Probably you can make separate *multimap *for each of the attribute and
while retrieval, taking intersection of sets associated with each of the
attribute.
The three tables could be:
multimap contentsContainingTopic;
multimap contentsContainingLocation;
multimap contentsContainingLocale;
For any
Hi Abhay,
Thanks for your solution, seems good as it is covering all the 3
attributes. Nesting of Hashmap to 3 layers is little clumsy. For Example if
we increase from 3 to 4 attributes we can see the complexity of handling
the things. I would like to know, do we have any other solutions.
I think there is a correction for the time complexities:
For the case when all three parameters are given, the time complexity will
be *O(log(numTopics) + log(numLocations) + log(numLocale)). *Reason being
it is like search on three different trees - after the key *topicValue* has
been searched, o
Use a B-Tree implemented using nested map<> as:
*map > > table;*
Now for each level the complexity will be log(numOfElementsAtThatLevel).
e.g.* if you have all three parameters, the complexity of retrieval will be
O(log(numTopics)*log(numLocations)*log(numLocale)).*
For the missing parameters it
Hi,
I have a question and i would like to know the data structure to be
used for this.
You have 3 attribute
1. Topic
2. Location
3. Locale
User can give any of the three or all the them to retrieve the content. For
example.
1. Politics, Hyderabad, English
In this case we nee
Thanks Bharat and Ashish;
Sorry my knowledge is so basic, I'm not yet with you.
The example they gave was:
% film.txt
...
Tin men (1987) / DeBoy, David/Blumenfeld, Alan/ --- /Geppi,
Cindy/Hershey, Barbara
Titanic (1997) /Mazin, Stan/...DiCaprio, Leonardo/.../Winslet, Kate/...
To Die For (1995
dual key hashmap
Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652
On Sun, Apr 8, 2012 at 2:37 PM, bharat b wrote:
> Maintain an vector of structure "Film_actors" for "List of actors"
> Maintain an vector of structure "Actor_films" for "List of Film
Maintain an vector of structure "Film_actors" for "List of actors"
Maintain an vector of structure "Actor_films" for "List of Films"
I'll explain this with the help of an example .
Films:
1.Hai
2.Bye
Actors:
A,B,C,D acted in Film Hai.
A,D,F,G acted in Film Bye.
struct Film_actors {
String Film_na
Thanks all of you. I'm new to algorithms and data structure and I'm new in
this forum.
I have an assignment but not sure yet:
A. Describe a data structure which can effectively answer the following
questions:
1. A list of actors (f) : Print a list of actors who took part in film* f *
.
2. A list
