If strings do not have same lengths, this simple greedy algorithm does not
work. E.g.
b
ba
bab
The best answer is bababb, instead of bbabab.
A correct way is to define a new string comparison operator, and concatenate
strings in that order:
bool comp(const string &a, const string &b)
{
retu
Why not try all possibilities? Not many numbers to enumerate.
2011/2/23 bittu
> How to find a number of 10 digits (non repeated digits) which is a
> perfect square? perfect square examples: 9 (3x3) 16 (4x4) 25(5x) etc.
> Ten digit number example 1,234,567,890
>
>
>
> Thanks & Regards
> Shashank
longest path is NP-hard
2010/1/11 Johan
> Ok, so I know that Dijkstra can be used to solve the single-source
> shortest path problem quite efficiently. I however need to find the
> single source longest path through a graph. Can Dijkstra be used for
> this if I transform the edge lengths so that
It is not a solution for minimize maximum distance either, since |x(i)-x(j)|
<= c does not hold for every pair of points, only for adjacent points.
2009/10/21 saltycookie
> Yes, you are quite right. If I am not mistaken, you give a good solution
> for finding the minimum maximum
Yes, you are quite right. If I am not mistaken, you give a good solution for
finding the minimum maximum distance.
But what about the original problem where we want to find the maximum
minimum distance? I am not clear about the connection between the two
problems.
Thanks.
2009/10/21 Dave
>
> 林
of numbers and that would depend on
> distribution of primes...
> So it occurs to me that there might not be a "closed form" winning
> strategy possible !
>
> Still thanks for the proof !
>
> cheers
>
> -
> nikhil
> Every single person has a slim shady lurki
Here is a proof. Unfortunately, the proof is not constructive.The
secret of winning is "1", which is a fator of every integer.
If the first player(player A) can win by removing a number between 2
to n, then our hypothesis holds. Or else, A can't win by removing any
number between 2 to n. We denot
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
I think the way google deals with spell error is quite complex.
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you may store several version of the
word in the database.
Here is one possible implementation:
For "world", we first add a spec
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
But if you just wanna find candidates for spell errors with one char
(miss, add or misspell one char), you
may store several version of the word in the database.
Here is one possible implementation:
For "world", we first add a special char, say '$' to the beginning of
the world, and get "$world
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