Re: [algogeeks] c program output
Float comparison are not recomended in C++ better try the following condition.
If( abs( a- 11.202 ) <= 1.e6 )
This will solve your problem.
Sent from my iPod
On Feb 7, 2011, at 8:22 PM, ankit agarwal wrote:
> #include
>
> int main()
> {
> float a=11.202;
> if(a<11.202)
> printf("Hiii!!!\n");
> else
> printf("Hello!!!\n");
> return 0;
> }
>
> output: Hiii!!!
>
> why does this output comes???
>
>
>
> Ankit Agarwal
>
>
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Re: [algogeeks] Re: C++ Riddle
I tried in vs 2005 in windows and work fine for me.
Sent from my iPod
On Feb 7, 2011, at 8:45 PM, "Sarma Tangirala" wrote:
> Won't it increment by 2 (or something) and not by 1?
> Sent from my BlackBerry
>
> From: Rajeevpodar
> Sender: algogeeks@googlegroups.com
> Date: Mon, 7 Feb 2011 20:41:32 +0530
> To: algogeeks@googlegroups.com
> ReplyTo: algogeeks@googlegroups.com
> Subject: Re: [algogeeks] Re: C++ Riddle
>
> @ashish: tht's true. But that will be the sum of two numbers.
> Reason is v store the address in char* so when increment it by other number
> it will increment that times, that is the required answer.
>
> Sent from my iPod
>
> On Feb 7, 2011, at 7:14 PM, Ashish Goel wrote:
>
>> &p[n] gives address of p+n it does not add..
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>>
>> On Mon, Feb 7, 2011 at 11:47 AM, jalaj jaiswal
>> wrote:
>> try this
>>
>> let nos be m & n
>>
>> char * p;
>> p=m;
>> int sum = (int)&p[n] ;
>>
>> sum is m+n :)
>>
>>
>> On Mon, Feb 7, 2011 at 11:41 AM, Dave wrote:
>> @Ricky: if increment and decrement operators are not considered
>> arithmetic, try
>>
>> int sum(int m, int n)
>> {
>>while( m > 0 )
>>{
>>m--;
>>n++;
>>}
>>while( m < 0 )
>>{
>>m++;
>>n--;
>>}
>>return n;
>> }
>>
>> On Feb 6, 11:49 pm, Ricky wrote:
>> > write the program to add two numbers without using arithmetic and bit
>> > operation..
>>
>> --
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>>
>>
>>
>>
>> --
>> With Regards,
>> Jalaj Jaiswal (+919019947895)
>> Final Year Undergraduate,
>> IIIT ALLAHABAD
>>
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Re: [algogeeks] Re: C++ Riddle
@ashish: tht's true. But that will be the sum of two numbers.
Reason is v store the address in char* so when increment it by other number it
will increment that times, that is the required answer.
Sent from my iPod
On Feb 7, 2011, at 7:14 PM, Ashish Goel wrote:
> &p[n] gives address of p+n it does not add..
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
> On Mon, Feb 7, 2011 at 11:47 AM, jalaj jaiswal
> wrote:
> try this
>
> let nos be m & n
>
> char * p;
> p=m;
> int sum = (int)&p[n] ;
>
> sum is m+n :)
>
>
> On Mon, Feb 7, 2011 at 11:41 AM, Dave wrote:
> @Ricky: if increment and decrement operators are not considered
> arithmetic, try
>
> int sum(int m, int n)
> {
>while( m > 0 )
>{
>m--;
>n++;
>}
>while( m < 0 )
>{
>m++;
>n--;
>}
>return n;
> }
>
> On Feb 6, 11:49 pm, Ricky wrote:
> > write the program to add two numbers without using arithmetic and bit
> > operation..
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
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> For more options, visit this group at
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>
>
>
>
> --
> With Regards,
> Jalaj Jaiswal (+919019947895)
> Final Year Undergraduate,
> IIIT ALLAHABAD
>
> --
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>
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