Happy to assist—a few notes/questions up-front:
- It's much easier to troubleshoot if you provide the full stack-trace,
as is. It helps answer questions like
- Which URL were you requesting that ultimately gave you this 404?
- Which URL patterns were "tried" or were regex-compar
I posted the same question on stackoverflow if anyone wants to answer it
there.
I am trying to create a builtin User object that has `is_active = False`
but I am getting this error:
null value in column "is_active" violates not-null constraint
Traceback:
File "/Library/Python/2.7/site-
I am creating a custom data migration to automatically create
GenericRelation entries in the database, based on existing entries across
two different models.
*Example models.py:*
...
class Place
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIn
I am trying to have django send emails but I am getting this error:
Traceback (most recent call last):
File "", line 1, in
File
"/Library/Python/2.7/site-packages/django/core/mail/__init__.py", line 62,
in send_mail
return mail.send()
File "/Library/Python/2.7/site
There is bounty on this stackoverflow question is anyone is interested
On Thursday, January 29, 2015 at 12:35:22 AM UTC-8, bradford li wrote:
>
> I posted a question on stackoverflow regarding my issue:
>
>
> http://stackoverflow.com/questions/28205560/upload-to-value-changes-photo
I posted a question on stackoverflow regarding my issue:
http://stackoverflow.com/questions/28205560/upload-to-value-changes-photo-name-attribute
Basically upload_to value will change my ImageField.name to the upload_to
value
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You received this message because you are subscribed to the Googl
I am trying to put thumbnail pictures of my photos within my admin page. I
am currently running into the issue where the thumbnail isn't displayed,
when I click on thumbnail I am redirected to the homepage of my project
with this as the URL:
http://127.0.0.1:8000/media/tumblr_ngotb4IY8v1sfi
I posted a question on stackoverflow regarding creating forms and
displaying the content. Right now I am only displaying the object name and
location. I am aiming to have it's content and widget displayed but being
new to Django I am having trouble =/ I feel the problem resides in beatle
field
I am trying to display the album titles related to my image in my admin
interface
class Album(models.Model):
title = models.CharField(max_length = 60)
def __unicode__(self):
return self.title
class Tag(models.Model):
tag = models.CharField(max_length = 50)
def __unicode__(self):
return self.ta
I want to create me admin like this: http://lightbird.net/dbe/_static/p1.png
What I have right now is:
def get_upload_file_name(instance, filename):
new_file_path_and_name = os.path.join(MEDIA_ROOT,'img/albums')
return new_file_path_and_name
class Album(models.Model):
title = models.CharField(ma
I want to do so without using an app because I feel that way I can really
learn Django. Currently this is what I have in my models.py
from django.db import models
from django.contrib import admin
#from PIL import Images as PImage
import os
from PersonalWebsite.settings import MEDIA_ROOT
#def get
I want to know how to display images separated by albums onto a page in
Django. So far, I've learned how to do so with the line
in my html file.
What I want to do is have a few album thumbnails out and upon click, all
the images from the album should be displayed. I believe I would do this
I'm pretty new to Django and I thought, what better way to learn than to
create your own website?!
I posted a question on Stackoverflow.
http://stackoverflow.com/questions/23534170/album-app-process-in-django
I want to create a Gallery App that would display a list of albums. These
albums woul
it's actually going to be thousands of sql queries for each user.
would doing it all in one object lock out all of the users for the
entire time the "magic" is being done (until it is updated)?
[EMAIL PROTECTED] wrote:
> Do you really need to perform hundreds of SQL queries? Wouldn't it be
> a l
It seems like I'm constantly using custom SQL statements, because the
ORM won't offer what's necessary to achieve the desired data
query/manipulation.
Right now I need to wrap up the following in a transaction that will be
called a few hundred times in a for loop.
delete from table ...
create te
Thanks, Malcolm -- as always :)
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I have a Model Foo, with a FK to user.
if i do f = Foo.objects.get(id=1) and all i need from that is f.title
and j.user.username in my template... is it returning more info than
needed with User. I mean, is it getting the entire user object for
each returned record?
If it is returning the enti
I need a model called settings that has some application settings the
user can edit in the admin. How should I set this model up so that one
and only one settings record always exists for the lifetime of the
application.
Also, please let me know if this approach is incorrect.
--~--~-~-
I'm trying to match emails in my urls.py by doing the following (which
was taken from core.validators:
(?P[A-Z0-9._%-][+A-Z0-9._%-]*@(?:[A-Z0-9-]+\.)+[A-Z]{2,4})
I have a few questions, though.
1. If the url pattern is too complex, will it slow anything down?
2. I'm assuming this matches the u
I have a blog with categories. Users who read the blog are allowed to
add up to five unique posts to their favorites for each category.
So
Favorites
- CategoryID
- PostID
- UserID
How should I limit the number of favorites per user (per category),
while enforcing favorite post uniqueness for e
I hope this makes sense:
I have two models: Foo and Bar. Bar contains a FK to Foo.
In the admin, when the admin looks at one of the Foo records, I want
them to be able to clear all Bar records that contain a FK to the Foo
record that's being used. How can I add a button to the Foo admin view
In my admin I am trying to create a new object, A. A has a FK to B,
which has a FK to Category, as shown: A -> B-> Category. The problem
is that when I create a new A object in my admin, it only shows a drop
down for B, and there you can have multiple B titles, but just not for
the same Categor
A question came up in #django and I was wondering what the best
solution may be: how to highlight search results.
Here are some possibilities:
1. Add in around the returned results
for the searched words in the view.
2. Template filter
3. Template tags
Please expand on any ideas.
Thanks
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