In case you are wondering about the part of the proof for k%3<>0, it
goes like this, the given number can be written as 1 + 1000 + 100
+ 10 +..and so on
now if for a given k, if we choose the string of k 1s and try to find
the modulus with each of the terms in the above expression,
for
well...its simple as given in the article..
note that the numbers are all decimal numbers (not binary..in case
misled by just 0 and 1 in the number) therefore
if you have have k copies of 001 and k%3 == 0, then the sum of the
digits is divisible by 3 hence the number is divisible by 3 - The
Standa
