Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread Dipit Grover
 http://en.wikipedia.org/wiki/Cayley%27s_formula

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Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread Dipit Grover
Mistake noted! Haste makes waste indeed.

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Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread Aamir Khan
On Sun, Dec 4, 2011 at 12:10 AM, praveen raj  wrote:

> N!/2
>
N!/2 is definitely wrong as you guys are thinking of MST with just two
terminal nodes. All the MSTs will be much more than N!/2 because of any
number of terminal nodes possible, but i can't find the closed form it.

>
> On 03-Dec-2011 11:30 PM, "Dipit Grover"  wrote:
> >
> > ^ we need to count "each permutation and its reverse" together as one
> possibility since both would result in identical mst.
> >
>



Aamir Khan | 3rd Year  | Computer Science & Engineering | IIT Roorkee

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Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread praveen raj
N!/2
On 03-Dec-2011 11:30 PM, "Dipit Grover"  wrote:
>
> ^ we need to count "each permutation and its reverse" together as one
possibility since both would result in identical mst.
>
>
>
>
>
> --
> Dipit Grover
> B.Tech in Computer Science and Engineering - lllrd year
> IIT Roorkee, India
>
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Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread Dipit Grover
^ we need to count "each permutation and its reverse" together as one
possibility since both would result in identical mst.




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Dipit Grover
B.Tech in Computer Science and Engineering - lllrd year
IIT Roorkee, India

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Re: [algogeeks] NUMBER OF MST ?

2011-12-03 Thread Dipit Grover
Shouldnt it be (n!)/2  ?  Equivalent to permutation of n distinct numbers
except that we need to count each permutation once, since for any
permutation, there would also be a reverse permutation that would result in
an identical mst in the given scenario.

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Dipit Grover
B.Tech in Computer Science and Engineering - lllrd year
IIT Roorkee, India

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[algogeeks] NUMBER OF MST ?

2011-12-03 Thread geek forgeek
If there are n nodes in a graph connected to each other with edges of same
length .Then how many minimum spanning trees are possible ?

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