close 491654
thanks dude
Hi Bastian,
The paragraph talks about how signed types need to map to unsigned
types, and then goes on to talk about _Bool and unsigned types. I
completely misread it as meaning that _Bool had to map to an unsigned
type. You're entirely correct here, sorry for the tro
Processing commands for [EMAIL PROTECTED]:
> close 491654
Bug#491654: gcc-4.3: _Bool isn't wide enough.
'close' is deprecated; see http://www.debian.org/Bugs/Developer#closing.
Bug closed, send any further explanations to Nick Lewycky <[EMAIL PROTECTED]>
> tha
On Sun, Jul 20, 2008 at 11:32:28PM -0700, Nick Lewycky wrote:
> In C99, _Bool is required to map to one of the unsigned types (6.2.5/6).
Please quote the standard. I read something different there.
> However, GCC rejects the following (admittedly unethical) snippet:
> struct S7 {
> _Bool D
Package: gcc-4.3
Version: 4.3.1-6
Severity: normal
In C99, _Bool is required to map to one of the unsigned types (6.2.5/6). On
i586, this is 'unsigned char', by ABI. That means that you get eight bits to
the _Bool.
However, GCC rejects the following (admittedly unethical) snippet:
struct S7 {
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