@jagan: that's true obj is a pointer to the data type for which size
need to be calculated.
On Feb 7, 10:38 am, jagannath prasad das wrote:
> @rajiv:i guess obj is a pointer here
>
>
>
>
>
>
>
> On Mon, Feb 7, 2011 at 10:51 AM, Rajiv Podar wrote:
> > Hi
> > Try following code
>
> > Suppo
@rajiv:i guess obj is a pointer here
On Mon, Feb 7, 2011 at 10:51 AM, Rajiv Podar wrote:
> Hi
> Try following code
>
> Suppose we need to find size of variable *"obj"*
> int size = (char*)(obj +1 ) - (char*)(obj);
>
> *
> *Thanks & Regards,
> Ricky
>
>
>
> On Mon, Feb 7, 2011 at 12:19 A
Hi
Try following code
Suppose we need to find size of variable *"obj"*
int size = (char*)(obj +1 ) - (char*)(obj);
*
*Thanks & Regards,
Ricky
On Mon, Feb 7, 2011 at 12:19 AM, albert theboss wrote:
> using this macro
>
> size(X) ((X*)0+1)
>
>
>
> if we give size(int) it ll return 4.
> size(d
using this macro
size(X) ((X*)0+1)
if we give size(int) it ll return 4.
size(double) gives 8.
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this gro
it has variable defined
On Sun, Feb 6, 2011 at 7:47 AM, Venki wrote:
> Hi Gajendra,
> See the following link
>
> http://geeksforgeeks.org/forum/topic/huwaei-interview-question-for-software-engineerdeveloper-2-5-years-about-cpuzzles#post-18725
>
>
> On Feb 5, 7:28 pm, Gajendra Dadheech wrote:
>>
Hi Gajendra,
See the following link
http://geeksforgeeks.org/forum/topic/huwaei-interview-question-for-software-engineerdeveloper-2-5-years-about-cpuzzles#post-18725
On Feb 5, 7:28 pm, Gajendra Dadheech wrote:
> Calculate size of a data type without using sizeof and without declaring any
> vari
@Dave nice algorithm
On Fri, Dec 24, 2010 at 6:59 PM, Dave wrote:
> @Monty: Use an alternating across and down algorithm:
>
> Set the current row = the first row
> While current row is not the last row
>Look across the current row for the first false
>Look down the column containing that
@Monty: Use an alternating across and down algorithm:
Set the current row = the first row
While current row is not the last row
Look across the current row for the first false
Look down the column containing that first false for a true
If no such row is found, break. // current row is