello.
why the above code is running normally even when constant char pointer is
being incremented...??plss help...
-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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Re: [algogeeks] OUTPUT

[ramya reddy]

The system on which u executed this will allocate 4 bytes for int type.
hence sizeof(p) gives 4 bytes and sizeof(*p) will contain 4 such integer
pointers( int *p[4] is the declaration)  which gives 4*4=16 bytes


Regards
Ramya

*Try to learn something about everything and everything about something*

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[algogeeks] OUTPUT

[Kamakshii Aggarwal]

#include
# define MAXROW 3
#define MAXCOL 4


int main()
{
int (*p)[MAXCOL];
p=(int(*)[MAXCOL])malloc(MAXROW*sizeof(*p));
printf("%d %d",sizeof(p),sizeof(*p));

 system("pause");

  return 0;
}

THE O/P IS 4 16.
I am not getting the reason.plss help

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Re: [algogeeks] OUTPUT

[kavitha nk]

sry sry o/p ll be 0 1 0in the 2nd printf the value ll be evaluated
from rite to left...
so in the 1st printf i's vlue ll be 0 and in the 2nd printf stmt rite
expression is evaluated first and then i value ll be modified in it..
and with hte help of it left one is evaluated...crct me if i'm
wrong..

On 7/26/11, kavitha nk  wrote:
> ans ll nt be 0 0 2 va???
>
> On 7/25/11, Puneet Gautam  wrote:
>> @aditi: the "%2" in each of these printf statements is redundant coz
>> it is "1%2"...and "%" has higher precedence over left or right
>> shifts..thats y output of say :
>>
>> #include
>> main()
>> {
>> int i=1;
>> printf("\n%d%d ",i<<=2,i<<=1%2);
>> return 0;
>> }
>>
>> is 8 8
>>
>> 1 gets left shifted twice in i<<=2, becomes 4
>> then i<<1%2 concludes to i<<1 as 1%2 is 1 only..
>> i<<1 ,makes i=8 and hence
>>
>> 8 8 is printed.
>>
>> On 7/25/11, Puneet Gautam  wrote:
>>> @rajeev: hey...does printf evaluate an expression right to left
>>> without considering any priority of operators..?
>>> Pls reply asap..
>>>
>>>
>>>
>>> On 7/25/11, Puneet Gautam  wrote:
 @aditi: y dont u try it out urself considering the priorities of
 different operators used here...!!
 that would help...

 On 7/25/11, aditi garg  wrote:
> Can u plz elaborate...im not able to understand...
>
> On Mon, Jul 25, 2011 at 11:04 PM, rajeev bharshetty
> wrote:
>
>> @sameer I think that is right
>>
>>
>> On Mon, Jul 25, 2011 at 11:02 PM, sameer.mut...@gmail.com <
>> sameer.mut...@gmail.com> wrote:
>>
>>> its because of side effect where value of i is getting changed twice
>>> in
>>> a
>>> single line.
>>> correct me if i am wrong :)
>>>
>>> *Muthuraj R.
>>> 4TH Year BE.**
>>> Information Science Dept*
>>> *PESIT, Bengaluru .
>>> *
>>>
>>>
>>>
>>>
>>> On Mon, Jul 25, 2011 at 11:01 PM, geek forgeek
>>> wrote:
>>>
 y not the output is 3 2  coz on right to left evaluation  of printf
 i
 shud be left shifted by 1 bit wgich shud make it 2 ??


 On Mon, Jul 25, 2011 at 10:28 AM, sameer.mut...@gmail.com <
 sameer.mut...@gmail.com> wrote:

> yeah output
>  0
> 1 1
> *is dis because of side effect? *
> * *
> *
> *
> *Muthuraj R.
> 4TH Year BE.**
> Information Science Dept*
> *PESIT, Bengaluru .
> *
>
>
>
>
>
> On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan
> wrote:
>
>> run on gcc compiler it would be
>> 0
>> 1 1
>>
>>
>> On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek
>> wrote:
>>
>>> 1.
>>> #include
>>> main()
>>> {
>>> int i=1;
>>>  printf("\n%d",i^=1%2);
>>>  printf("\n%d %d",i^=1%2,i<<=1%2);
>>> return 0;
>>> }
>>>
>>> output 3 3
>>> hey shudnt the output be 3 2
>>>
>>>
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>>
>>
>>
>> --
>> **With Regards
>> Deoki Nandan Vishwakarma
>>
>> *
>> *
>>
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