On Jul 11, 9:58 am, amit wrote:
> Give a algorithm to remove extra pair of parenthesis
> Remove unnecessary from an expression :
> 1) (((a))) => a
> 2) (a+b) => a+b
> 3) (a+b)*c => (a+b)*c
> 4)(((a+b)*(c+d))+e) => (a+b)*(c+d)+e
We can build an abstract syntax tree with a simple parser and then
wa
Assuming we do not want to remove
brackets from cases like (a+b)+c,
(because strictly speaking, the brackets
here are not required), one algorithm to
remove brackets for given above cases can be:
1) Scan through the string.
2) Increment a counter when '(' is
encountered and decrement it on ')'
3)
