@Wujin: Okay. b is but an integer, yet it is being printed as a long
long. Since there are no implicit type conversions in procedure calls
such as the printf statement, b is taken as a long long, not of an
int. So b and the next 32-bits are printed. The format that these are
printed in is a figment
@Wujin: Okay. But b is an integer and it is being printed as a long
long. Since there are no implicit type conversions in procedure calls
such as the printf statement, b is taken as a long long, not of an
int. So b and the next 32-bits are printed.
Dave
On Sep 19, 8:18 pm, wujin chen wrote:
> @D
@Dave printf("a=%x, b=%llx",a,b,c); i think c will be ignored~~ , and the
output is a=9,b=10
2011/9/19 Dave
> @Wujin: What do you expect the output to be? How does it differ from
> what you actually get?
>
> Dave
>
> On Sep 18, 8:47 am, wujin chen wrote:
> > usigned long long x = 0x12345678;
@Wujin: What do you expect the output to be? How does it differ from
what you actually get?
Dave
On Sep 18, 8:47 am, wujin chen wrote:
> usigned long long x = 0x12345678;
> int a = 0x09;
> int b = 0x10;
> printf("a=%x, b=%llx",a,b,c);
>
> the result is: a=9,b=123456780010
>
> i wonder why~~
