[algogeeks] Implement a queue in which push_rear(), pop_front() and get_min() are all constant time operations.
Implement a queue in which push_rear(), pop_front() and get_min() are all constant time operations. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@Dave, Yeah, I had read those numbers on internet as this puzzle is well known. However I am not convinced with the calculations because of following 2 points: 1) If C shoots in air, the probability of survival is more for the probabilities considered in the calculations with which A & B will shoot at him. Now, if A & B are intelligent, they will know that increasing survival probability for C is bad for them (you can calculate survival probability for A & B in each case), and therefore they will shoot at C with higher probability than what they were planning earlier. 2) C's survival probability depends on P(A shooting at C) * 1 and P(B shooting at C) * 1/2. If C shoots at A, P(A shooting at C) is less by 33% and P(B shooting at C) is more by 33%. So, if P(A shooting at C) dominates by logic in 1st point, C's survival probability will be now more. On Sun, Jan 2, 2011 at 7:59 AM, Dave wrote: > @Salil: Working out the probabilities, we find that: > > 1. If C initially shoots at A, C's probability of survival is ~ > 0.35867. > 2. If C initially shoots at B, C's probability of survival is ~ > 0.27679. > 3. If C initially shoots in the air, C's probability of survival is ~ > 0.49624. > > Dave > > On Jan 1, 11:30 am, Salil Joshi wrote: > > @Rahul, > > As per my understanding, > > In any round P(C is dead) = P(A is alive * A shoots C * A's shot is > > accurate) + P(B is alive * B shoots C * B's shot is accurate) > > this is to be minimized. > > by not shooting at either A or B in 1st chance, how is this probability > less > > for C? > > > > On Sat, Jan 1, 2011 at 10:43 PM, Salil Joshi >wrote: > > > > > > > > > > > > > @Rahul, > > > What purpose is served by wasting the shot? If C shoots at A or B, at > least > > > some probability that C is dead in future will be reduced. > > > > > On Sat, Jan 1, 2011 at 10:14 PM, RAHUL KUJUR < > kujurismonu2...@gmail.com>wrote: > > > > >> @snehal: > > >> will the shooting take place in increasing order of accuracy of > hitting > > >> the target and is that at a time only one person can take a shot??? > > >> if yes then > > >> @Salil: > > >> my answer would be the same as above. what C will do is that it will > first > > >> let A and B kill each other first. > > >> After C wastes his shot it will be B's turn. B can kill C, but in that > > >> case the turn would go to A and he would surely kill B. If B goes > after A, > > >> then B may hit it or miss it(as its probability of hitting is 50%) > > >> If B misses it > > >> then > > >> it depends on A whom to kill. A may kill B or C. A will try to kill > one > > >> who is better shooter i.e. B as C is less likely to hit A. > > >> If B hits A then we are done. Round 1 is complete(as required in the > > >> question) and C survives the first round. > > >> Look the problem is not that who gets killed at last but rather what C > > >> should fire in the first round obviously to survive(as I understood > the > > >> problem). It may happen that eventually C gets killed. But what should > C > > >> shoot in first round to survive. > > > > >> -- > > >> You received this message because you are subscribed to the Google > Groups > > >> "Algorithm Geeks" group. > > >> To post to this group, send email to algoge...@googlegroups.com. > > >> To unsubscribe from this group, send email to > > >> algogeeks+unsubscr...@googlegroups.com > > > >> . > > >> For more options, visit this group at > > >>http://groups.google.com/group/algogeeks?hl=en. > > > > > -- > > > > > > > > Thanks & Regards > > > Salil Joshi. > > > CSE MTech II, IITB > > > A-414, Hostel 12 > > > +91.9819.442.865 > > > > > This is a confidential E-Mail. If it has reached you by mistake or if > you > > > are not the intended receiver, please send it back to me. > > > > -- > > > > > > Thanks & Regards > > Salil Joshi. > > CSE MTech II, IITB > > A-414, Hostel 12 > > +91.9819.442.865 > > > > This is a confidential E-Mail. If it has reached you by mistake or if you > > are not the intended receiver, please send it back to me.- Hide quoted > text - > > > > - Show quoted text - > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.goog
Re: [algogeeks] Re: Float Comparison
we use epsilon in that case as the float values are not exact there is an approximation. On 1/2/11, Anuj Kumar wrote: > he means == > > On 1/2/11, Dave wrote: >> @Saunsh: Why do you say that we cannot use < or > on floats? Of course >> we can! >> >> Dave >> >> On Jan 1, 3:06 pm, saunsh wrote: >>> how to compare two float variables for equality as wel as for which of >>> dem has greater value >>> as we know we can not use < n > operators on float >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algoge...@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > Anuj Kumar > Third Year Undergraduate, > Dept. of Computer Science and Engineering > NIT Durgapur > -- Anuj Kumar Third Year Undergraduate, Dept. of Computer Science and Engineering NIT Durgapur -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Float Comparison
he means == On 1/2/11, Dave wrote: > @Saunsh: Why do you say that we cannot use < or > on floats? Of course > we can! > > Dave > > On Jan 1, 3:06 pm, saunsh wrote: >> how to compare two float variables for equality as wel as for which of >> dem has greater value >> as we know we can not use < n > operators on float > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Anuj Kumar Third Year Undergraduate, Dept. of Computer Science and Engineering NIT Durgapur -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Float Comparison
@Saunsh: Why do you say that we cannot use < or > on floats? Of course we can! Dave On Jan 1, 3:06 pm, saunsh wrote: > how to compare two float variables for equality as wel as for which of > dem has greater value > as we know we can not use < n > operators on float -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: probability
@Salil: Working out the probabilities, we find that: 1. If C initially shoots at A, C's probability of survival is ~ 0.35867. 2. If C initially shoots at B, C's probability of survival is ~ 0.27679. 3. If C initially shoots in the air, C's probability of survival is ~ 0.49624. Dave On Jan 1, 11:30 am, Salil Joshi wrote: > @Rahul, > As per my understanding, > In any round P(C is dead) = P(A is alive * A shoots C * A's shot is > accurate) + P(B is alive * B shoots C * B's shot is accurate) > this is to be minimized. > by not shooting at either A or B in 1st chance, how is this probability less > for C? > > On Sat, Jan 1, 2011 at 10:43 PM, Salil Joshi wrote: > > > > > > > @Rahul, > > What purpose is served by wasting the shot? If C shoots at A or B, at least > > some probability that C is dead in future will be reduced. > > > On Sat, Jan 1, 2011 at 10:14 PM, RAHUL KUJUR > > wrote: > > >> @snehal: > >> will the shooting take place in increasing order of accuracy of hitting > >> the target and is that at a time only one person can take a shot??? > >> if yes then > >> @Salil: > >> my answer would be the same as above. what C will do is that it will first > >> let A and B kill each other first. > >> After C wastes his shot it will be B's turn. B can kill C, but in that > >> case the turn would go to A and he would surely kill B. If B goes after A, > >> then B may hit it or miss it(as its probability of hitting is 50%) > >> If B misses it > >> then > >> it depends on A whom to kill. A may kill B or C. A will try to kill one > >> who is better shooter i.e. B as C is less likely to hit A. > >> If B hits A then we are done. Round 1 is complete(as required in the > >> question) and C survives the first round. > >> Look the problem is not that who gets killed at last but rather what C > >> should fire in the first round obviously to survive(as I understood the > >> problem). It may happen that eventually C gets killed. But what should C > >> shoot in first round to survive. > > >> -- > >> You received this message because you are subscribed to the Google Groups > >> "Algorithm Geeks" group. > >> To post to this group, send email to algoge...@googlegroups.com. > >> To unsubscribe from this group, send email to > >> algogeeks+unsubscr...@googlegroups.com > >> . > >> For more options, visit this group at > >>http://groups.google.com/group/algogeeks?hl=en. > > > -- > > > > > Thanks & Regards > > Salil Joshi. > > CSE MTech II, IITB > > A-414, Hostel 12 > > +91.9819.442.865 > > > This is a confidential E-Mail. If it has reached you by mistake or if you > > are not the intended receiver, please send it back to me. > > -- > > > Thanks & Regards > Salil Joshi. > CSE MTech II, IITB > A-414, Hostel 12 > +91.9819.442.865 > > This is a confidential E-Mail. If it has reached you by mistake or if you > are not the intended receiver, please send it back to me.- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Plz Explain The Output.
2.
#include
using namespace std;
int main(){
int n = 255, i;
char *p = (char *)&n;
for(i = 0; i < sizeof(int); i++)
cout<<(unsigned int)p[i]<<"\n";
cin.get();
return 0;
}
Output:
4294967295
0
0
0
I think p[0] is .So why it is giving 4294967295 in the first line.
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[algogeeks] Plz Explain The Output.
# include
#include
#define concatinate(a,b) a##b
#define same1(a) #a
#define same2(a) same1(a)
int main(){
printf("%s\n",same2(concatinate(1,2)));
printf("%s\n",same1(concatinate(1,2)));
getch();
return 0;
}
Output is:
12
concatinate(1,2)
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[algogeeks] Float Comparison
how to compare two float variables for equality as wel as for which of dem has greater value as we know we can not use < n > operators on float -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: arrays
You mentioned EXPECTED time, not the worst case. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@Rahul, As per my understanding, In any round P(C is dead) = P(A is alive * A shoots C * A's shot is accurate) + P(B is alive * B shoots C * B's shot is accurate) this is to be minimized. by not shooting at either A or B in 1st chance, how is this probability less for C? On Sat, Jan 1, 2011 at 10:43 PM, Salil Joshi wrote: > @Rahul, > What purpose is served by wasting the shot? If C shoots at A or B, at least > some probability that C is dead in future will be reduced. > > > > On Sat, Jan 1, 2011 at 10:14 PM, RAHUL KUJUR wrote: > >> @snehal: >> will the shooting take place in increasing order of accuracy of hitting >> the target and is that at a time only one person can take a shot??? >> if yes then >> @Salil: >> my answer would be the same as above. what C will do is that it will first >> let A and B kill each other first. >> After C wastes his shot it will be B's turn. B can kill C, but in that >> case the turn would go to A and he would surely kill B. If B goes after A, >> then B may hit it or miss it(as its probability of hitting is 50%) >> If B misses it >> then >> it depends on A whom to kill. A may kill B or C. A will try to kill one >> who is better shooter i.e. B as C is less likely to hit A. >> If B hits A then we are done. Round 1 is complete(as required in the >> question) and C survives the first round. >> Look the problem is not that who gets killed at last but rather what C >> should fire in the first round obviously to survive(as I understood the >> problem). It may happen that eventually C gets killed. But what should C >> shoot in first round to survive. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algoge...@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > > > Thanks & Regards > Salil Joshi. > CSE MTech II, IITB > A-414, Hostel 12 > +91.9819.442.865 > > > This is a confidential E-Mail. If it has reached you by mistake or if you > are not the intended receiver, please send it back to me. > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] arrays
yes O(n) solution posible..
1. traverse the first array..
2. for(i=1;i<=n;i++)
{ X[a[i]] = i ;
}
3. print array X[];
On Sat, Jan 1, 2011 at 10:42 PM, Soumya Prasad Ukil
wrote:
> Is the second array really required, assuming intersection of both A & B is
> equal to either A or B?
>
> How about X[a[i]] = i?
>
>
> On 27 December 2010 21:24, Anand wrote:
>
>> I have a two arrays
>>
>> One is
>>
>> 2 5 1 6 4 3
>>
>> other is
>>
>> 1 2 3 4 5 6.
>>
>> I want to make an array X which gives the index of its element on other
>> arrays.
>>
>> Meaning X[1] = 3 1 is element of the second array and 3 is the index of
>> element 1 in first array.
>>
>> How shall we get array X in O(nlogn).
>>
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>> .
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>>
>
>
>
> --
> regards,
> soumya prasad ukil
>
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Re: [algogeeks] Re: probability
@Rahul, What purpose is served by wasting the shot? If C shoots at A or B, at least some probability that C is dead in future will be reduced. On Sat, Jan 1, 2011 at 10:14 PM, RAHUL KUJUR wrote: > @snehal: > will the shooting take place in increasing order of accuracy of hitting the > target and is that at a time only one person can take a shot??? > if yes then > @Salil: > my answer would be the same as above. what C will do is that it will first > let A and B kill each other first. > After C wastes his shot it will be B's turn. B can kill C, but in that case > the turn would go to A and he would surely kill B. If B goes after A, then B > may hit it or miss it(as its probability of hitting is 50%) > If B misses it > then > it depends on A whom to kill. A may kill B or C. A will try to kill one who > is better shooter i.e. B as C is less likely to hit A. > If B hits A then we are done. Round 1 is complete(as required in the > question) and C survives the first round. > Look the problem is not that who gets killed at last but rather what C > should fire in the first round obviously to survive(as I understood the > problem). It may happen that eventually C gets killed. But what should C > shoot in first round to survive. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] arrays
Is the second array really required, assuming intersection of both A & B is equal to either A or B? How about X[a[i]] = i? On 27 December 2010 21:24, Anand wrote: > I have a two arrays > > One is > > 2 5 1 6 4 3 > > other is > > 1 2 3 4 5 6. > > I want to make an array X which gives the index of its element on other > arrays. > > Meaning X[1] = 3 1 is element of the second array and 3 is the index of > element 1 in first array. > > How shall we get array X in O(nlogn). > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- regards, soumya prasad ukil -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@snehal: will the shooting take place in increasing order of accuracy of hitting the target and is that at a time only one person can take a shot??? if yes then @Salil: my answer would be the same as above. what C will do is that it will first let A and B kill each other first. After C wastes his shot it will be B's turn. B can kill C, but in that case the turn would go to A and he would surely kill B. If B goes after A, then B may hit it or miss it(as its probability of hitting is 50%) If B misses it then it depends on A whom to kill. A may kill B or C. A will try to kill one who is better shooter i.e. B as C is less likely to hit A. If B hits A then we are done. Round 1 is complete(as required in the question) and C survives the first round. Look the problem is not that who gets killed at last but rather what C should fire in the first round obviously to survive(as I understood the problem). It may happen that eventually C gets killed. But what should C shoot in first round to survive. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@Rahul: We (Dave and me) saw your reply as joke ... it doesn't make any sense seriously speaking. Even if C wastes his shot, A and B can still shoot him... by wasting it, C will be in loss. On Sat, Jan 1, 2011 at 8:49 PM, RAHUL KUJUR wrote: > @Dave: first of all "By shooting in air" I meant that C will not fire any > one. That was my figure of speech:)) > He will simply waste his shot. > @Salil: its a duel. everyone will get chance to shoot in each round > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@Dave: first of all "By shooting in air" I meant that C will not fire any one. That was my figure of speech:)) He will simply waste his shot. @Salil: its a duel. everyone will get chance to shoot in each round -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
well, since it is not mentioned that everyone gets to shoot only once, C can keep shooting A & B until both are dead... case solved :-)) On Sat, Jan 1, 2011 at 8:29 PM, Dave wrote: > @Rahul: If shooter C shoots into the air, doesn't he still have only a > 33% chance of hitting it? If so, then he would have a 67% chance of > hitting B or C, or, I suppose, himself. :-) > > This brings up another alternative. In round 1 he shoots himself in > the foot. If he is successful (33% of the time), he is certain to > survive the duel because he is out as soon as he is hit. If he is > unsuccessful (67% of the time), the result is the same as if he had > shot into the air, i.e., he survives with probability 66/133 ~= > 0.49624. Putting this all together, by shooting himself in the foot, > his probability of survival increases to about 0.66248. :-) > > Dave > > On Jan 1, 6:58 am, RAHUL KUJUR wrote: > > Suppose three gunmen are A, B, and C who have a probability of 100%, 50% > and > > 33% respectively. The shooting will start from C, then B and at last A. > > Now there are several possibilities for C. If C shoots B, then A would > shoot > > C with an accuracy of 100% or in other case if C shoots A, then B would > > shoot him with an accuracy of 50%. So he has a probability of getting > > killed. We can see in either of the cases C will die. > > So what C will do in first round is that it will fire the shot in air. > Now > > the scenario gets interesting. By doing this C has turned the battle > among > > three people into two people A and B. This will increase the chances of > > survival of C. So now its B's turn of firing. So he can fire at either A > or > > C. If B fires at C, then A will shoot B with an accuracy of 100% and B > knows > > that he will surely die so B won't do that. If B shoots A, then C will > shoot > > B. > > I think this is the solution. Please point out if there are any > loopholes. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: probability
@Rahul: If shooter C shoots into the air, doesn't he still have only a 33% chance of hitting it? If so, then he would have a 67% chance of hitting B or C, or, I suppose, himself. :-) This brings up another alternative. In round 1 he shoots himself in the foot. If he is successful (33% of the time), he is certain to survive the duel because he is out as soon as he is hit. If he is unsuccessful (67% of the time), the result is the same as if he had shot into the air, i.e., he survives with probability 66/133 ~= 0.49624. Putting this all together, by shooting himself in the foot, his probability of survival increases to about 0.66248. :-) Dave On Jan 1, 6:58 am, RAHUL KUJUR wrote: > Suppose three gunmen are A, B, and C who have a probability of 100%, 50% and > 33% respectively. The shooting will start from C, then B and at last A. > Now there are several possibilities for C. If C shoots B, then A would shoot > C with an accuracy of 100% or in other case if C shoots A, then B would > shoot him with an accuracy of 50%. So he has a probability of getting > killed. We can see in either of the cases C will die. > So what C will do in first round is that it will fire the shot in air. Now > the scenario gets interesting. By doing this C has turned the battle among > three people into two people A and B. This will increase the chances of > survival of C. So now its B's turn of firing. So he can fire at either A or > C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows > that he will surely die so B won't do that. If B shoots A, then C will shoot > B. > I think this is the solution. Please point out if there are any loopholes. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
hahaha... lol... shoot in air ... lamo :-)) On Sat, Jan 1, 2011 at 6:28 PM, RAHUL KUJUR wrote: > Suppose three gunmen are A, B, and C who have a probability of 100%, 50% > and 33% respectively. The shooting will start from C, then B and at last A. > Now there are several possibilities for C. If C shoots B, then A would > shoot C with an accuracy of 100% or in other case if C shoots A, then B > would shoot him with an accuracy of 50%. So he has a probability of getting > killed. We can see in either of the cases C will die. > So what C will do in first round is that it will fire the shot in air. Now > the scenario gets interesting. By doing this C has turned the battle among > three people into two people A and B. This will increase the chances of > survival of C. So now its B's turn of firing. So he can fire at either A or > C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows > that he will surely die so B won't do that. If B shoots A, then C will shoot > B. > I think this is the solution. Please point out if there are any loopholes. > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Thanks & Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
Suppose three gunmen are A, B, and C who have a probability of 100%, 50% and 33% respectively. The shooting will start from C, then B and at last A. Now there are several possibilities for C. If C shoots B, then A would shoot C with an accuracy of 100% or in other case if C shoots A, then B would shoot him with an accuracy of 50%. So he has a probability of getting killed. We can see in either of the cases C will die. So what C will do in first round is that it will fire the shot in air. Now the scenario gets interesting. By doing this C has turned the battle among three people into two people A and B. This will increase the chances of survival of C. So now its B's turn of firing. So he can fire at either A or C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows that he will surely die so B won't do that. If B shoots A, then C will shoot B. I think this is the solution. Please point out if there are any loopholes. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Fwd: [ƒƒÖ]™ HaPpY NeW YeAr 2011
Thanks for the wishes. Same to you guys too. May this year bring happiness and prosperity into your lives. On Sat, Jan 1, 2011 at 2:27 PM, sudhir mishra wrote: > thank u,wish u the same > > > -- > * > Thanks & Regards... > Sudhir Mishra > undergraduate student, > Department Of **Computer Science and engineering,* > *Motilal Nehru National institute Of Technology-ALLAHABAD. > > * > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Umer -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Fwd: [ƒƒÖ]™ HaPpY NeW YeAr 2011
thank u,wish u the same -- * Thanks & Regards... Sudhir Mishra undergraduate student, Department Of **Computer Science and engineering,* *Motilal Nehru National institute Of Technology-ALLAHABAD. * -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
