Re: [algogeeks] Print Hello infinite..................

2011-03-09 Thread Nishant Agarwal
#include
void print1();
void print2()
{
printf("Hello\n");
print1();
}
void print1()
{
printf("Hello\n");
print2();
}
int main()
{
print1();
}


On Thu, Mar 10, 2011 at 11:47 AM, nidhi jain wrote:

>
>
> @abhishek:isn't it recursion?
>
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[algogeeks] Explain the o/p

2011-03-04 Thread Nishant Agarwal
#include
main()
{
long x;
float t;
scanf("%f",&t);
printf("%d\n",t);
x=90;
printf("%f\n",x);
{
x=1;
printf("%f\n",x);
{
x=30;
printf("%f\n",x);
}
printf("%f\n",x);
}
x==9;
printf("%f\n",x);

}

o/p on gcc compiler
20.3   (i/p given)
-1073741824
20.299988
20.299988
20.299988
20.299988
20.299988

plz explain the o/p

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Re: [algogeeks] Re: printing without loop

2011-03-01 Thread Nishant Agarwal
use recursion.

On Tue, Mar 1, 2011 at 5:13 PM, bittu  wrote:

> here we go
>
> void main()
> {
> int i;
>
> i=1;
>
> loop:
> printf("%d", i)
> (i<100)? i++: return 0;
> go to loop;
>
> }
>
> Thanks & Regards
> Shashank Mani >> "The Best Way to Escape From The Problem is to Solve
> it"
>
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Re: [algogeeks] Re: arrays

2010-09-28 Thread Nishant Agarwal
#include
#include
int main()
{
int a[20],i,n,max,t,j,k;
printf("Enter the no. of elements\n");
scanf("%d",&n);
for(i=0;i=max)
{
max=a[j];
k=j;
j--;
}
else
j--;
}
t=a[i];
a[i]=a[k];
a[k]=t;
}
for(i=0;i wrote:

> Move-To-The-Front.
>
> On Sep 27, 11:58 pm, Anand  wrote:
> >  Given an array of integers, for each index i, you have to swap the value
> at
> > i with the first value smaller than A[ i ] that comes after index i
>
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Re: [algogeeks] Re: ReVerse a string using recursion

2010-09-25 Thread Nishant Agarwal
@albert
why r u asking for a non optimal solution??

On Sat, Sep 25, 2010 at 11:24 PM, albert theboss wrote:

> please let me know solution using extra memory.
>
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Re: [algogeeks] Re: Number problem

2010-09-25 Thread Nishant Agarwal
Here's the code
int rem_dup(int n)
{
int *a,i,c,t,d,count[10]={0},arr[20],j=0,sum=0;
a=(int *)malloc(sizeof(a));
for(i=0;n>0;i++)//storing each digit of number in an array
{
a[i]=n%10;
n=n/10;
}
c=d=i-1;
i=0;
while(i wrote:

> @Saurabh: Doesn't this turn 10 into 1? You need to count the digits in
> the number as you are reversing it, and replace the second while loop
> with a for loop with that many iterations.
>
> Dave
>
> On Sep 21, 11:28 pm, saurabh agrawal  wrote:
> > @dave:
> > your code is producing 4526 for input=24526 instead of 2456
> > Here's corrected code :)
> > /CODE///
> > int function(int n){
> > int a[10]={0},temp=0,result =0;
> > while(n){   //reverse the number..
> >  temp=10*temp+n%10;
> >  n/=10;
> > }
> > n=temp;
> > while(n){   ///remove duplicate digits...
> >  if(a[n%10]==0){
> >  a[n%10]=1;
> >  result=10*result+n%10;
> >  }
> > n/=10;
> > }
> > return result;}
> >
> > ///END/
> >
> >
> >
> > On Wed, Sep 22, 2010 at 8:51 AM, Dave  wrote:
> > > @Saurabh: Doesn't your code turn 123 into 321? Try this:
> >
> > > int function(int n)
> > > {
> > >int a[10]={0};
> > >int result=0;
> > > int place=1;
> > > while(n){
> > >if(a[n%10]==0){
> > >a[n%10]=1;
> > > result+=(n%10)*place;
> > >place*=10;
> > >}
> > >n/=10;
> > >}
> > >return result;
> > > }
> >
> > > Dave
> >
> > > On Sep 21, 3:12 pm, saurabh agrawal  wrote:
> > > > int function(int n){
> >
> > > > int a[10]={0};
> > > > int result =0;
> > > > while(n){
> > > > if(a[n%10]==0){
> > > > a[n%10]=1;
> > > > result=10*result+n%10;
> > > > }
> > > > n/=10;}
> >
> > > > return result;`
> >
> > > > }
> > > > On Wed, Sep 22, 2010 at 12:39 AM, Albert 
> > > wrote:
> > > > > Given a number find the number by eliminating the duplicate digits
> in
> > > > > the number..
> >
> > > > > for eg:   24526  ans is 2456
> > > > > .
> >
> > > > > int function(int n)
> > > > > {
> >
> > > > >  .
> > > > >  .
> > > > >  .
> >
> > > > > }
> >
> > > > > Give all sort of solutions to this problem.
> >
> > > > > Efficiency in the code is important 
> >
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Re: [algogeeks] Re: Number problem

2010-09-25 Thread Nishant Agarwal
@yellow
your code turns 1000,100,10,2270,12130 to 1,1,1,27,123 repectively
simply it removes all trailing zeros ...

On Wed, Sep 22, 2010 at 8:10 PM, Yellow Sapphire wrote:

> My Solution.
>
> Almost same as above but the flag is set by using bits.
>
> #define SETFLAG(flag, pos) (flag=flag | (1< #define IS_FLAG_SET(flag,pos) (flag & (1<
> int remove_dup(int n)
> {
>int temp=0, temp2=0;
>unsigned int flag=0;
>
>/*
> * Reverse the number
> */
>while (n>0 && (temp=temp*10 + n%10), n=n/10);
>
>/*
> * Find duplicates by setting the bits in the flag
> */
>n=temp;
>temp=0;
>while (n>0) {
>temp2=n%10;
>if(!IS_FLAG_SET(flag, temp2)) {
>temp=temp*10 + temp2;
>SETFLAG(flag, temp2);
>}
>n=n/10;
>}
>return temp;
> }
>
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Re: [algogeeks] Re: ReVerse a string using recursion

2010-09-24 Thread Nishant Agarwal
i dont think that without giving 1st and last index, this is possible.i
m using i and j as 1st and last index respectively

On Sat, Sep 25, 2010 at 1:00 AM, albert theboss wrote:

> sorry i dont know the solution.
> i just expecting such answer
>
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Re: [algogeeks] Re: ReVerse a string using recursion

2010-09-24 Thread Nishant Agarwal
@albert
i think you know the solution and u r just testing others.so post the
solution and stop this discussion..

On Sat, Sep 25, 2010 at 12:48 AM, albert theboss wrote:

> @nishanth :
>  could u give me any solutions without global variable or static
> variable
>
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Re: [algogeeks] ReVerse a string using recursion

2010-09-23 Thread Nishant Agarwal
@Albert
i think this should be right

static int i=0;
int j;
void xstrrev(char *s)
{
char t;
if(i==0)
j=strlen(s)-1;
if(iwrote:

> Ur function prototype is not similar to one i posted before
>
> check it out
>
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Re: [algogeeks] ReVerse a string using recursion

2010-09-23 Thread Nishant Agarwal
i am giving the full code

#include
#include
#include
void xstrrev(char *s , int i , int j)
{
char t;
if(i wrote:

> @nishant:
> what is i and j..???
> @
>
> On Thu, Sep 23, 2010 at 1:20 PM, Nishant Agarwal <
> nishant.agarwa...@gmail.com> wrote:
>
>> void xstrrev(char *s , int i , int j)
>> {
>> char t;
>> if(i> {
>> t=s[i];
>> s[i]=s[j];
>> s[j]=t;
>> xstrrev(s,i+1,j-1);
>>
>> }
>> }
>>
>> On Thu, Sep 23, 2010 at 11:29 PM, Albert  wrote:
>>
>>> How to reverse a String using recursion in C without using any extra
>>> memory?
>>>
>>> the question seems to be simple.
>>>
>>> char* strrev(char *)
>>> {
>>>...
>>>...
>>>...
>>> }
>>>
>>>
>>> Try to give all the answers for this prototype.
>>>
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>>>
>>
>>
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>> Computer Science and Engineering
>> NIT Allahabad
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Re: [algogeeks] ReVerse a string using recursion

2010-09-23 Thread Nishant Agarwal
void xstrrev(char *s , int i , int j)
{
char t;
if(i wrote:

> How to reverse a String using recursion in C without using any extra
> memory?
>
> the question seems to be simple.
>
> char* strrev(char *)
> {
>...
>...
>...
> }
>
>
> Try to give all the answers for this prototype.
>
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Re: [algogeeks] Re: Print 1 to n one per each line on the standard output

2010-09-23 Thread Nishant Agarwal
try in linux.it is working fine

On Thu, Sep 23, 2010 at 8:58 PM, coolfrog$
wrote:

> @Greed
> in windows.. output is  infinite loop and printing...
> 0
> 0
> 0
> 0
> 0
> ...  infinite loop..
>
>
> On Thu, Sep 23, 2010 at 9:57 AM, Greed  wrote:
>
>> You can use setjmp ,longjmp  or goto to get desired result.
>> #include
>> #include
>> void print(int v)
>> {
>>int i=0;
>>
>>jmp_buf env;
>>
>>setjmp(env);
>>if(i<=v)
>>{
>>printf("%d\n",i);
>>++i;
>>longjmp(env,1);
>>}
>> }
>>
>>
>> int main()
>> {
>>int n;
>>scanf("%d",&n);
>>print(n);
>> }
>>
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Re: [algogeeks] sum of primes

2010-09-23 Thread Nishant Agarwal
http://en.wikipedia.org/wiki/Sieve_of_Eratosthenes

On Thu, Sep 23, 2010 at 5:45 PM, Debajyoti Sarma
wrote:

> How to find the sum of prime numbers between 1 and 1.
> I don't expected traversal of the whole range and find primes and sum
> uping
> Any other logic is there?? i think we need deep mathematics for this .
>
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Re: [algogeeks] do this: two numbers with min diff

2010-09-23 Thread Nishant Agarwal
int minDiff(int arr[], int arr_size)
{
  int min_diff = arr[1] - arr[0];
  int max_element = arr[0];
  int i;
  for(i = 1; i < arr_size; i++)
  {
if(arr[i] - max_element < min_diff)
  min_diff = arr[i] - max_element;
if(arr[i] > max_element)
 max_element = arr[i];
  }
  return min_diff;
}


On Mon, Sep 20, 2010 at 10:38 AM, Srinivas wrote:

> 2 nos with min diff
> given an array of size n. find 2 numbers from array whose difference
> is least in O(n) w/o
> using xtra space( i mean constant space)
>
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Computer Science and Engineering
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Re: [algogeeks] Print 1 to n one per each line on the standard output

2010-09-22 Thread Nishant Agarwal
void print_number(int n)
{ if(n<=100)
  { printf("%d\n",n); print_number(n+1);}
}
main()
{ int n=1; print_number(n);}

this code is using recursion only.not loops, goto and switch
if anyone can do it without recursion then please post ur algo...
On Wed, Sep 22, 2010 at 9:19 PM, Divesh Dixit <
dixit.coolfrog.div...@gmail.com> wrote:

> Write an algorithm that will print 1 to n, one per each line on the
> standard output, where n is
> a integer parameter to the algorithm. An algorithm should not use
> while, for, do-while
> loops, goto statement, recursion, and switch statement.
>
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Re: [algogeeks] A help please

2010-09-22 Thread Nishant Agarwal
output will be
2 garbage_value

scanf returns numbers of inputs taken from std input and since there should
be 2 arguments in printf according to the format, so garbage value will
print

On Wed, Sep 22, 2010 at 2:25 PM, rahul rai  wrote:

> "printf("%d%d",scanf("%d%d",&a &b))"
>
> --
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> rahulpossi...@gmail.com
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