Re: [algogeeks] C doubt

2012-10-06 Thread atul anand
ch=i++[s]; // in this value is assigned first and then increment will
take place...bcozz you are using post increment.
here i does not have any other option it has to do post increment
before [] comes...but it will not assign value to 'i' ( i.e
incremented 'i' value)
so compiler will do something like this
ch=*(i + s);
i=i+1;

ch=++i[s]; // in this case compiler will rewrite it to something like this ,
ch=++(*(i+s)); // this will increment the value at i[s], pre-increment
is taking place ...so updated i[s] value will be assigned o ch

if you do somthing like this :-
ch=i[s]++; // here post increment is happening , so compiler will
rewrite it somthing like this

// ch will contain old value but if you print i[s] , it will print
incremented value of i[s];
ch=*(i+s);
i[s]=i[s] + 1;


On 10/6/12, rahul sharma  wrote:
> char ch
> ch=i++[s];
>
> printf("%c",ch);  this will print i[s],then i is incrementrd after
> assigning to ch
>
>
> ch=++i[s];// this will inccrement value at i[s]
>
>
> My question is what is role of priority which is making them behaving
> differentI am not getting  y not first i is incremented then i[s] is
> assigned
> plz tell
>
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Re: [algogeeks] finding element in array with minimum of comparing

2012-10-06 Thread Umer Farooq
Well actually, I've just gone through Dave's code thoroughly and I believe
that his code is most appropriate.

Thanks viper11 for providing the explanation.

As for my code, I'd like to replace

while (i!=j)

with

while (i < j)

because != won't work for middle element if the number of elements are odd
... and it also won't work if the number of elements are even.

Anyway, thanks Dave for providing us with such a great solution. Please
keep posting! :-)

And others, thanks for pointing out the issue in my code.

On Sat, Oct 6, 2012 at 9:03 PM, Kalidhakani J  wrote:

> @umer - what if the element to be searched is at the middle of the array?
> your code doesn't handles this. check out.
>
>
> On Sat, Oct 6, 2012 at 3:38 AM, icy`  wrote:
>
>> nice solution, Dave!
>>
>> @Umer -- if the sought ele is first, then Dave's code has it sitting in
>> the variable temp for a little while.   Loop will stop when size is 0,
>> since arr[0]==elem.  Now he throws temp back into arr[0], which will return
>> index 0 from the last compare line.
>>
>> On Wednesday, October 3, 2012 2:08:56 AM UTC-4, Umer Farooq wrote:
>>>
>>> @Dave Thanks for pointing that out.
>>>
>>> But I still can't get what if elem is on first element or it is not
>>> present in the array? How is your code going to handle that situation?
>>>
>>> @Atul, Well yes, In the given question, the number of iterations were
>>> 2n. Which I have reduced to n+n/2.
>>>
>>>
>>>
>>>
>>>
>>> On Tue, Oct 2, 2012 at 11:13 PM, atul anand  wrote:
>>>
 @umer : how no. of comparison are reduced to half by moving both
 sidesyou have 2 if condition inside, so you are making 2
 comparisons at each iteration + n/2 comparison for while loop so
 number of comparisons are n+n/2

 On 10/2/12, Umer Farooq  wrote:
 > why don't we try it from both ends ... something like this:
 >
 > int i = 0; j = size-1;
 >
 > while (i != j)
 > {
 > if (arr[i] == elem)
 >   return arr[i];
 > if (arr[j] == elem)
 >return arr[j];
 > }
 >
 > this way, we have eliminated half of the comparisons in for loop?
 What do
 > you guys say?
 >
 > On Tue, Oct 2, 2012 at 12:18 PM, rafi  wrote:
 >
 >> Vikas is right!
 >> while (n) is equal to (while n!=0)
 >> you have 2n compares!
 >>
 >> בתאריך יום שני, 1 באוקטובר 2012 12:12:21 UTC+2, מאת vikas:
 >>
 >>> still there is no improvement, compiler will generate the code to
 >>> compare
 >>> with zero here. what you have accomplished is , hide it from human
 eyes
 >>>
 >>> On Monday, 1 October 2012 15:25:09 UTC+5:30, Navin Kumar wrote:
 
  @atul:
  still it won't compare 0 th element. Slight modification in your
 code:
 
  n=*sizeof(arr)*;
  do
  {
   if(elem==arr[*--n*])
   print found;
 
  }while(n);
 
  On Mon, Oct 1, 2012 at 9:50 AM, atul anand 
 wrote:
 
 > yes, but there no need of checking outside the loop
 >
 > n=sizeof(arr)-1;
 > do
 > {
 >  if(elem==arr[n])
 >  print found;
 > n--;
 >
 > }while(n);
 >
 >
 >
 > On Mon, Oct 1, 2012 at 9:33 AM, Navin Kumar
 > wrote:
 >
 >> @atul: keep one more checking outside loop for element at 0 th
 index.
 >> Because when n = 0  the your loop come out from the loop without
 >> comparing
 >> it.
 >>
 >>
 >> On Mon, Oct 1, 2012 at 8:55 AM, atul anand
 >> wrote:
 >>
 >>> n=sizeof(arr);
 >>> n--;
 >>>
 >>> while(n)
 >>> {
 >>>  if(elem=arr[n])
 >>>   print found;
 >>>
 >>> n--;
 >>>
 >>> }
 >>>
 >>> On Sun, Sep 30, 2012 at 2:56 PM, רפי וינר 
 >>> wrote:
 >>>
  Hi
  i was in an interview and was given a simple function
  int arrExsits(int* arr,int size,int elem){
  for (int i=0;i>>>  if(elem==arr[i])
 return i;
  return -1;
  }
  this function does 2n compares
  n- the if statment
  n-check that i is smaller then size
  i was suppose to give an optimal (less compares) solution so i
 gave
 
  int arrExsits(int* arr,int size,int elem){
  if (arr[size-1]==elem)
  return size-1;
  arr[size-1]=elem]
  for (int i=0;;++i)
  if(elem==arr[i]){
  if (i!=size-1)
  return i;
  return -1;
  }
  this solution works and it has n+2 compares the first one
 another n
 >

[algogeeks] C doubt

2012-10-06 Thread rahul sharma
char ch
ch=i++[s];

printf("%c",ch);  this will print i[s],then i is incrementrd after
assigning to ch


ch=++i[s];// this will inccrement value at i[s]


My question is what is role of priority which is making them behaving
differentI am not getting  y not first i is incremented then i[s] is
assigned
plz tell

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Re: [algogeeks] finding element in array with minimum of comparing

2012-10-06 Thread Kalidhakani J
@umer - what if the element to be searched is at the middle of the array?
your code doesn't handles this. check out.

On Sat, Oct 6, 2012 at 3:38 AM, icy`  wrote:

> nice solution, Dave!
>
> @Umer -- if the sought ele is first, then Dave's code has it sitting in
> the variable temp for a little while.   Loop will stop when size is 0,
> since arr[0]==elem.  Now he throws temp back into arr[0], which will return
> index 0 from the last compare line.
>
> On Wednesday, October 3, 2012 2:08:56 AM UTC-4, Umer Farooq wrote:
>>
>> @Dave Thanks for pointing that out.
>>
>> But I still can't get what if elem is on first element or it is not
>> present in the array? How is your code going to handle that situation?
>>
>> @Atul, Well yes, In the given question, the number of iterations were 2n.
>> Which I have reduced to n+n/2.
>>
>>
>>
>>
>>
>> On Tue, Oct 2, 2012 at 11:13 PM, atul anand  wrote:
>>
>>> @umer : how no. of comparison are reduced to half by moving both
>>> sidesyou have 2 if condition inside, so you are making 2
>>> comparisons at each iteration + n/2 comparison for while loop so
>>> number of comparisons are n+n/2
>>>
>>> On 10/2/12, Umer Farooq  wrote:
>>> > why don't we try it from both ends ... something like this:
>>> >
>>> > int i = 0; j = size-1;
>>> >
>>> > while (i != j)
>>> > {
>>> > if (arr[i] == elem)
>>> >   return arr[i];
>>> > if (arr[j] == elem)
>>> >return arr[j];
>>> > }
>>> >
>>> > this way, we have eliminated half of the comparisons in for loop? What
>>> do
>>> > you guys say?
>>> >
>>> > On Tue, Oct 2, 2012 at 12:18 PM, rafi  wrote:
>>> >
>>> >> Vikas is right!
>>> >> while (n) is equal to (while n!=0)
>>> >> you have 2n compares!
>>> >>
>>> >> בתאריך יום שני, 1 באוקטובר 2012 12:12:21 UTC+2, מאת vikas:
>>> >>
>>> >>> still there is no improvement, compiler will generate the code to
>>> >>> compare
>>> >>> with zero here. what you have accomplished is , hide it from human
>>> eyes
>>> >>>
>>> >>> On Monday, 1 October 2012 15:25:09 UTC+5:30, Navin Kumar wrote:
>>> 
>>>  @atul:
>>>  still it won't compare 0 th element. Slight modification in your
>>> code:
>>> 
>>>  n=*sizeof(arr)*;
>>>  do
>>>  {
>>>   if(elem==arr[*--n*])
>>>   print found;
>>> 
>>>  }while(n);
>>> 
>>>  On Mon, Oct 1, 2012 at 9:50 AM, atul anand 
>>> wrote:
>>> 
>>> > yes, but there no need of checking outside the loop
>>> >
>>> > n=sizeof(arr)-1;
>>> > do
>>> > {
>>> >  if(elem==arr[n])
>>> >  print found;
>>> > n--;
>>> >
>>> > }while(n);
>>> >
>>> >
>>> >
>>> > On Mon, Oct 1, 2012 at 9:33 AM, Navin Kumar
>>> > wrote:
>>> >
>>> >> @atul: keep one more checking outside loop for element at 0 th
>>> index.
>>> >> Because when n = 0  the your loop come out from the loop without
>>> >> comparing
>>> >> it.
>>> >>
>>> >>
>>> >> On Mon, Oct 1, 2012 at 8:55 AM, atul anand
>>> >> wrote:
>>> >>
>>> >>> n=sizeof(arr);
>>> >>> n--;
>>> >>>
>>> >>> while(n)
>>> >>> {
>>> >>>  if(elem=arr[n])
>>> >>>   print found;
>>> >>>
>>> >>> n--;
>>> >>>
>>> >>> }
>>> >>>
>>> >>> On Sun, Sep 30, 2012 at 2:56 PM, רפי וינר 
>>> >>> wrote:
>>> >>>
>>>  Hi
>>>  i was in an interview and was given a simple function
>>>  int arrExsits(int* arr,int size,int elem){
>>>  for (int i=0;i>>  if(elem==arr[i])
>>> return i;
>>>  return -1;
>>>  }
>>>  this function does 2n compares
>>>  n- the if statment
>>>  n-check that i is smaller then size
>>>  i was suppose to give an optimal (less compares) solution so i
>>> gave
>>> 
>>>  int arrExsits(int* arr,int size,int elem){
>>>  if (arr[size-1]==elem)
>>>  return size-1;
>>>  arr[size-1]=elem]
>>>  for (int i=0;;++i)
>>>  if(elem==arr[i]){
>>>  if (i!=size-1)
>>>  return i;
>>>  return -1;
>>>  }
>>>  this solution works and it has n+2 compares the first one
>>> another n
>>>  and the second inner if.
>>>  they told me it's good (and I've passed) but they told just for
>>> my
>>>  knowledge that there is a better N compare solution.
>>>  I've searched the web but couldn't find it.
>>>  anybody knows?
>>>  Thanks
>>> 
>>>  --
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Re: [algogeeks] C output

2012-10-06 Thread rahul sharma
#include


int main()
{
char str[10]={'g','k'};
char str1[10]="gh";
int i;
for(i=0;str1[i]!=NULL;i++)
printf("%c",str[i]);
getchar();
}

NUll is there in character array also...make clear me...

On Sat, Oct 6, 2012 at 9:22 PM, rahul sharma wrote:

> int main()
> {
> char str[10]={'g','k'};
> char str1[10]="gh";
>
>
> printf("%s",str);
> printf("%s",str1);
> getchar();
> }
> then how does this work???
> str printing gk...then NULL is automatically appended in this also...plz
> tell
>
>
> On Sat, Oct 6, 2012 at 6:33 PM, Rathish Kannan wrote:
>
>> For string, C appends '\0' internally. hence sizeof(str) returned the
>> value 3.
>> str1 is char array with two character. hence sizeof(str1) returned the
>> value 2.
>>
>> --  RK :)
>>
>>
>> On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma wrote:
>>
>>> char str[]="ab";
>>> char str1[]={'a','b'};
>>>
>>> sizeof(str) ...o/p is 3
>>> sizeof(str1)o/p is 2..
>>>
>>> Why so
>>> plz explain...
>>>
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Re: [algogeeks] C output

2012-10-06 Thread rahul sharma
int main()
{
char str[10]={'g','k'};
char str1[10]="gh";


printf("%s",str);
printf("%s",str1);
getchar();
}
then how does this work???
str printing gk...then NULL is automatically appended in this also...plz
tell


On Sat, Oct 6, 2012 at 6:33 PM, Rathish Kannan wrote:

> For string, C appends '\0' internally. hence sizeof(str) returned the
> value 3.
> str1 is char array with two character. hence sizeof(str1) returned the
> value 2.
>
> --  RK :)
>
>
> On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma wrote:
>
>> char str[]="ab";
>> char str1[]={'a','b'};
>>
>> sizeof(str) ...o/p is 3
>> sizeof(str1)o/p is 2..
>>
>> Why so
>> plz explain...
>>
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>
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Re: [algogeeks]

2012-10-06 Thread vindhya chhabra
i dint get the questions..someone has 2+ year exp ke questions.i dnt
need that.. i need questions for freshers

On Sat, Oct 6, 2012 at 2:20 PM, vaibhav shukla  wrote:
> then please post it here as others might also be in need for the same.
>
>
> On Sat, Oct 6, 2012 at 2:09 PM, vindhya chhabra 
> wrote:
>>
>> m sorry for this ques:) i got to know about it.
>>
>> On Sat, Oct 6, 2012 at 1:42 PM, vindhya chhabra
>>  wrote:
>> > any one has an idea of what is the recruitment procedure of amadeus
>> > software lab and what kind of pattern do they have?
>> >
>> > --
>> > Vindhya Chhabra
>> >
>> > --
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>> >
>>
>>
>>
>> --
>> Vindhya Chhabra
>>
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>
>
>
> --
> best wishes!!
>  Vaibhav
>
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-- 
Vindhya Chhabra

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Re: [algogeeks] Min Edges to be added to DAG to make it Strongly connected?

2012-10-06 Thread atul anand
find no. of cut vertex in the DAGthat will be the ans.
On 6 Oct 2012 19:33, "KK"  wrote:

> Given a DAG(Directed Acyclic Graph). How to find out the minimum number of
> edges that needs to be added so that the given graph becomes Strongly
> Connected?
>
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Re: [algogeeks] C output

2012-10-06 Thread Jaspreet Singh
because of null char in 1st

On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma wrote:

> char str[]="ab";
> char str1[]={'a','b'};
>
> sizeof(str) ...o/p is 3
> sizeof(str1)o/p is 2..
>
> Why so
> plz explain...--
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Re: [algogeeks] C output

2012-10-06 Thread Rathish Kannan
For string, C appends '\0' internally. hence sizeof(str) returned the value
3.
str1 is char array with two character. hence sizeof(str1) returned the
value 2.

--  RK :)


On Sat, Oct 6, 2012 at 5:53 PM, rahul sharma wrote:

> char str[]="ab";
> char str1[]={'a','b'};
>
> sizeof(str) ...o/p is 3
> sizeof(str1)o/p is 2..
>
> Why so
> plz explain...
>
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[algogeeks] Min Edges to be added to DAG to make it Strongly connected?

2012-10-06 Thread KK
Given a DAG(Directed Acyclic Graph). How to find out the minimum number of 
edges that needs to be added so that the given graph becomes Strongly 
Connected?

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[algogeeks] Min Edges to be added to DAG to make it Strongly connected?

2012-10-06 Thread KK
Given a DAG(Directed Acyclic Graph). How to find out the minimum number of 
edges that needs to be added so that the given graph becomes Strongly 
Connected?

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Re: [algogeeks]

2012-10-06 Thread vaibhav shukla
then please post it here as others might also be in need for the same.

On Sat, Oct 6, 2012 at 2:09 PM, vindhya chhabra wrote:

> m sorry for this ques:) i got to know about it.
>
> On Sat, Oct 6, 2012 at 1:42 PM, vindhya chhabra
>  wrote:
> > any one has an idea of what is the recruitment procedure of amadeus
> > software lab and what kind of pattern do they have?
> >
> > --
> > Vindhya Chhabra
> >
> > --
> > You received this message because you are subscribed to the Google
> Groups "Algorithm Geeks" group.
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[algogeeks] C output

2012-10-06 Thread rahul sharma
char str[]="ab";
char str1[]={'a','b'};

sizeof(str) ...o/p is 3
sizeof(str1)o/p is 2..

Why so
plz explain...

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Re: [algogeeks]

2012-10-06 Thread vindhya chhabra
m sorry for this ques:) i got to know about it.

On Sat, Oct 6, 2012 at 1:42 PM, vindhya chhabra
 wrote:
> any one has an idea of what is the recruitment procedure of amadeus
> software lab and what kind of pattern do they have?
>
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[algogeeks]

2012-10-06 Thread vindhya chhabra
any one has an idea of what is the recruitment procedure of amadeus
software lab and what kind of pattern do they have?

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