Well, when i compiled the code the output ie i is alway i=2,
http://ideone.com/AFljo
http://ideone.com/87waz
This expression is ambiguous, and compiler dependent.
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go it.
+1
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http://ideone.com/5uhz1
it seems that
-ve number is always converted to unsigned, but this time x=3 is greater
why?
On Sun, Jan 29, 2012 at 3:14 PM, Saurabh Yadav wrote:
> may be because when you compare unsigned number with signed number ,the
> signed will changed to unsigned type and when si
