Thank you, Caveat [emptor?].
The code you proposed worked very, very well.
In fact, I timed it against two versions of the C program and the result
was quite good.
In C, reading from the standard input and writing to the standard output
took a trifle beyond half a second (0.6?? real time).
Meanwhi
Something is horribly wrong, or you're running on a 286 :-)
I just tested here, and the program runs on a 51 MB test file in about 5
seconds.
Some reasonably well commented code for you...
Public Sub Main()
Dim inFile, outFile As File
Dim buff As New Byte[1024]
Dim idx, remBytes, readS
Le 15/07/2017 à 20:49, Tony Morehen a écrit :
Did you try Benoit's suggestion:
Public Sub Main()
Dim sIn as String
Dim sOut as String
sIn = File.Load("/home/fernando/temp/deah001.dhn")
sOut = Add11(sIn)
File.Save("/home/fernando/temp/deah001.11Added.dhn", sOut)
End
Public Sub
Did you try Benoit's suggestion:
Public Sub Main()
Dim sIn as String
Dim sOut as String
sIn = File.Load("/home/fernando/temp/deah001.dhn")
sOut = Add11(sIn)
File.Save("/home/fernando/temp/deah001.11Added.dhn", sOut)
End
Public Sub Add11(InputString as String) as String
Dim bArray
Well, after 5 hours the most efficient version is still running. Only 1/5
of the file has been processed. The less efficient version has only
processed 1 MB, or 1/ 42 of the file.
So I decided to write a C program to do the same task. Since I have not
been using C in the last 20 years, I did not t
Le 15/07/2017 à 16:08, Fernando Cabral a écrit :
Hi
I've found a file whose text has been obfuscated by subtracting 11 from
every byte. Now I want to bring it back to regular text. To do this I have
to add 11 to each byte read from that file. Now, I have tried several ways
to do it, and they all
Hi
I've found a file whose text has been obfuscated by subtracting 11 from
every byte. Now I want to bring it back to regular text. To do this I have
to add 11 to each byte read from that file. Now, I have tried several ways
to do it, and they all seemed every inefficient to me. Two examples follo
