Re: Newbie: MYSQL nested query question

2005-04-05 Thread SGreen 
Just turn your subquery into another join

SELECT C2.City, N.Distance
FROM Cities C
INNER JOIN Nbc N ON C.CityID = N.PrimaryCityID
INNER JOIN Cities C2 ON C2.cityID = N.CityID
WHERE C.City = 'Los Angeles'
AND N.Distance <20

Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine

Graham Anderson <[EMAIL PROTECTED]> wrote on 04/01/2005 04:49:31 PM:

> I upgraded my local mysql version to 4.1.10a and the below query 
> finally works :)
> 
> How can I now amend the query so it works on my remote server running 
> mysql 3.23.58 ? From one headache to another ;)
> 
> SELECT (
> 
> SELECT City
> FROM Cities
> WHERE CityID = N.CityID
> ), N.Distance
> FROM Cities C
> JOIN Nbc N ON C.CityID = N.PrimaryCityID
> WHERE C.City = 'Los Angeles'
> AND N.Distance <20
> 
> many many thanks to all those that replied :)
> 
> g
> 
> On Mar 31, 2005, at 11:49 PM, Philip M. Gollucci wrote:
> 
> > Graham Anderson wrote:
> >> What is the proper way to say this ?
> >> SELECT C.City, N.Distance
> >> FROM Cities C
> >> JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
> >> WHERE  N.CityId =
> >> (SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los Angeles')
> >> AND N.distance < 20
> >> I am trying to enter in a city and get all the nearby cites with 20 
> >> miles
> >> Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, 
> >> and Cities.city
> >> learning :)
> > Unless I missed something... Why did you make it so hard ?
> > SQL is meant to be easy :)
> >
> > SELECT c.city, n.distance
> > FROM Cities c, Nearbycities n
> > WHERE c.cityid = n.primarycityid
> > AND c.city = 'Los Angeles'
> > AND n.distance < 20
> >
> >
> >
> > -- 
> > MySQL General Mailing List
> > For list archives: http://lists.mysql.com/mysql
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> >
> 
> 
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Re: Newbie: MYSQL nested query question

2005-04-01 Thread Graham Anderson 
strangely, the query works intermittently :(
SELECT (
SELECT City
FROM Cities
WHERE CityId = N.CityId
), N.Distance
FROM Cities C
JOIN Nbc N ON C.CityId = N.PrimaryCityId
WHERE C.City = 'Los Angeles'
AND N.Distance <20
sometimes it works...other times it gives the mysql query error:
show keys from
tbl_properties.php: Missing parameter: table
huh ?
On Apr 1, 2005, at 2:21 PM, Graham Anderson wrote:
In the simple query...
the city field showed the result 'Los Angeles' in every row
the distance field showed incorrect  results  to :(
City|   Distance
Los Angeles 18
Los Angeles 5
Los Angeles 7
...
On Apr 1, 2005, at 1:59 PM, Peter Brawley wrote:
What was wrong with Graham's simpler query?
PB
-
Graham Anderson wrote:
I upgraded my local mysql version to 4.1.10a and the below query 
finally works :)

How can I now amend the query so it works on my remote server 
running mysql 3.23.58 ? From one headache to another ;)

SELECT (
SELECT City
FROM Cities
WHERE CityID = N.CityID
), N.Distance
FROM Cities C
JOIN Nbc N ON C.CityID = N.PrimaryCityID
WHERE C.City = 'Los Angeles'
AND N.Distance <20
many many thanks to all those that replied :)
g
On Mar 31, 2005, at 11:49 PM, Philip M. Gollucci wrote:
Graham Anderson wrote:
What is the proper way to say this ?
SELECT C.City, N.Distance
FROM Cities C
JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
WHERE  N.CityId =
(SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los 
Angeles')
AND N.distance < 20
I am trying to enter in a city and get all the nearby cites with 
20 miles
Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, 
and Cities.city
learning :)
Unless I missed something... Why did you make it so hard ?
SQL is meant to be easy :)
SELECT c.city, n.distance
FROM Cities c, Nearbycities n
WHERE c.cityid = n.primarycityid
AND c.city = 'Los Angeles'
AND n.distance < 20

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Re: Newbie: MYSQL nested query question

2005-04-01 Thread Graham Anderson 
In the simple query...
the city field showed the result 'Los Angeles' in every row
the distance field showed incorrect  results  to :(
City|   Distance
Los Angeles 18
Los Angeles 5
Los Angeles 7
...
On Apr 1, 2005, at 1:59 PM, Peter Brawley wrote:
What was wrong with Graham's simpler query?
PB
-
Graham Anderson wrote:
I upgraded my local mysql version to 4.1.10a and the below query 
finally works :)

How can I now amend the query so it works on my remote server running 
mysql 3.23.58 ? From one headache to another ;)

SELECT (
SELECT City
FROM Cities
WHERE CityID = N.CityID
), N.Distance
FROM Cities C
JOIN Nbc N ON C.CityID = N.PrimaryCityID
WHERE C.City = 'Los Angeles'
AND N.Distance <20
many many thanks to all those that replied :)
g
On Mar 31, 2005, at 11:49 PM, Philip M. Gollucci wrote:
Graham Anderson wrote:
What is the proper way to say this ?
SELECT C.City, N.Distance
FROM Cities C
JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
WHERE  N.CityId =
(SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los Angeles')
AND N.distance < 20
I am trying to enter in a city and get all the nearby cites with 20 
miles
Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, 
and Cities.city
learning :)
Unless I missed something... Why did you make it so hard ?
SQL is meant to be easy :)
SELECT c.city, n.distance
FROM Cities c, Nearbycities n
WHERE c.cityid = n.primarycityid
AND c.city = 'Los Angeles'
AND n.distance < 20

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Re: Newbie: MYSQL nested query question

2005-04-01 Thread Peter Brawley 
What was wrong with Graham's simpler query?
PB
-
Graham Anderson wrote:
I upgraded my local mysql version to 4.1.10a and the below query 
finally works :)

How can I now amend the query so it works on my remote server running 
mysql 3.23.58 ? From one headache to another ;)

SELECT (
SELECT City
FROM Cities
WHERE CityID = N.CityID
), N.Distance
FROM Cities C
JOIN Nbc N ON C.CityID = N.PrimaryCityID
WHERE C.City = 'Los Angeles'
AND N.Distance <20
many many thanks to all those that replied :)
g
On Mar 31, 2005, at 11:49 PM, Philip M. Gollucci wrote:
Graham Anderson wrote:
What is the proper way to say this ?
SELECT C.City, N.Distance
FROM Cities C
JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
WHERE  N.CityId =
(SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los Angeles')
AND N.distance < 20
I am trying to enter in a city and get all the nearby cites with 20 
miles
Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, 
and Cities.city
learning :)
Unless I missed something... Why did you make it so hard ?
SQL is meant to be easy :)
SELECT c.city, n.distance
FROM Cities c, Nearbycities n
WHERE c.cityid = n.primarycityid
AND c.city = 'Los Angeles'
AND n.distance < 20

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Re: Newbie: MYSQL nested query question

2005-04-01 Thread Graham Anderson 
I upgraded my local mysql version to 4.1.10a and the below query 
finally works :)

How can I now amend the query so it works on my remote server running 
mysql 3.23.58 ? From one headache to another ;)

SELECT (
SELECT City
FROM Cities
WHERE CityID = N.CityID
), N.Distance
FROM Cities C
JOIN Nbc N ON C.CityID = N.PrimaryCityID
WHERE C.City = 'Los Angeles'
AND N.Distance <20
many many thanks to all those that replied :)
g
On Mar 31, 2005, at 11:49 PM, Philip M. Gollucci wrote:
Graham Anderson wrote:
What is the proper way to say this ?
SELECT C.City, N.Distance
FROM Cities C
JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
WHERE  N.CityId =
(SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los Angeles')
AND N.distance < 20
I am trying to enter in a city and get all the nearby cites with 20 
miles
Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, 
and Cities.city
learning :)
Unless I missed something... Why did you make it so hard ?
SQL is meant to be easy :)
SELECT c.city, n.distance
FROM Cities c, Nearbycities n
WHERE c.cityid = n.primarycityid
AND c.city = 'Los Angeles'
AND n.distance < 20

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Re: Newbie: MYSQL nested query question

2005-03-31 Thread Philip M. Gollucci 
Graham Anderson wrote:
What is the proper way to say this ?
SELECT C.City, N.Distance
FROM Cities C
JOIN Nearbycities N ON C.CityId =ci N.PrimaryCityId
WHERE  N.CityId =
(SELECT Cities.CityId FROM Cities WHERE Cities.city = 'Los Angeles')
AND N.distance < 20
I am trying to enter in a city and get all the nearby cites with 20 miles
Somehow, I need to join NearbyCities.PrimaryCityId, Cities.CityId, and 
Cities.city

learning :)

Unless I missed something... Why did you make it so hard ?
SQL is meant to be easy :)
SELECT c.city, n.distance
FROM Cities c, Nearbycities n
WHERE c.cityid = n.primarycityid
AND c.city = 'Los Angeles'
AND n.distance < 20

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