There is my version of DP:
Define C(m,n) as the number of proper bracket expressions
B1,B2,B3,...,Bm+n with m left brackets '(' and n right brackets ')',
in which 'proper' means that for each i belonging to {1,2,...,m+n} the
number of left brackets '(' in B1,B2...Bi is larger than or equal to
the
What do you input into the algorithm corresponding to the specific
node? A pointer pointing to the node or just the key value of that
node used for query? These two situations are totally different in
which the former one can be handled in O(d) time complexity and the
other one will be O(2^d) compl
Actually, your code just considers the only non-decreasing subsequence
which starts from a[0] and is the most 'LEFT' one in this situation
rather than all the possible subsequences.
For example, we have such sequence as 2,3,999,, and k = 2.
In this situation, your code will give the subsequen
this number as Ci. Finally, we count up
C0, C1 ... Ck. Then we get the final answer C = C0 + C1 + ... + Ck.
On Aug 24, 5:43 am, Saikat Debnath wrote:
> Thank you Adam, but the thing is I don't only want the solution but
> also, how to go about such questions? How do you came to a sol
Just do a little changes on your given function, that may help you
understand it:
We denote the transformed function as heap_compare_new:
int heap_compare_new(priority_queue *q, int i, int count, int x)
{
if ((count >= k) || (i > q->n) return(k-count);
/* change */
if (q->q[i] < x) {
count++;
Write here again:
I find an easier non-recursive solution to compute the rectangle
number (represented as RN) of an h x w rectangle (which has a height
of h units and a width of w units):
Situation 1:
If (h and w are coprime) or (h = 1) or (w = 1)
then RN = h + w - 1.
Situation 2:
If h and w a
Write here again:
I find an easier non-recursive solution to compute the rectangle
number (represented as RN) of an h x w rectangle (which has a height
of h units and a width of w units):
Situation 1:
If (h and w are coprime) or (h = 1) or (w = 1)
then RN = h + w - 1.
Situation 2:
if h and w a
I find an easier non-recursive solution to compute the rectangle
number (represented as RN) of an h x w rectangle (which has a height
of h units and a width of w units):
Situation 1. if (h and w are coprime) or (h = 1) or (w = 1), then RN =
h + w - 1
Situation 2. if h and w are not relatively pri
What do you exactly mean? You want to represent a linear structure by
using a tree structure?
You can imagine a linked list as a tree with all its root and inner
nodes only having one descendent/child node.
On Aug 23, 10:50 am, Raj N wrote:
> What will be the representation. How do you define lef
