On Monday 09 August 2010 13:22:20 Avik Mitra wrote:
> ANSI standard specifies that during right shift of a negative number
> the shift MUST be a logical shift with sign extension. So,
> when right shifted will logically with sign extention it
> gives (in hex).
> So the answ
#include
int main()
{
printf("%x\n", (unsigned)-1>>1);
return 0;
}
this will give you the expected result.
Cheers,
venki
VENKATARAMAN.GB
"If Its Upto Be, It Is Upto Me"
On Mon, Aug 9, 2010 at 3:53 PM, Avik Mitra wrote:
>
> Note that (in hex) is 2's compleme
Note that (in hex) is 2's complement representation of -1.
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ANSI standard specifies that during right shift of a negative number
the shift MUST be a logical shift with sign extension. So,
when right shifted will logically with sign extention it
gives (in hex).
So the answer is [A].
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In both C and C++, the result of a right shift of a signed value is
implementation specific. The vacated bits can be filled either with
zeros or with copies of the sign bit. Portable code must not depend on
the implementation, but must work with either implementation choice.
Thus, the result could
