[algogeeks] apti????

2011-08-31 Thread htross
If a 6 o'clock the clock strikes 6times. The difference between the
first and the last strike is 30 secs. Find the time taken when it
strikes 12

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Re: [algogeeks] apti????

2011-08-31 Thread annarao kataru
it takes  66  sec after 12correct me if i am wrong

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Re: [algogeeks] apti????

2011-08-31 Thread Dheeraj Sharma
66 sec

On Wed, Aug 31, 2011 at 11:00 PM, htross  wrote:

> If a 6 o'clock the clock strikes 6times. The difference between the
> first and the last strike is 30 secs. Find the time taken when it
> strikes 12
>
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Re: [algogeeks] apti!

2011-08-26 Thread Dheeraj Sharma
ans is 20



*Stop Cramming Start Thinking*
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Re: [algogeeks] apti!

2011-08-26 Thread priya ramesh
oh thanks :) It's given as 10 only. Printing mistake i guess.

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Re: [algogeeks] apti!

2011-08-26 Thread Piyush Grover
it's basic unitary method problem:

x men do work in 10 days
1 man will do-in 10*x days
x-10 men do it in 10*x/(x-10) = (10+10)

Solve it and x = 20
 it can't be 130

On Fri, Aug 26, 2011 at 11:53 PM, gmagog...@gmail.com
wrote:

> @Rahul
>
> Assume the productivity of each man is the same
>
> let original number of man be x
>
> The total workload= x*10*p
> also workload = (x-10)(10+10)*p
>
> solve it
> so x=20
>
> Yanan Cao
>
>
>
> On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma wrote:
>
>> @yanan how it is 20.
>>
>> Rahul Verma
>>
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Re: [algogeeks] apti!

2011-08-26 Thread Sanjay Rajpal
If it is 10 days originally, answer is 20 for sure.


Sanju
:)



On Fri, Aug 26, 2011 at 11:27 AM, Sanjay Rajpal  wrote:

>  In this question, instead of 10, it is 100.
> Check it again.
>
>
> Sanju
> :)
>
>
>
> On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal  wrote:
>
>>  Sry for prrevious post .
>>
>> It is question of R S Aggarwal, and solved using conecpt of direct and
>> indirect proportions.
>>
>> Originally,let there be x men.
>>
>> Less men,more days(indirect proposition)
>>
>> (x-10) : x :: 100 : 110
>>
>> (x-10) * 110 = x * 100
>>
>> ANS : x = 110
>>
>>
>> Sanju
>> :)
>>
>>
>>
>> On Fri, Aug 26, 2011 at 11:23 AM, gmagog...@gmail.com <
>> gmagog...@gmail.com> wrote:
>>
>>> @Rahul
>>>
>>> Assume the productivity of each man is the same
>>>
>>> let original number of man be x
>>>
>>> The total workload= x*10*p
>>> also workload = (x-10)(10+10)*p
>>>
>>> solve it
>>> so x=20
>>>
>>> Yanan Cao
>>>
>>>
>>>
>>> On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma wrote:
>>>
 @yanan how it is 20.

 Rahul Verma

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>>
>>
>

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Re: [algogeeks] apti!

2011-08-26 Thread Sanjay Rajpal
In this question, instead of 10, it is 100.
Check it again.


Sanju
:)



On Fri, Aug 26, 2011 at 11:26 AM, Sanjay Rajpal  wrote:

>  Sry for prrevious post .
>
> It is question of R S Aggarwal, and solved using conecpt of direct and
> indirect proportions.
>
> Originally,let there be x men.
>
> Less men,more days(indirect proposition)
>
> (x-10) : x :: 100 : 110
>
> (x-10) * 110 = x * 100
>
> ANS : x = 110
>
>
> Sanju
> :)
>
>
>
> On Fri, Aug 26, 2011 at 11:23 AM, gmagog...@gmail.com  > wrote:
>
>> @Rahul
>>
>> Assume the productivity of each man is the same
>>
>> let original number of man be x
>>
>> The total workload= x*10*p
>> also workload = (x-10)(10+10)*p
>>
>> solve it
>> so x=20
>>
>> Yanan Cao
>>
>>
>>
>> On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma wrote:
>>
>>> @yanan how it is 20.
>>>
>>> Rahul Verma
>>>
>>> --
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>
>

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Re: [algogeeks] apti!

2011-08-26 Thread Sanjay Rajpal
Sry for prrevious post .

It is question of R S Aggarwal, and solved using conecpt of direct and
indirect proportions.

Originally,let there be x men.

Less men,more days(indirect proposition)

(x-10) : x :: 100 : 110

(x-10) * 110 = x * 100

ANS : x = 110


Sanju
:)



On Fri, Aug 26, 2011 at 11:23 AM, gmagog...@gmail.com
wrote:

> @Rahul
>
> Assume the productivity of each man is the same
>
> let original number of man be x
>
> The total workload= x*10*p
> also workload = (x-10)(10+10)*p
>
> solve it
> so x=20
>
> Yanan Cao
>
>
>
> On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma wrote:
>
>> @yanan how it is 20.
>>
>> Rahul Verma
>>
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Re: [algogeeks] apti!

2011-08-26 Thread gmagog...@gmail.com
@Rahul

Assume the productivity of each man is the same

let original number of man be x

The total workload= x*10*p
also workload = (x-10)(10+10)*p

solve it
so x=20

Yanan Cao



On Fri, Aug 26, 2011 at 1:21 PM, Rahul Verma  wrote:

> @yanan how it is 20.
>
> Rahul Verma
>
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Re: [algogeeks] apti!

2011-08-26 Thread priya ramesh
the answer is 130 itseems. i too got 20

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Re: [algogeeks] apti!

2011-08-26 Thread Rahul Verma
@yanan how it is 20.

Rahul Verma

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Re: [algogeeks] apti!

2011-08-26 Thread Sanjay Rajpal
20 men ?

(x-10)20=10x
Sanju
:)



On Fri, Aug 26, 2011 at 11:17 AM, gmagog...@gmail.com
wrote:

> 20?
>
> Yanan Cao
>
>
>
> On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh <
> love.for.programm...@gmail.com> wrote:
>
>> A certain number of men can finish a piece of work in 10 days. If however
>> there were 10 men less it will take 10 days more for the work to be
>> finished. How
>> many men were there originally?
>>
>> (a) 110 men
>> (b) 130 men
>> (c) 100 men
>> (d) none of these
>>
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Re: [algogeeks] apti!

2011-08-26 Thread priya ramesh
i too got the same ans.

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Re: [algogeeks] apti!

2011-08-26 Thread gmagog...@gmail.com
20?

Yanan Cao



On Fri, Aug 26, 2011 at 1:12 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

> A certain number of men can finish a piece of work in 10 days. If however
> there were 10 men less it will take 10 days more for the work to be
> finished. How
> many men were there originally?
>
> (a) 110 men
> (b) 130 men
> (c) 100 men
> (d) none of these
>
> --
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[algogeeks] apti!

2011-08-26 Thread priya ramesh
A certain number of men can finish a piece of work in 10 days. If however
there were 10 men less it will take 10 days more for the work to be
finished. How
many men were there originally?

(a) 110 men
(b) 130 men
(c) 100 men
(d) none of these

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Re: [algogeeks] Apti

2011-08-23 Thread Nikhil Gupta
sorry I   wrote   them in different order:
if (a,b) and (b,a) are considered same then answer is 12
and if they are considered different it is 24.


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Re: [algogeeks] Apti

2011-08-23 Thread prakash y
The number of distinct factors a number has is given by the product of one
more than the maximum power of each of the prime factors.
the number 24*33 = 792 can be written as (2^3)*(3^2)*(11^1)
then the number of distinct factors of 792 will become (3+1)*(2+1)*(1+1) =
24
So we can form 24/2 = 12 distinct sets of (a,b)  such that N = a*b

http://www.mathisfunforum.com/viewtopic.php?id=11042


On Tue, Aug 23, 2011 at 11:38 PM, Shravan Kumar  wrote:

> It would be sum of number of  factors of both the numbers.
> 24 -1,2,3,4,6,8,12,24
> 33-1,3,11,33
>
>
> On Tue, Aug 23, 2011 at 10:54 PM, Aman Goyal wrote:
>
>> ans is 12, but instead of counting i am looking for some better solution.
>>
>>
>> On Tue, Aug 23, 2011 at 10:48 PM, manish patel 
>> wrote:
>>
>>>
>>> (24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
>>>
>>> On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal wrote:
>>>
 Let a natural number N be such that N = a × b where a and b are the
 factors of N. How many such sets of (a, b) can be formed in which the
 selection of the two numbers a and b is distinctly different if N = 24 × 
 33?

 Please explain your solution also.

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>>>
>>>
>>>
>>> --
>>> With Regards
>>>
>>> Manish Patel
>>> BTech 3rd Year
>>> Computer Science And Engineering
>>> National Institute of Technology -Allahabad
>>>
>>>
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Re: [algogeeks] Apti

2011-08-23 Thread Nikhil Gupta
The answer can be given by writing all the prime factors as:
N = 24 * 33 = 2^3 * 3*2 * 11

=> answer will be :
(3+1)*(2+1)*(1+1) = 24

This is the answer considering (a,b) and (b,a) different

If you consider them same the answer is 24/2 = 12.

Nikhil Gupta
IIT Roorkee

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Re: [algogeeks] Apti

2011-08-23 Thread Shravan Kumar
It would be sum of number of  factors of both the numbers.
24 -1,2,3,4,6,8,12,24
33-1,3,11,33


On Tue, Aug 23, 2011 at 10:54 PM, Aman Goyal  wrote:

> ans is 12, but instead of counting i am looking for some better solution.
>
>
> On Tue, Aug 23, 2011 at 10:48 PM, manish patel wrote:
>
>>
>> (24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
>>
>> On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal wrote:
>>
>>> Let a natural number N be such that N = a × b where a and b are the
>>> factors of N. How many such sets of (a, b) can be formed in which the
>>> selection of the two numbers a and b is distinctly different if N = 24 × 33?
>>>
>>> Please explain your solution also.
>>>
>>> --
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>>
>>
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Re: [algogeeks] Apti

2011-08-23 Thread Aman Goyal
ans is 12, but instead of counting i am looking for some better solution.

On Tue, Aug 23, 2011 at 10:48 PM, manish patel wrote:

>
> (24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
>
> On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal wrote:
>
>> Let a natural number N be such that N = a × b where a and b are the
>> factors of N. How many such sets of (a, b) can be formed in which the
>> selection of the two numbers a and b is distinctly different if N = 24 × 33?
>>
>> Please explain your solution also.
>>
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>
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Re: [algogeeks] Apti

2011-08-23 Thread manish patel
(24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)

On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal  wrote:

> Let a natural number N be such that N = a × b where a and b are the factors
> of N. How many such sets of (a, b) can be formed in which the selection of
> the two numbers a and b is distinctly different if N = 24 × 33?
>
> Please explain your solution also.
>
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Re: [algogeeks] Apti

2011-08-23 Thread priya ramesh
is the ans 16??

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[algogeeks] Apti

2011-08-23 Thread Aman Goyal
Let a natural number N be such that N = a × b where a and b are the factors
of N. How many such sets of (a, b) can be formed in which the selection of
the two numbers a and b is distinctly different if N = 24 × 33?

Please explain your solution also.

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Re: [algogeeks] apti!

2011-08-23 Thread Rahul
i also have the problem , any one, in the book , the answer is not
satisfiable
Rahul


On Tue, Aug 23, 2011 at 7:52 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

> Out of two thirds of the total number of basket -ball matches, a team has
> won 17 matches and lost 3 of them. What is the maximum number of matches
> that the team can lose and still win three -fourths of the   total number of
> matches, if it is true that no match can end in a tie? [1] 4 [2] 6 [3] 5 [4]
> 3
>
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[algogeeks] apti!

2011-08-23 Thread priya ramesh
Out of two thirds of the total number of basket -ball matches, a team has
won 17 matches and lost 3 of them. What is the maximum number of matches
that the team can lose and still win three -fourths of the   total number of
matches, if it is true that no match can end in a tie? [1] 4 [2] 6 [3] 5 [4]
3

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Re: [algogeeks] apti

2011-08-21 Thread prasanth n
@tushar:

thanks

On Sun, Aug 21, 2011 at 12:27 PM, Tushar Bindal wrote:

> if the cyclist would have left on time, then in those 20 minutes, he would
> have covered 4miles at a speed of 12miles/h
> so he would have been 1 mile before station whereas train would have been 5
> miles before as it is on its normal time, so no change in its position.
> then, when the cyclist covers that 1 mile, the train covers 5 miles so that
> both of them meet at the station.
> thus, speed of the train = 5*speed of cyclist = 60 miles/hour
>
>
> On Sun, Aug 21, 2011 at 12:19 PM, prasanth n  wrote:
>
>> @gupta:
>>
>> can you explain your answer?
>>
>>
>> On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta 
>> wrote:
>>
>>> 60mph
>>>
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Re: [algogeeks] apti

2011-08-20 Thread Tushar Bindal
if the cyclist would have left on time, then in those 20 minutes, he would
have covered 4miles at a speed of 12miles/h
so he would have been 1 mile before station whereas train would have been 5
miles before as it is on its normal time, so no change in its position.
then, when the cyclist covers that 1 mile, the train covers 5 miles so that
both of them meet at the station.
thus, speed of the train = 5*speed of cyclist = 60 miles/hour

On Sun, Aug 21, 2011 at 12:19 PM, prasanth n  wrote:

> @gupta:
>
> can you explain your answer?
>
>
> On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta wrote:
>
>> 60mph
>>
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Re: [algogeeks] apti

2011-08-20 Thread prasanth n
@gupta:

can you explain your answer?

On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta wrote:

> 60mph
>
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Re: [algogeeks] apti

2011-08-20 Thread D!leep Gupta
60mph

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[algogeeks] apti

2011-08-20 Thread prasanth n
A train and A Cyclist reaches a station every  day  at the same time.  One
 day the Cyclist starts 20 minutes late from his   house.On his way to
station   the train  crosses him at 5 miles before station.The speed of
cyclist is12mph. Find the speed of the train.
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Re: [algogeeks] apti! solve this!

2011-08-17 Thread aditya kumar
answer has to be sqrt(146) . 13 cant be the answer

On Wed, Aug 17, 2011 at 7:55 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

> the answer is given as 13... even i got root(146)
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Re: [algogeeks] apti! solve this!

2011-08-17 Thread priya ramesh
the answer is given as 13... even i got root(146)

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Re: [algogeeks] apti! solve this!

2011-08-17 Thread manish patel
he is srqt(11^2+5^2)~12.1kms away from A.
if he would hav travelled 4 kms in east then ans would hav been 13kms

On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

>  A moves 3 kms east from his starting point . He then travels 5 kms north.
> From that point he moves 8 kms to the east.How far is A from his starting
> point?
>
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Re: [algogeeks] apti! solve this!

2011-08-17 Thread priyanka singhal
11.716 km

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Re: [algogeeks] apti! solve this!

2011-08-17 Thread Ashish kumar Jain
sqrt(146)

On Wed, Aug 17, 2011 at 7:43 PM, priya ramesh <
love.for.programm...@gmail.com> wrote:

>  A moves 3 kms east from his starting point . He then travels 5 kms north.
> From that point he moves 8 kms to the east.How far is A from his starting
> point?
>
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[algogeeks] apti! solve this!

2011-08-17 Thread priya ramesh
 A moves 3 kms east from his starting point . He then travels 5 kms north.
>From that point he moves 8 kms to the east.How far is A from his starting
point?

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Re: [algogeeks] apti Q

2011-07-07 Thread Tushar Bindal
the clock has become faster by 48 seconds in 10800 minutes
i.e., 1 sec in 225 minutes

from 8am on sunday we have to go 225*5*60 minutes behind to get time when
clock showed the correct time.
i.e., 67500 minutes or 44 days 1260 minutes
44 days 21 hours
which means clock showed correct timing at 11amon the day 45 days before the
sunday on which it was 5 minutes ahead.

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[algogeeks] apti Q

2011-07-07 Thread Agyat
a clock gains uniformly and is 5 minute at 8.00 am on sunday.And on
next sunday it is 5 minute 48 second fast at 8.00 pm.Tell the time
when clock was showing correct time

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