Re: [algogeeks] Re: sbtration
awesum :) thanx all On Tue, Jul 12, 2011 at 8:27 PM, bittu wrote: > Lets Try For Decimal Integer Number how we add them > > 1 Add 759 + 674, but “forget” to carry I then get 323 > 2 Add 759 + 674 but only do the carrying, rather than the addition of > each digit I then > get 1110 > 3 Add the result of the first two operations (recursively, using the > same process de- > scribed in step 1 and 2): 1110 + 323 = 1433 > > we have done for decimal numbers > > Now, how would we do this in binary? > > 1 If I add two binary numbers together but forget to carry, bit[i] > will be 0 if bit[i] in a and > b are both 0 or both 1 This is an XOR > 2 If I add two numbers together but only carry, I will have a 1 in > bit[i] if bit[i-1] in a and b > are both 1’s This is an AND, shifted > > 3 Now, recurse until there’s nothing to carry > > int add_no_arithm(int a, int b) > { > if (b == 0) return a; > int sum = a ^ b; // add without carrying > int carry = (a & b) << 1; // carry, but don’t add return > add_no_arithm(sum, carry); // recurse > } > > Subtraction uses add function internally as well as we have adder !!! > > int sub(int x, int y) > { > return(add(x,add(~y,1)); > > } > > Thanks > Shashank Mani > Computer Science > Birla Institute of Technology Mesra > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: sbtration
Lets Try For Decimal Integer Number how we add them 1 Add 759 + 674, but “forget” to carry I then get 323 2 Add 759 + 674 but only do the carrying, rather than the addition of each digit I then get 1110 3 Add the result of the first two operations (recursively, using the same process de- scribed in step 1 and 2): 1110 + 323 = 1433 we have done for decimal numbers Now, how would we do this in binary? 1 If I add two binary numbers together but forget to carry, bit[i] will be 0 if bit[i] in a and b are both 0 or both 1 This is an XOR 2 If I add two numbers together but only carry, I will have a 1 in bit[i] if bit[i-1] in a and b are both 1’s This is an AND, shifted 3 Now, recurse until there’s nothing to carry int add_no_arithm(int a, int b) { if (b == 0) return a; int sum = a ^ b; // add without carrying int carry = (a & b) << 1; // carry, but don’t add return add_no_arithm(sum, carry); // recurse } Subtraction uses add function internally as well as we have adder !!! int sub(int x, int y) { return(add(x,add(~y,1)); } Thanks Shashank Mani Computer Science Birla Institute of Technology Mesra -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
correction: if(a/b<=1){ return a%b; } else (a/b)*b + a%b; assumption that difference is positive everytime On Tue, Jul 12, 2011 at 10:29 AM, Dave wrote: > @Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 > = 5. Check? > > Dave > > On Jul 11, 11:38 pm, chandy jose paul wrote: > > Y are u guys complicating things.Its as simple as this > > > > x=a-b = (a/b)*b + a%b > > > > > > > > On Tue, Jul 12, 2011 at 1:18 AM, Dave wrote: > > > @Aditya: Since 124 is a 3-digit number, I think it would make more > > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + > > > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents > > > an overflow, which you ignore. Thus, the answer is 78. > > > > > Dave > > > > > On Jul 11, 2:42 pm, aditya pratap wrote: > > > > suppose u want to do 124 - 46 > > > > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 > > > > step2: add 124 + 54 = 178 > > > > step3: neglect 1 from 178 and answer will be 78. > > > > > > correct me if i am wrong. > > > > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain > > > > wrote: > > > > > how to do subtraction of two integers widout using subtractn?? > > > > > > > -- > > > > > You received this message because you are subscribed to the Google > > > Groups > > > > > "Algorithm Geeks" group. > > > > > To post to this group, send email to algogeeks@googlegroups.com. > > > > > To unsubscribe from this group, send email to > > > > > algogeeks+unsubscr...@googlegroups.com. > > > > > For more options, visit this group at > > > > >http://groups.google.com/group/algogeeks?hl=en. > > > > > > -- > > > > Regards > > > > Aditya Pratap > > > > MCA II > > > > > -- > > > You received this message because you are subscribed to the Google > Groups > > > "Algorithm Geeks" group. > > > To post to this group, send email to algogeeks@googlegroups.com. > > > To unsubscribe from this group, send email to > > > algogeeks+unsubscr...@googlegroups.com. > > > For more options, visit this group at > > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > > > - Show quoted text - > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
@hary check sunny's solution and for '+' do with bitwise operators. On Tue, Jul 12, 2011 at 4:11 PM, hary rathor wrote: > how it can done without using any arithmetic operation ? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- best wishes!! Vaibhav Shukla DU-MCA -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
how it can done without using any arithmetic operation ? -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
@sunny: +1 On Tue, Jul 12, 2011 at 11:11 AM, Vishal Thanki wrote: > z = x + (-y) > > :) > > On Tue, Jul 12, 2011 at 10:58 AM, Sunny T wrote: > > i would say.. implementing subtraction using division and modulus is more > > costly and complicated. bit manipulation is the fastest among all > > these techniques. > > x=a-b = (a/b)*b + a%b > > .here u are performing... totally 4 operations..1 division,1 > > multiplication,1 modulus and 1 addition.. > > > > it can be easily done by... > > > > x=a+(~b+1). this solution takes less number of operation than > > ur solution and involve less costly operators. > > > > On Tue, Jul 12, 2011 at 10:29 AM, Dave wrote: > >> > >> @Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 > >> = 5. Check? > >> > >> Dave > >> > >> On Jul 11, 11:38 pm, chandy jose paul wrote: > >> > Y are u guys complicating things.Its as simple as this > >> > > >> > x=a-b = (a/b)*b + a%b > >> > > >> > > >> > > >> > On Tue, Jul 12, 2011 at 1:18 AM, Dave > wrote: > >> > > @Aditya: Since 124 is a 3-digit number, I think it would make more > >> > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 > + > >> > > 954 = 1078. Since we are working in 3-digit numbers, the 1 > represents > >> > > an overflow, which you ignore. Thus, the answer is 78. > >> > > >> > > Dave > >> > > >> > > On Jul 11, 2:42 pm, aditya pratap > wrote: > >> > > > suppose u want to do 124 - 46 > >> > > >> > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = > 54 > >> > > > step2: add 124 + 54 = 178 > >> > > > step3: neglect 1 from 178 and answer will be 78. > >> > > >> > > > correct me if i am wrong. > >> > > >> > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain > >> > > > > >> > > wrote: > >> > > > > how to do subtraction of two integers widout using subtractn?? > >> > > >> > > > > -- > >> > > > > You received this message because you are subscribed to the > Google > >> > > Groups > >> > > > > "Algorithm Geeks" group. > >> > > > > To post to this group, send email to algogeeks@googlegroups.com > . > >> > > > > To unsubscribe from this group, send email to > >> > > > > algogeeks+unsubscr...@googlegroups.com. > >> > > > > For more options, visit this group at > >> > > > >http://groups.google.com/group/algogeeks?hl=en. > >> > > >> > > > -- > >> > > > Regards > >> > > > Aditya Pratap > >> > > > MCA II > >> > > >> > > -- > >> > > You received this message because you are subscribed to the Google > >> > > Groups > >> > > "Algorithm Geeks" group. > >> > > To post to this group, send email to algogeeks@googlegroups.com. > >> > > To unsubscribe from this group, send email to > >> > > algogeeks+unsubscr...@googlegroups.com. > >> > > For more options, visit this group at > >> > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > >> > > >> > - Show quoted text - > >> > >> -- > >> You received this message because you are subscribed to the Google > Groups > >> "Algorithm Geeks" group. > >> To post to this group, send email to algogeeks@googlegroups.com. > >> To unsubscribe from this group, send email to > >> algogeeks+unsubscr...@googlegroups.com. > >> For more options, visit this group at > >> http://groups.google.com/group/algogeeks?hl=en. > >> > > > > > > > > -- > > Warm Regards, > > Sunny T > > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > > http://groups.google.com/group/algogeeks?hl=en. > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
z = x + (-y) :) On Tue, Jul 12, 2011 at 10:58 AM, Sunny T wrote: > i would say.. implementing subtraction using division and modulus is more > costly and complicated. bit manipulation is the fastest among all > these techniques. > x=a-b = (a/b)*b + a%b > .here u are performing... totally 4 operations..1 division,1 > multiplication,1 modulus and 1 addition.. > > it can be easily done by... > > x=a+(~b+1). this solution takes less number of operation than > ur solution and involve less costly operators. > > On Tue, Jul 12, 2011 at 10:29 AM, Dave wrote: >> >> @Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 >> = 5. Check? >> >> Dave >> >> On Jul 11, 11:38 pm, chandy jose paul wrote: >> > Y are u guys complicating things.Its as simple as this >> > >> > x=a-b = (a/b)*b + a%b >> > >> > >> > >> > On Tue, Jul 12, 2011 at 1:18 AM, Dave wrote: >> > > @Aditya: Since 124 is a 3-digit number, I think it would make more >> > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + >> > > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents >> > > an overflow, which you ignore. Thus, the answer is 78. >> > >> > > Dave >> > >> > > On Jul 11, 2:42 pm, aditya pratap wrote: >> > > > suppose u want to do 124 - 46 >> > >> > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 >> > > > step2: add 124 + 54 = 178 >> > > > step3: neglect 1 from 178 and answer will be 78. >> > >> > > > correct me if i am wrong. >> > >> > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain >> > > > >> > > wrote: >> > > > > how to do subtraction of two integers widout using subtractn?? >> > >> > > > > -- >> > > > > You received this message because you are subscribed to the Google >> > > Groups >> > > > > "Algorithm Geeks" group. >> > > > > To post to this group, send email to algogeeks@googlegroups.com. >> > > > > To unsubscribe from this group, send email to >> > > > > algogeeks+unsubscr...@googlegroups.com. >> > > > > For more options, visit this group at >> > > > >http://groups.google.com/group/algogeeks?hl=en. >> > >> > > > -- >> > > > Regards >> > > > Aditya Pratap >> > > > MCA II >> > >> > > -- >> > > You received this message because you are subscribed to the Google >> > > Groups >> > > "Algorithm Geeks" group. >> > > To post to this group, send email to algogeeks@googlegroups.com. >> > > To unsubscribe from this group, send email to >> > > algogeeks+unsubscr...@googlegroups.com. >> > > For more options, visit this group at >> > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - >> > >> > - Show quoted text - >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Warm Regards, > Sunny T > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
i would say.. implementing subtraction using division and modulus is more costly and complicated. bit manipulation is the fastest among all these techniques. x=a-b = (a/b)*b + a%b .here u are performing... totally 4 operations..1 division,1 multiplication,1 modulus and 1 addition.. it can be easily done by... x=a+(~b+1). this solution takes less number of operation than ur solution and involve less costly operators. On Tue, Jul 12, 2011 at 10:29 AM, Dave wrote: > @Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 > = 5. Check? > > Dave > > On Jul 11, 11:38 pm, chandy jose paul wrote: > > Y are u guys complicating things.Its as simple as this > > > > x=a-b = (a/b)*b + a%b > > > > > > > > On Tue, Jul 12, 2011 at 1:18 AM, Dave wrote: > > > @Aditya: Since 124 is a 3-digit number, I think it would make more > > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + > > > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents > > > an overflow, which you ignore. Thus, the answer is 78. > > > > > Dave > > > > > On Jul 11, 2:42 pm, aditya pratap wrote: > > > > suppose u want to do 124 - 46 > > > > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 > > > > step2: add 124 + 54 = 178 > > > > step3: neglect 1 from 178 and answer will be 78. > > > > > > correct me if i am wrong. > > > > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain > > > > wrote: > > > > > how to do subtraction of two integers widout using subtractn?? > > > > > > > -- > > > > > You received this message because you are subscribed to the Google > > > Groups > > > > > "Algorithm Geeks" group. > > > > > To post to this group, send email to algogeeks@googlegroups.com. > > > > > To unsubscribe from this group, send email to > > > > > algogeeks+unsubscr...@googlegroups.com. > > > > > For more options, visit this group at > > > > >http://groups.google.com/group/algogeeks?hl=en. > > > > > > -- > > > > Regards > > > > Aditya Pratap > > > > MCA II > > > > > -- > > > You received this message because you are subscribed to the Google > Groups > > > "Algorithm Geeks" group. > > > To post to this group, send email to algogeeks@googlegroups.com. > > > To unsubscribe from this group, send email to > > > algogeeks+unsubscr...@googlegroups.com. > > > For more options, visit this group at > > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > > > - Show quoted text - > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Warm Regards, Sunny T -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: sbtration
@Chandy: Let a = 5 and b = 3. Then x = 5 - 3 = (5/3)*3 + 5%3 = 1*3 + 2 = 5. Check? Dave On Jul 11, 11:38 pm, chandy jose paul wrote: > Y are u guys complicating things.Its as simple as this > > x=a-b = (a/b)*b + a%b > > > > On Tue, Jul 12, 2011 at 1:18 AM, Dave wrote: > > @Aditya: Since 124 is a 3-digit number, I think it would make more > > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + > > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents > > an overflow, which you ignore. Thus, the answer is 78. > > > Dave > > > On Jul 11, 2:42 pm, aditya pratap wrote: > > > suppose u want to do 124 - 46 > > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 > > > step2: add 124 + 54 = 178 > > > step3: neglect 1 from 178 and answer will be 78. > > > > correct me if i am wrong. > > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain > > wrote: > > > > how to do subtraction of two integers widout using subtractn?? > > > > > -- > > > > You received this message because you are subscribed to the Google > > Groups > > > > "Algorithm Geeks" group. > > > > To post to this group, send email to algogeeks@googlegroups.com. > > > > To unsubscribe from this group, send email to > > > > algogeeks+unsubscr...@googlegroups.com. > > > > For more options, visit this group at > > > >http://groups.google.com/group/algogeeks?hl=en. > > > > -- > > > Regards > > > Aditya Pratap > > > MCA II > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: sbtration
Y are u guys complicating things.Its as simple as this x=a-b = (a/b)*b + a%b On Tue, Jul 12, 2011 at 1:18 AM, Dave wrote: > @Aditya: Since 124 is a 3-digit number, I think it would make more > sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + > 954 = 1078. Since we are working in 3-digit numbers, the 1 represents > an overflow, which you ignore. Thus, the answer is 78. > > Dave > > On Jul 11, 2:42 pm, aditya pratap wrote: > > suppose u want to do 124 - 46 > > > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 > > step2: add 124 + 54 = 178 > > step3: neglect 1 from 178 and answer will be 78. > > > > correct me if i am wrong. > > > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain > wrote: > > > how to do subtraction of two integers widout using subtractn?? > > > > > -- > > > You received this message because you are subscribed to the Google > Groups > > > "Algorithm Geeks" group. > > > To post to this group, send email to algogeeks@googlegroups.com. > > > To unsubscribe from this group, send email to > > > algogeeks+unsubscr...@googlegroups.com. > > > For more options, visit this group at > > >http://groups.google.com/group/algogeeks?hl=en. > > > > -- > > Regards > > Aditya Pratap > > MCA II > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: sbtration
@Aditya: Since 124 is a 3-digit number, I think it would make more sense to use the 3-digit 10's complement of 46, i.e., 954. Then 124 + 954 = 1078. Since we are working in 3-digit numbers, the 1 represents an overflow, which you ignore. Thus, the answer is 78. Dave On Jul 11, 2:42 pm, aditya pratap wrote: > suppose u want to do 124 - 46 > > step1 : write 10's complement of 46 i.e. 53 (9's complement) +1 = 54 > step2: add 124 + 54 = 178 > step3: neglect 1 from 178 and answer will be 78. > > correct me if i am wrong. > > On Tue, Jul 12, 2011 at 12:54 AM, Anika Jain wrote: > > how to do subtraction of two integers widout using subtractn?? > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en. > > -- > Regards > Aditya Pratap > MCA II -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.