On May 8, 2013, at 23:31 , "Alex Leach" wrote:
> That error means the type_id of uuid is not in the bp registry.
>
> I think you can fix this by deriving uuid_to_python from to_python_converter,
> as demonstrated in the pytype_function example[1]. This will add the
> get_pytype function call,
On May 8, 2013, at 23:58 , Jim Bosch wrote:
> On 05/08/2013 05:48 PM, Jim Bosch wrote:
>> On 05/08/2013 04:33 PM, Wichert Akkerman wrote:
>>> I am trying to expose a class with a boost::uuids::uuid member to Python.
>>> The class is pretty simple:
>>>
>>> class Article {
>>> public:
>>> b
On 05/08/2013 05:48 PM, Jim Bosch wrote:
On 05/08/2013 04:33 PM, Wichert Akkerman wrote:
I am trying to expose a class with a boost::uuids::uuid member to Python. The
class is pretty simple:
class Article {
public:
boost::uuids::uuid uuid;
};
which is exposed like this:
article
On 05/08/2013 04:33 PM, Wichert Akkerman wrote:
I am trying to expose a class with a boost::uuids::uuid member to Python. The
class is pretty simple:
class Article {
public:
boost::uuids::uuid uuid;
};
which is exposed like this:
article
.def(init((arg("uuid")))
.def_r
That error means the type_id of uuid is not in the bp registry.I think you can fix this by deriving uuid_to_python from to_python_converter, as demonstrated in the pytype_function example[1]. This will add the get_pytype function call, and on initialisation, should hopefully add what's missing: a
I am trying to expose a class with a boost::uuids::uuid member to Python. The
class is pretty simple:
class Article {
public:
boost::uuids::uuid uuid;
};
which is exposed like this:
article
.def(init((arg("uuid")))
.def_readwrite("uuid", &Article::uuid);
and I have basic c
Hi -
Using Boost 1.53.0, the following code fails to compile with g++, when
c++11 is enabled:
#include
#include
struct A{}; struct B{};
typedef boost::variant my_variant;
void foo(boost::python::object o) {
my_variant v = boost::python::extract(o);
}
The error is:
/home/bcatanzaro/boost_
