In a sports contest there were m medals awarded on n successive days
(n > 1).
1. On the first day 1 medal and 1/7 of the remaining m - 1 medals
were
awarded.
2. On the second day 2 medals and 1/7 of the now remaining medals
was
awarded; and so on.
3. On the nth and last day, the
If [a1,a2,a3...,an,b1,b2...bn] is given input change this to
[a1,b1,a2,b2.an,bn]
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You have four numbers 1 , 1 , 9 ,9 .
Now using these four and operator + , - , * ,/ and parentheses(if
required) your have to get 10.
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Well the solution is pretty simple.
What you have to do is just do inoder traversal of tree in reverse
order.
Here goes my C++ code for that
int ith_order(Tree *root,int i)
{
static int c;
static int ans;
if(root)
{
ith_order(root->right,i);