Re: How can I get this result?

Hi, consider two objects, ls_dic=[{'key1':a , 'key2': b},{'key1':c , 'key2': d}] num=sum([len(x.values()) for x in ls_dic]) print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[:-num] print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[num:] This is will help a lot

Re: How can I get this result?

sorry. assuming: l = [{'key1':'a' , 'key2': 'b'},{'key1':'c' , 'key2': 'd'}] for e in l: for k, v in e.iteritems(): print v, print On 2/15/15, Shai Efrati wrote: > assuming: > l = [{'key1':a , 'key2': b},{'key1':c , 'key2': d}] > > for e in l: > for k, v in iteritems(e): >

Re: How can I get this result?

assuming: l = [{'key1':a , 'key2': b},{'key1':c , 'key2': d}] for e in l: for k, v in iteritems(e): print v, print On 2/15/15, aronivi...@gmail.com wrote: > [{'key1':a , 'key2': b},{'key1':c , 'key2': d}] > a,b > c,d > > -- > You received this message because you are subscribed

How can I get this result?

[{'key1':a , 'key2': b},{'key1':c , 'key2': d}] a,b c,d -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to thi